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A standard flashlight battery can deliver about \(2.0 \mathrm{~W} \cdot \mathrm{h}\) of energy before it runs down. (a) If a battery costs US\$0.80, what is the cost of operating a \(100 \mathrm{~W}\) lamp for \(8.0 \mathrm{~h}\) using batteries? (b) What is the cost if energy is provided at the rate of US\$0.06 per kilowatthour?

Short Answer

Expert verified
(a) US$320 (b) US$0.048

Step by step solution

01

Calculate Total Energy Requirement

To find the total energy required to operate a 100 W lamp for 8.0 hours, multiply the power by the time: \( 100 \text{ W} \times 8.0 \text{ h} = 800 \text{ Wh} \).
02

Calculate Number of Batteries Needed

Each battery provides \( 2.0 \text{ Wh} \) of energy. To find the number of batteries required, divide the total energy by the energy per battery: \( \frac{800 \text{ Wh}}{2.0 \text{ Wh}} = 400 \text{ batteries} \).
03

Calculate Cost of Batteries

Each battery costs US\(0.80. Multiply the number of batteries by the cost per battery: \( 400 \times 0.80 = \text{US\\)}320 \).
04

Convert Total Energy to Kilowatt-hours

Convert 800 Wh to kWh: \( \frac{800 \text{ Wh}}{1000} = 0.8 \text{ kWh} \).
05

Calculate Cost with Utility Rate

Multiply the energy used (0.8 kWh) by the cost per kWh (US\(0.06): \( 0.8 \text{ kWh} \times 0.06 = \text{US\\)}0.048 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Battery Energy
Battery energy is a key concept when understanding how devices like flashlights, or in this case, a 100 W lamp can operate over time using stored energy. Each battery has a certain energy capacity, measured in watt-hours (Wh). In our example, a standard flashlight battery provides 2.0 Wh of energy. This means that the battery can deliver one watt of power for two hours or two watts of power for one hour before it is fully discharged. Understanding this concept is crucial because it helps us estimate how many batteries we would need for a certain amount of energy requirement. To paint a clear picture, if you want to power a device that needs 100 watts for 8 hours, you'll need a total of 800 watt-hours (100 W times 8 hours). Knowing the energy capacity of each battery allows you to figure out how many batteries are required to meet this energy need. This forms the basis of calculating costs when using batteries for power.
Power Consumption
Power consumption refers to the amount of energy a device uses over a certain period. It is measured in watts (W). If we know a device's power consumption, we can calculate the total energy it will use over time. In this scenario, the lamp uses 100 W of power. To find out how much energy it consumes, multiply the power by the number of hours it is used. For example, using a 100 W bulb for 8 hours consumes 800 Wh of energy. Understanding this helps analyze how many batteries or what kind of utility rate is needed to cover this power demand. Furthermore, knowing the power consumption can help you estimate costs beforehand, whether you are using batteries or paying for electricity from a utility provider.
Kilowatthour Cost
The kilowatthour (kWh) is a unit of energy that equates to one kilowatt (1,000 watts) of power used for one hour. It is a common unit used by utility companies to measure energy consumption and calculate billing costs.To determine the cost of energy consumption using electric utilities, you typically multiply the energy usage in kWh by the cost per kWh. In our exercise, the utility charges US$0.06 per kWh.So, if you use 0.8 kWh (as calculated earlier by converting 800 Wh to 0.8 kWh), you simply multiply this by the cost per kWh: \[ 0.8 \text{ kWh} \times 0.06 \text{ USD} = 0.048 \text{ USD} \]This provides an economical view of powering the lamp for 8 hours using grid electricity rather than batteries. This comparison highlights the importance of understanding kilowatthour costs for efficient energy budgeting.

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Most popular questions from this chapter

A \(120 \mathrm{~V}\) power line is protected by a 15 A fuse. What is the maximum number of \(500 \mathrm{~W}\) lamps that can be simultaneously operated in parallel on this line without "blowing" the fuse because of an excess of current?

A \(1.0 \mu \mathrm{F}\) capacitor with an initial stored energy of \(0.50 \mathrm{~J}\) is discharged through a \(1.0 \mathrm{M} \Omega\) resistor. (a) What is the initial charge on the capacitor? (b) What is the current through the resistor when the discharge starts? Find an expression that gives, as a function of time \(t,(\mathrm{c})\) the potential difference \(V_{C}\) across the capacitor, (d) the potential difference \(V_{R}\) across the resistor, and (e) the rate at which thermal energy is produced in the resistor.

When the lights of a car are switched on, an ammeter in series with them reads \(10.0 \mathrm{~A}\) and a voltmeter connected across them reads \(12.0 \mathrm{~V}\) (Fig. 27-60). When the electric starting motor is turned on, the ammeter reading drops to \(8.00 \mathrm{~A}\) and the lights \(\operatorname{dim}\) somewhat. If the internal resistance of the battery is \(0.0500 \Omega\) and that of the ammeter is negligible, what are (a) the emf of the battery and (b) the current through the starting motor when the lights are on?

(a) In electron-volts, how much work does an ideal battery with a \(12.0 \mathrm{~V}\) emf do on an electron that passes through the battery from the positive to the negative terminal? (b) If \(3.40 \times 10^{18}\) electrons pass through each second, what is the power of the battery in watts?

A total resistance of \(3.00 \Omega\) is to be produced by connecting an unknown resistance to a \(12.0 \Omega\) resistance. (a) What must be the value of the unknown resistance, and (b) should it be connected in series or in parallel?

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