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The electric field just above the surface of the charged conducting drum of a photocopying machine has a magnitude \(E\) of \(2.3 \times 10^{5} \mathrm{~N} / \mathrm{C} .\) What is the surface charge density on the drum?

Short Answer

Expert verified
The surface charge density is \(2.03 \times 10^{-6} \ \text{C/m}^2\).

Step by step solution

01

Understanding the Electric Field and Surface Charge Density

The surface charge density \( \sigma \) on a conducting surface is related to the electric field \( E \) just above the surface. For a conductor, the relationship is given by the equation \( E = \frac{\sigma}{\varepsilon_0} \), where \( \varepsilon_0 \) is the permittivity of free space, equal to \( 8.85 \times 10^{-12} \ \text{C}^2/\text{N} \cdot \text{m}^2 \).
02

Rearrange the Formula for Surface Charge Density

Rearrange the equation \( E = \frac{\sigma}{\varepsilon_0} \) to solve for \( \sigma \). This gives \( \sigma = E \varepsilon_0 \).
03

Substituting Values to Calculate \( \sigma \)

Substitute the given value of electric field \( E = 2.3 \times 10^5 \ \text{N/C} \) and \( \varepsilon_0 = 8.85 \times 10^{-12} \ \text{C}^2/\text{N} \cdot \text{m}^2 \) into the rearranged formula:\[\sigma = (2.3 \times 10^5 \ \text{N/C}) \times (8.85 \times 10^{-12} \ \text{C}^2/\text{N} \cdot \text{m}^2)\]
04

Perform the Calculation

Carry out the multiplication to find \( \sigma \):\[\sigma = 2.3 \times 8.85 \times 10^{5 - 12} \ \text{C/m}^2\]\[\sigma = 2.03 \times 10^{-6} \ \text{C/m}^2\]
05

State the Conclusion

The calculated surface charge density \( \sigma \) on the drum is \( 2.03 \times 10^{-6} \ \text{C/m}^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Surface Charge Density
Surface charge density, often denoted by the symbol \( \sigma \), is a measure of how much electric charge is accumulated over a specific area on a surface. It's like asking how "thick" the charge layer is on a surface.
This concept is crucial when dealing with electric fields and potentials around charged objects.

Think about the surface of a conductor like a drum in a photocopying machine. The charge on this surface will affect the electric field in the nearby region. For a given electric field \( E \), we can describe the surface charge density using the formula \( \sigma = E \varepsilon_0 \) where \( \varepsilon_0 \) is the permittivity of free space.

This relationship helps us understand the behavior of charged surfaces in both practical and theoretical situations:
  • It allows calculation of charge required for a specific electric field strength.
  • It describes how charge distribution affects electric fields around conductors.
Permittivity of Free Space
The permittivity of free space, symbolized by \( \varepsilon_0 \), is a fundamental constant in physics.
This value permeates through equations related to electric and magnetic fields, acting like a baseline for understanding electric behavior in a vacuum.

It's value is approximately \( 8.85 \times 10^{-12} \ ext{C}^2/ ext{N} \cdot \text{m}^2 \).
This constant essentially describes how much electric field can "pass through" free space or a vacuum.

Its presence in the equation \( E = \frac{\sigma}{\varepsilon_0} \) suggests that for any given charge density, the resulting electric field also depends on \( \varepsilon_0 \):
  • \( \varepsilon_0 \) serves as a scaling factor for the strength of electric fields in a vacuum.
  • It is critical for calculating forces between charged particles.
Conducting Surface
A conducting surface is one that can transmit electrical current. Metals are examples of good conductors due to their mobile electrons.
When a charge is placed on a conductor, the electrons spread out evenly across the surface. They do this in order to minimize repulsive forces between them.

This even distribution results in uniform surface charge density, making it easier to predict the electric field just outside its surface:
  • In a conductor, the electric field inside is zero, and all charges reside on the surface.
  • The external electric field directly relates to the surface charge density.
Think about it like spreading peanut butter across a piece of bread; you want it to be even. This ensures a smooth electric field around the conductor.
Such uniformity is crucial in technology, where control over electric fields can mean precision and accuracy in electronic devices.
Photocopying Machine Drum
A photocopying machine drum is an essential component in a copier.
The drum holds an electrostatic charge that attracts toner particles, transferring them onto paper to create copies.

When you charge the drum, you are setting up a surface charge density that controls how well the toner is attracted to the drum.
Understand that a higher surface charge density means stronger electric fields:
  • A greater ability to attract toner particles to ensure clearer copy images.
  • The electric field should be uniform to prevent smudging or uneven print quality.
The functionality of the drum relies heavily on the concepts of electric fields and surface charge density.
Designing copier drums with these principles in mind ensures high-quality printouts and efficiency in operation.

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Most popular questions from this chapter

Charge is distributed uniformly throughout the volume of an infinitely long solid cylinder of radius \(R .\) (a) Show that, at a distance \(r<\) \(R\) from the cylinder axis, $$E=\frac{\rho r}{2 \varepsilon_{0}}$$ where \(\rho\) is the volume charge density. (b) Write an expression for \(E\) when \(r>R\)

Charge \(Q\) is uniformly distributed in a sphere of radius \(R\). (a) What fraction of the charge is contained within the radius \(r=R / 2.00 ?\) (b) What is the ratio of the electric field magnitude at \(r=R / 2.00\) to that on the surface of the sphere?

A spherical ball of charged particles has a uniform charge density. In terms of the ball's radius \(R\), at what radial distances (a) inside and (b) outside the ball is the magnitude of the ball's electric field equal to \(\frac{1}{4}\) of the maximum magnitude of that field?

A uniform charge density of \(500 \mathrm{nC} / \mathrm{m}^{3}\) is distributed throughout a spherical volume of radius \(6.00 \mathrm{~cm} .\) Consider a cubical Gaussian surface with its center at the center of the sphere. What is the electric flux through this cubical surface if its edge length is (a) \(4.00 \mathrm{~cm}\) and (b) \(14.0 \mathrm{~cm} ?\)

Space vehicles traveling through Earth's radiation belts can intercept a significant number of electrons. The resulting charge buildup can damage electronic components and disrupt operations. Suppose a spherical metal satellite \(1.3 \mathrm{~m}\) in diameter accumulates \(2.4\) \(\mu \mathrm{C}\) of charge in one orbital revolution. (a) Find the resulting surface charge density. (b) Calculate the magnitude of the electric field just outside the surface of the satellite, due to the surface charge.

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