/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 83 A controller on an electronic ar... [FREE SOLUTION] | 91Ó°ÊÓ

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A controller on an electronic arcade game consists of a variable resistor connected across the plates of a \(0.220 \mu \mathrm{F}\) capacitor. The capacitor is charged to \(5.00 \mathrm{~V}\), then discharged through the resistor. The time for the potential difference across the plates to decrease to \(0.800 \mathrm{~V}\) is measured by a clock inside the game. If the range of discharge times that can be handled effectively is from \(10.0 \mu \mathrm{s}\) to \(6.00 \mathrm{~ms}\), what should be the (a) lower value and (b) higher value of the resistance range of the resistor?

Short Answer

Expert verified
The resistance should range from approximately 123 Ω to 73.8 kΩ.

Step by step solution

01

Understanding Time Constant Formula

The discharge of a capacitor through a resistor is described by the equation \( V(t) = V_0 e^{-t/RC} \), where \( V(t) \) is the voltage at time \( t \), \( V_0 \) is the initial voltage, \( R \) is the resistance, \( C \) is the capacitance, and \( t \) is the time elapsed. We need the voltage to decrease from \( 5.00 \, \text{V} \) to \( 0.800 \, \text{V} \).
02

Rearranging the Formula

First, isolate \( R \) in the decay formula: \[ e^{-t/RC} = \frac{0.800}{5.00} \]. Taking the natural logarithm of both sides gives \[ -\frac{t}{RC} = \ln \left( \frac{0.800}{5.00} \right) \]. Rearranging for \( R \), we have \[ R = -\frac{t}{C \ln (0.800/5.00)} \].
03

Calculating Resistance for Shortest Time

Substitute the smallest time of discharge \( t = 10.0 \mu\text{s} = 10.0 \times 10^{-6} \text{s} \) and \( C = 0.220 \mu\text{F} = 0.220 \times 10^{-6} \text{F} \) into the equation. Calculate \( R_{\text{min}} \): \[ R_{\text{min}} = -\frac{10.0 \times 10^{-6}}{0.220 \times 10^{-6} \times \ln (0.160)} \]. Evaluating this gives \( R_{\text{min}} \approx 123 \Omega \).
04

Calculating Resistance for Longest Time

Substitute the longest time of discharge \( t = 6.00 \, \text{ms} = 6.00 \times 10^{-3} \text{s} \) into the resistance formula. Calculate \( R_{\text{max}} \): \[ R_{\text{max}} = -\frac{6.00 \times 10^{-3}}{0.220 \times 10^{-6} \times \ln (0.160)} \]. Evaluating this gives \( R_{\text{max}} \approx 73.8 \text{k}\Omega \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Variable Resistor
A variable resistor, often termed as a potentiometer, is an electronic component that allows the resistance value to change, giving us control over the current flowing through a circuit. This adjustability makes it essential in various applications, such as volume control in radios, speed control in motors, and in this context, controlling the discharge rate of a capacitor within an arcade game.

When connected with a capacitor, the resistive element's value can determine how quickly or slowly the capacitor discharges its stored electrical energy. By varying the resistance, the user can influence how long it takes for the capacitor to dump its charge, which is the characteristic focused on in the exercise.
  • As resistance increases, the time for discharge also increases, leading to slower decay of voltage.
  • Conversely, as resistance decreases, the discharge happens faster, decreasing the voltage more swiftly.
Understanding how a variable resistor functions in such a setup is crucial for managing energy dynamics in circuits effectively.
Time Constant
The time constant, denoted by the symbol \( \tau \), is a measure in an RC circuit of how quickly a capacitor charges or discharges. It is mathematically defined as \( \tau = RC \), where \( R \) is the resistance in ohms and \( C \) is the capacitance in farads.

This parameter is fundamental because it determines how fast or slow the exponential process of charging or discharging will be. A larger time constant means slower discharge, while a smaller time constant signifies a quick depletion.

In the exercise, you encountered various discharge times, each influenced by different resistor values.
  • For a short discharge time, you require a smaller \( R \), resulting in a smaller \( \tau \).
  • For a longer discharge time, a larger \( R \) is needed, resulting in a larger \( \tau \).
Thus, the time constant is a critical factor in designing and analyzing circuits where timing is vital, such as in timing and control applications.
Exponential Decay
Exponential decay describes the process by which a quantity decreases at a rate proportional to its current value. In an electrical circuit with a discharging capacitor, the voltage drops exponentially over time.

The mathematical representation is given by the formula \( V(t) = V_0 e^{-t/RC} \), which means the voltage at any time \( t \) is the initial voltage \( V_0 \) times the exponential decay factor \( e^{-t/RC} \). This property of exponential decay is what allows the prediction of voltage over time with great accuracy.

  • The decay occurs rapidly at first, then slows down.
  • It never truly reaches zero, theoretically, but will approach it infinitely.
Understanding exponential decay is vital for designing systems that rely on precise voltage levels at specific times, such as in arcade game controllers or other timed electronic circuits.
Resistance Range
Resistance range refers to the span of resistance values a variable resistor can adjust between. In the exercise, determining the appropriate resistance range is crucial to achieving the desired capacitor discharge times.

For the given exercise, the resistance range must accommodate both the shortest and longest discharge times permissible. This involves calculating both the minimum and maximum resistance values required to meet the range of discharge times: from the fastest (smallest resistance) to the slowest (largest resistance).

  • The lower value, \( R_{\text{min}} \), corresponds to the shortest allowable discharge time.
  • The higher value, \( R_{\text{max}} \), corresponds to the longest allowable discharge time.
This allows flexibility for the system to operate under various conditions. By determining this range accurately, you ensure that the device functions correctly within the specified parameters, crucial for maintaining game integrity and user-control precision.

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Most popular questions from this chapter

A solar cell generates a potential difference of \(0.10 \mathrm{~V}\) when a \(500 \Omega\) resistor is connected across it, and a potential difference of \(0.15 \mathrm{~V}\) when a \(1000 \Omega\) resistor is substituted. What are the (a) internal resistance and (b) emf of the solar cell? (c) The area of the cell is \(5.0 \mathrm{~cm}^{2}\), and the rate per unit area at which it receives energy from light is \(2.0 \mathrm{~mW} / \mathrm{cm}^{2} .\) What is the efficiency of the cell for converting light energy to thermal energy in the 1000 \(\Omega\) external resistor?

\- When resistors 1 and 2 are connected in series, the equivalent resistance is \(16.0 \Omega\). When they are connected in parallel, the equivalent resistance is \(3.0 \Omega\). What are (a) the smaller resistance and (b) the larger resistance of these two resistors?

Thermal energy is to be generated in a \(0.10 \Omega\) resistor at the rate of \(10 \mathrm{~W}\) by connecting the resistor to a battery whose emf is \(1.5 \mathrm{~V} .\) (a) What potential difference must exist across the resistor? (b) What must be the internal resistance of the battery?

A \(3.00 \mathrm{M} \Omega\) resistor and a \(1.00 \mu \mathrm{F}\) capacitor are connected in series with an ideal battery of emf \(\mathscr{E}=4.00 \mathrm{~V} .\) At \(1.00 \mathrm{~s}\) after the connection is made, what is the rate at which (a) the charge of the capacitor is increasing, (b) energy is being stored in the capacitor, (c) thermal energy is appearing in the resistor, and (d) energy is being delivered by the battery?

The current in a single-loop circuit with one resistance \(R\) is \(5.0 \mathrm{~A}\). When an additional resistance of \(2.0 \Omega\) is inserted in series with \(R\), the current drops to \(4.0 \mathrm{~A}\). What is \(R ?\)

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