/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 Thermal energy is produced in a ... [FREE SOLUTION] | 91Ó°ÊÓ

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Thermal energy is produced in a resistor at a rate of \(100 \mathrm{~W}\) when the current is \(3.00 \mathrm{~A}\). What is the resistance?

Short Answer

Expert verified
The resistance is approximately 11.11 Ω.

Step by step solution

01

Understanding the Formula

We need to use the formula for electric power in a resistor, which is given by: \[ P = I^2R \] where \( P \) is the power, \( I \) is the current, and \( R \) is the resistance. We need to find \( R \).
02

Rearranging the Formula to Find Resistance

To find the resistance, rearrange the formula: \[ R = \frac{P}{I^2} \]. This formula allows us to calculate the resistance based on the given power and current.
03

Substituting the Known Values

Substitute the given values (\( P = 100 \, \text{W} \) and \( I = 3.00 \, \text{A} \)) into the equation: \[ R = \frac{100}{3.00^2} \].
04

Performing the Calculation

Calculate \( 3.00^2 \), which is \( 9.00 \), and then divide 100 by 9.00 to find \( R \). Thus, \[ R = \frac{100}{9.00} \approx 11.11 \, \Omega \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Power
Electric power is the rate at which electrical energy is converted into another form such as heat, light, or mechanical energy. In this context, electric power is dissipated as thermal energy in a resistor. The electric power (P) consumed by a resistor can be calculated using various formulas, with one common formula being: \[ P = I^2 R \] Here, \( I \) represents the current flowing through the resistor, and \( R \) stands for resistance. This formula is useful when you know both the current and the resistance, allowing you to calculate the power directly. Electric power is typically measured in watts (W), which represent joules per second (1 \, ext{W} = 1 \, ext{J/s}), and is a convenient way to understand how much energy is being used by the electrical device or resistor in a short amount of time.
It gives insights into the energy efficiency of the device, which helps in designing circuits and managing energy consumption effectively.
Ohm's Law
Ohm's Law is foundational in the field of electronics and is crucial for understanding how electric circuits work. This law establishes a direct relationship between the voltage (V), current (I), and resistance (R) in a circuit. The formula is expressed as: \[ V = IR \] This indicates that the voltage across a resistor is the product of the current flowing through it and its resistance. In practical terms, it means you can easily determine one of these variables if you know the other two.
If you need to determine the resistance in a system using Ohm's Law, simply rearrange the formula: *R = \frac{V}{I}\*.
One key insight from Ohm's Law is that as resistance increases, for the same voltage, the current will decrease. This law helps in predicting how a circuit will behave under various conditions, which is fundamental when designing electrical systems.
Thermal Energy in Resistors
When electric current flows through a resistor, it encounters resistance which causes the electrical energy to be converted into thermal energy. This is often referred to as Joule heating or resistive heating. The thermal energy produced in a resistor can be described by the power dissipation formula we encountered earlier: \[ P = I^2R \]. Further, we recognize that the power represents the rate at which thermal energy is generated.
This rate is very critical in practical applications because excessive heat can damage components and affect their performance.
Designing circuits with proper heat management is essential for maintaining efficiency and longevity of electrical components.

The energy converted into heat over time is calculated by multiplying the power by the duration of time: \[ ext{Thermal Energy} = P imes t \] Where \( t \) is the time in seconds. This equation highlights the total energy conversion occurring due to resistance during a given time and underscores the importance of managing heat in devices like resistors for safe and efficient operation.

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Most popular questions from this chapter

A potential difference of \(1.20 \mathrm{~V}\) will be applied to a \(33.0 \mathrm{~m}\) length of 18 -gauge copper wire (diameter \(=0.0400\) in.). Calculate (a) the current, (b) the magnitude of the current density, (c) the magnitude of the electric field within the wire, and (d) the rate at which thermal energy will appear in the wire.

A charged belt, \(50 \mathrm{~cm}\) wide, travels at \(30 \mathrm{~m} / \mathrm{s}\) between a source of charge and a sphere. The belt carries charge into the sphere at a rate corresponding to \(100 \mu \mathrm{A}\). Compute the surface charge density on the belt.

When \(115 \mathrm{~V}\) is applied across a wire that is \(10 \mathrm{~m}\) long and has a \(0.30 \mathrm{~mm}\) radius, the magnitude of the current density is \(1.4 \times\) \(10^{4} \mathrm{~A} / \mathrm{m}^{2}\). Find the resistivity of the wire,

A Nichrome heater dissipates \(500 \mathrm{~W}\) when the applied potential difference is \(110 \mathrm{~V}\) and the wire temperature is \(800^{\circ} \mathrm{C}\). What would be the dissipation rate if the wire temperature were held at \(200^{\circ} \mathrm{C}\) by immersing the wire in a bath of cooling oil? The applied potential difference remains the same, and \(\alpha\) for Nichrome at \(800^{\circ} \mathrm{C}\) is \(4.0 \times 10^{-4} \mathrm{~K}^{-1}\).

A beam contains \(2.0 \times 10^{8}\) doubly charged positive ions per cubic centimeter, all of which are moving north with a speed of \(1.0 \times 10^{5} \mathrm{~m} / \mathrm{s}\). What are the (a) magnitude and (b) direction of the current density \(\vec{J} ?\) (c) What additional quantity do you need to calculate the total current \(i\) in this ion beam?

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