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What is the escape speed for an electron initially at rest on the surface of a sphere with a radius of \(1.0 \mathrm{~cm}\) and a uniformly distributed charge of \(1.6 \times 10^{-15} \mathrm{C} ?\) That is, what initial speed must the electron have in order to reach an infinite distance from the sphere and have zero kinetic energy when it gets there?

Short Answer

Expert verified
The escape speed is approximately \(5.93 \times 10^6 \text{ m/s}\).

Step by step solution

01

Understand the Concept

The escape speed is the minimum speed needed for an object to break free from the gravitational or electrostatic attraction of a body to reach infinity, where its kinetic energy becomes zero. For an electron escaping a charged sphere, this involves overcoming the electrostatic potential energy.
02

Calculate the Electrostatic Potential Energy

The electrostatic potential energy \( U \) at the surface of a sphere of radius \( R \) and charge \( Q \) is given by \( U = \frac{k_e Q e}{R} \), where \( k_e \) is Coulomb's constant \( 8.99 \times 10^9 \text{ Nm}^2 \text{C}^{-2} \), \( Q = 1.6 \times 10^{-15} \text{ C} \), \( e \) is the charge of the electron \( 1.6 \times 10^{-19} \text{ C} \), and \( R = 0.01 \text{ m} \).
03

Use Energy Conservation for Escape Speed

For the electron to escape, its initial kinetic energy must equal the potential energy it needs to break free: \( \frac{1}{2}mv^2 = \frac{k_e Q e}{R} \), where \( m \) is the mass of the electron \( 9.11 \times 10^{-31} \text{ kg} \) and \( v \) is the escape speed. Solve for \( v \).
04

Solve for Speed

Rearrange the formula to estimate escape speed: \( v = \sqrt{\frac{2k_e Q e}{mR}} \). Substitute the known values: \( v = \sqrt{\frac{2 \times 8.99 \times 10^9 \times 1.6 \times 10^{-15} \times 1.6 \times 10^{-19}}{9.11 \times 10^{-31} \times 0.01}} \). Calculate \( v \).
05

Calculate the Result

Calculate \( v \) and it results in approximately \( 5.93 \times 10^6 \text{ m/s} \). This is the speed required for the electron to escape the sphere's electric field.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Escape Speed
Escape speed is the minimum velocity required for an object to travel infinitely far away from a gravitational or electrostatic source without any further propulsion. This means the object can effectively "escape" the influence of the gravitational or electrostatic field it is in.
For example, in this problem, we want to find out the speed needed by an electron to escape a charged sphere's electric field. The electron, starting at rest, must reach a point far away from the sphere where its kinetic energy in the system is zero. The sphere here has a specific charge distribution, and given its radius and charge, we can determine the escape velocity.
  • The notion of escape speed is closely linked to potential energy. Potential energy must be overcome for an object to escape a field.
  • Escape speed is unique because it depends on the characteristics of the object exerting the field (like the sphere's charge here) and not the escaping object alone (the electron).
This calculation does not consider external factors like friction or air resistance, as it assumes a vacuum environment up to a certain distance from the field.
Electrostatic Potential Energy
Electrostatic potential energy refers to the energy stored due to the positions of charged particles in an electric field. It plays a crucial role in calculating escape speed, as this energy must be overcome for the object to escape.
In our exercise, we are dealing with a charged sphere, and the electrostatic potential energy ( \( U \) ) for an electron at the surface is given by:\[U = \frac{k_e Q e}{R}\]
where:
  • \( k_e \) is Coulomb's constant, \( 8.99 \times 10^9 \text{ Nm}^2 \text{C}^{-2} \).
  • \( Q \) is the total charge of the sphere, \( 1.6 \times 10^{-15} \text{ C} \).
  • \( e \) is the charge of an electron, \( 1.6 \times 10^{-19} \text{ C} \).
  • \( R \) is the radius of the sphere, \( 0.01 \text{ m} \).
This formula calculates the potential energy due to the presence of another charge within the electric field of the sphere. This energy is what the electron needs to overcome to reach infinity (essentially escaping the sphere's electric influence for good). Understanding this concept helps us comprehend how charged particles behave in electric fields.
Conservation of Energy
The law of conservation of energy is fundamental in physics and states that energy cannot be created or destroyed; it can only change forms. For the electron escape problem, this principle implies that the total mechanical energy of the system remains constant.
In the context of the escape speed, the conservation of energy principle translates to ensuring that the initial energy (combination of kinetic and potential energy at the surface of the sphere) equals the final energy (kinetic energy at infinity, is zero). The equation used here is:
  • \( \frac{1}{2}mv^2 = \frac{k_e Q e}{R} \)
where:
  • \( m \) is the mass of the electron, \( 9.11 \times 10^{-31} \text{ kg} \).
  • \( v \) is the escape velocity we seek.
This relationship ensures that all potential energy the electron had initially is converted into kinetic energy needed to reach infinity. Solving this equation gives us the precise escape velocity needed. This concept underscores the balance and transformation of energy in any given system, providing us with a powerful tool to analyze physical phenomena.

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Most popular questions from this chapter

Two electrons are fixed \(2.0 \mathrm{~cm}\) apart. Another electron is shot from infinity and stops midway between the two. What is its initial speed?

A solid copper sphere whose radius is \(1.0 \mathrm{~cm}\) has a very thin surface coating of nickel. Some of the nickel atoms are radioactive, each atom emitting an electron as it decays. Half of these electrons enter the copper sphere, each depositing \(100 \mathrm{keV}\) of energy there. The other half of the electrons escape, each carrying away a charge \(-e\). The nickel coating has an activity of \(3.70 \times\) \(10^{8}\) radioactive decays per second. The sphere is hung from a long, nonconducting string and isolated from its surroundings. (a) How long will it take for the potential of the sphere to increase by 1000 \(\mathrm{V}\) ? (b) How long will it take for the temperature of the sphere to increase by \(5.0 \mathrm{~K}\) due to the energy deposited by the electrons? The heat capacity of the sphere is \(14 \mathrm{~J} / \mathrm{K}\).

Three \(+0.12\) C charges form an equilateral triangle \(1.7\) \(\mathrm{m}\) on a side. Using energy supplied at the rate of \(0.83 \mathrm{~kW}\), how many days would be required to move one of the charges to the midpoint of the line joining the other two charges?

Much of the material making up Saturn's rings is in the form of tiny dust grains having radii on the order of \(10^{-6} \mathrm{~m}\). These grains are located in a region containing a dilute ionized gas, and they pick up excess electrons. As an approximation, suppose each grain is spherical, with radius \(R=1.0 \times 10^{-6} \mathrm{~m} .\) How many electrons would one grain have to pick up to have a potential of \(-400 \mathrm{~V}\) on its surface (taking \(V=0\) at infinity)?

Here are the charges and coordinates of two point charges located in an \(x y\) plane: \(q_{1}=+3.00 \times 10^{-6} \mathrm{C}, x=+3.50 \mathrm{~cm}\), \(y=+0.500 \mathrm{~cm}\) and \(q_{2}=-4.00 \times 10^{-6} \mathrm{C}, x=-2.00 \mathrm{~cm}, y=+1.50\) \(\mathrm{cm}\). How much work must be done to locate these charges at their given positions, starting from infinite separation?

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