Chapter 21: Problem 1
Of the charge \(Q\) initially on a tiny sphere, a portion \(q\) is to be transferred to a second, nearby sphere. Both spheres can be treated as particles. For what value of \(q / Q\) will the electrostatic force between the two spheres be maximized?
Short Answer
Expert verified
\( q / Q = 1/2 \) maximizes the force.
Step by step solution
01
Express the Electrostatic Force
The electrostatic force between the two spheres can be described by Coulomb's Law: \[ F = k \frac{q(Q-q)}{r^2} \]where \( k \) is the electrostatic constant, \( q \) is the charge transferred, \( Q-q \) is the charge remaining on the first sphere, and \( r \) is the distance between the centers of the two spheres.
02
Simplify the Force Equation
To make the problem easier, simplify the equation of force by substituting \( k \) and \( r^2 \) as constants, getting:\[ F \propto q(Q-q) = qQ - q^2 \].This expression will be maximized to find the optimal value of \( \frac{q}{Q} \).
03
Define the Function for Maximization
Let \( f(q) = qQ - q^2 \). This is a quadratic function that opens downward, since the coefficient of \( q^2 \) is negative.
04
Find the Derivative of the Function
To find the maximum, take the derivative of \( f(q) \) with respect to \( q \):\[ f'(q) = Q - 2q \].
05
Set the Derivative Equal to Zero
To find the critical points, set the derivative equal to zero:\[ Q - 2q = 0 \].Solve for \( q \) by rearranging the equation:\[ q = \frac{Q}{2} \].
06
Determine the Value of \(\frac{q}{Q}\)
Substitute \( q = \frac{Q}{2} \) back into the ratio \( \frac{q}{Q} \):\[ \frac{q}{Q} = \frac{\frac{Q}{2}}{Q} = \frac{1}{2} \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electrostatic Force
Electrostatic force is a fundamental concept in physics that describes the force of attraction or repulsion between two electrically charged particles. This force is calculated using Coulomb's Law, which is named after Charles-Augustin de Coulomb, who first formulated it in the 18th century. Coulomb's Law states that the electrostatic force (\( F \)) between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance (\( r \)) between them. This is expressed mathematically as:
Understanding this force helps you explain various phenomena, from adhesion of particles to the behavior of capacitors.
- \[ F = k \frac{q_1 q_2}{r^2} \]
Understanding this force helps you explain various phenomena, from adhesion of particles to the behavior of capacitors.
Quadratic Function
A quadratic function is a type of polynomial function specifically of degree two, characterized by the general equation:
- \[ f(x) = ax^2 + bx + c \]
- \[ F \, \propto \, qQ - q^2 \]
Derivative of a Function
The derivative of a function is a mathematical tool that measures how a function changes as its input changes. It provides the rate at which the function's value is changing at any given point, often regarded as the 'slope' of the function. For a quadratic function like \( f(q) \), the derivative helps identify where the function reaches its maximum or minimum value by finding critical points.
- The derivative of \( f(q) = qQ - q^2 \) is \( f'(q) = Q - 2q \)
- \[ Q - 2q = 0 \]
- \[ q = \frac{Q}{2} \]