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What is the resistivity of a wire of \(1.0 \mathrm{~mm}\) diameter, \(2.0\) \(\mathrm{m}\) length, and \(50 \mathrm{~m} \Omega\) resistance?

Short Answer

Expert verified
The resistivity is approximately \(1.9625 \times 10^{-8} \Omega\cdot \text{m}\).

Step by step solution

01

Identify the given values

We have been given the diameter of the wire as \(1.0 \text{ mm}\), which needs to be converted into meters: \(1.0 \text{ mm} = 0.001 \text{ m}\). The length of the wire is \(2.0 \text{ m}\), and the resistance is \(50 \text{ m}\Omega = 50 \times 10^{-3} \text{ }\Omega\).
02

Calculate the cross-sectional area

The cross-section of the wire is circular. Use the formula for the area of a circle, \(A = \pi r^2\), where \(r\) is the radius. The radius \(r\) is half of the diameter, so \(r = 0.5 \times 0.001\, \text{m} = 0.0005\, \text{m}\). Now calculate the area:\[A = \pi (0.0005)^2 = \pi \times 0.00000025\, \text{m}^2\approx 7.85 \times 10^{-7}\, \text{m}^2\]
03

Use the resistivity formula

The formula that relates resistance \(R\), resistivity \(\rho\), length \(L\), and cross-sectional area \(A\) is:\[R = \rho \frac{L}{A}\]We can rearrange it to solve for resistivity \(\rho\):\[\rho = R \frac{A}{L}\]
04

Substitute values into the formula

Now substitute the known values into the formula from Step 3:\[\rho = (50 \times 10^{-3}) \Omega \cdot \frac{7.85 \times 10^{-7} \text{ m}^2}{2.0 \text{ m}}\]\[\rho = 50 \times 10^{-3} \times 3.925 \times 10^{-7} = 1.9625 \times 10^{-8} \Omega \cdot \text{m}\]
05

Double-check the calculation

Verify the calculation for accuracy:1. Calculate \(A = 7.85 \times 10^{-7}\, \text{m}^2\) (confirmed).2. Substitute into \(\rho = (50 \times 10^{-3})\Omega \cdot \frac{7.85 \times 10^{-7}\, \text{m}^2}{2.0\text{ m}}\) and simplify.3. Calculate \(\rho = 1.9625 \times 10^{-8} \Omega \cdot \text{m}\) (confirmed).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ohm's Law
Ohm's Law is a fundamental principle in the field of electrical engineering and physics. It states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points, provided the temperature remains constant. This can be mathematically represented by the formula:
  • The formula is given by: \[ V = IR \] where \( V \) is the voltage, \( I \) is the current, and \( R \) is the resistance of the conductor.
  • A higher resistance implies that less current flows for a given voltage.
It is crucial for understanding how resistors and circuits operate. When solving for the resistivity of a wire, as in the provided exercise, Ohm's Law helps us understand the role of resistance in the circuit. Resistance is a key element, as it is affected by the wire’s material and geometry. While Ohm’s Law typically connects voltage, current, and resistance, it also sets the foundation for exploring resistivity in conductive materials.
Circular Cross Section
A circular cross section refers to the shape of the area that a wire presents when viewed from its end. For wires manufactured in practical scenarios, most commonly, this shape is a circle. This is crucial particularly when calculating the cross-sectional area, which influences the wire’s resistance.To compute the area of a circle, use:
  • The formula for the area of a circle is: \[ A = \pi r^2 \] where \( r \) is the radius of the circle.
  • For the given exercise, the diameter of the wire is \(1.0 \text{ mm}\), which means the radius \( r \) is half of the diameter, i.e., \(0.5 \times 0.001 \text{ m}\ equals 0.0005 \text{ m}\).
  • Using the formula, the area is calculated as \( A \approx 7.85 \times 10^{-7} \text{ m}^2 \).
The cross-sectional area is important because it affects the resistance and resistivity calculations, where a smaller area results in greater resistance.
Resistivity Formula
The resistivity formula plays a pivotal role in determining how materials resist current flow in an electrical circuit. It links together resistance, resistivity, the length of the conductor, and its cross-sectional area.The relationship is expressed by the formula:
  • \[ R = \rho \frac{L}{A} \] Where \( R \) is resistance, \( \rho \) is resistivity, \( L \) is the length of the conductor, and \( A \) is the cross-sectional area.
  • To find the resistivity \( \rho \) of a wire, rearrange the formula to: \[ \rho = R \frac{A}{L} \]
Understanding resistivity helps in determining how resistive a material is inherently. It's a material-specific property:
  • A material with high resistivity will resist the flow of electric current more than a material with low resistivity.
  • This resistivity depends on the material composition and its temperature.
For the given exercise, by substituting the known values in the formula, resistivity is calculated as \( \rho = 1.9625 \times 10^{-8} \Omega \cdot \text{m} \). Accurately calculating resistivity is essential for designing circuits with appropriate resistance levels.

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Most popular questions from this chapter

A current is established in a gas discharge tube when a sufficiently high potential difference is applied across the two electrodes in the tube. The gas ionizes; electrons move toward the positive terminal and singly charged positive ions toward the negative terminal. (a) What is the current in a hydrogen discharge tube in which \(3.1 \times 10^{18}\) electrons and \(1.1 \times 10^{18}\) protons move past a cross-sectional area of the tube each second? (b) Is the direction of the current density \(\vec{J}\) toward or away from the negative terminal?

A certain brand of hot-dog cooker works by applying a potential difference of \(120 \mathrm{~V}\) across opposite ends of a hot dog and allowing it to cook by means of the thermal energy produced. The current is \(10.0 \mathrm{~A}\), and the energy required to cook one hot dog is \(60.0\) \(\mathrm{kJ}\). If the rate at which energy is Fig. supplied is unchanged, how long will it take to cook three hot dogs simultaneously?

A human being can be electrocuted if a current as small as \(50 \mathrm{~mA}\) passes near the heart. An electrician working with sweaty hands makes good contact with the two conductors he is holding, one in each hand. If his resistance is \(2000 \Omega\), what might the fatal voltage be?

An unknown resistor is connected between the terminals of a \(3.00 \mathrm{~V}\) battery. Energy is dissipated in the resistor at the rate of \(0.540 \mathrm{~W}\). The same resistor is then connected between the terminals of a \(1.50 \mathrm{~V}\) battery. At what rate is energy now dissipated?

Near Earth, the density of protons in the solar wind (a stream of particles from the Sun) is \(8.70 \mathrm{~cm}^{-3}\), and their speed is \(470 \mathrm{~km} / \mathrm{s}\). (a) Find the current density of these protons. (b) If Earth's magnetic field did not deflect the protons, what total current would Earth receive?

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