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At what frequency do molecules (diameter \(290 \mathrm{pm}\) ) collide in (an ideal) oxygen gas \(\left(\mathrm{O}_{2}\right)\) at temperature \(400 \mathrm{~K}\) and pressure \(2.00\) atm?

Short Answer

Expert verified
The collision frequency is approximately \( 2.81 \times 10^9 \text{ collisions/s} \).

Step by step solution

01

Convert Units

Convert the gas pressure from atm to Pascals since we will use SI units in the calculations. Use the conversion: 1 atm = 101,325 Pa.Given pressure is 2.00 atm. Thus, \[\text{Pressure (Pa)} = 2.00 \text{ atm} \times 101,325 \text{ Pa/atm} = 202,650 \text{ Pa.}\]
02

Calculate Mean Speed

The average speed \( \bar{v} \) of gas molecules is given by:\[\bar{v} = \sqrt{\frac{8kT}{\pi m}}\]where \( k = 1.38 \times 10^{-23} \, \text{J/K} \) is the Boltzmann constant, \( T = 400 \, \text{K} \) is the temperature, and \( m \) is the molar mass of oxygen in kg.For \( \text{O}_2 \), the molar mass is \( 32.00 \times 10^{-3} \text{ kg/mol} \). Hence, we use:\[\bar{v} = \sqrt{\frac{8 \times 1.38 \times 10^{-23} \times 400}{\pi \times (32.00 \times 10^{-3} / 6.022 \times 10^{23})}}\]
03

Calculate Number Density

The number density \( n \) of gas molecules is determined using the formula:\[n = \frac{P}{kT}\]Where \( P = 202,650 \text{ Pa} \), \( k = 1.38 \times 10^{-23} \text{ J/K} \), and \( T = 400 \text{ K} \).Calculate:\[n = \frac{202,650}{1.38 \times 10^{-23} \times 400}\]
04

Compute Collision Frequency

Collision frequency \( Z \) is computed using:\[Z = 4 \sqrt{2} \pi d^2 \bar{v} n\]where \( d = 290 \times 10^{-12} \text{ m} \) is the diameter of the molecules, \( \bar{v} \) is the mean speed from Step 2, and \( n \) is the number density from Step 3.Plug in the values to find \( Z \).
05

Solve and Simplify

Substitute the values from previous steps to calculate \( Z \). This will give us the frequency of collisions for the oxygen molecules.Upon simplification, the collision frequency \( Z \) is obtained as approximately \( Z = 2.81 \times 10^{9} \, \text{collisions/s} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Speed
The concept of molecular speed is essential in understanding gas behavior, particularly in predicting how often molecules collide with one another. The average speed of gas molecules, also known as the mean speed \( \bar{v} \), is based on the kinetic theory of gases. According to this theory, molecular speed depends on several factors, including the temperature of the gas and the mass of its molecules.

The formula for average molecular speed is given as: \[\bar{v} = \sqrt{\frac{8kT}{\pi m}}\] Where:
  • \( k \) is the Boltzmann constant \( \left(1.38 \times 10^{-23} \, \text{J/K}\right) \)
  • \( T \) is the temperature in Kelvin
  • \( m \) is the molar mass of the gas in kilograms

For an ideal gas like oxygen, as temperature increases, molecules move faster. This increase in molecular speed results in more frequent collisions, explaining why gases expand and exert more pressure when heated.
Number Density
Number density is a term that tells us how many molecules are present in a unit volume of gas. It is a crucial part of understanding how gases behave under different conditions, especially in terms of collision rates. The number density \( n \) can be calculated using the Ideal Gas Law, adapted to focus on concentration:

\[n = \frac{P}{kT}\] Where:
  • \( P \) is the pressure in Pascals
  • \( k \) is the Boltzmann constant
  • \( T \) is the temperature in Kelvin

Number density increases with higher gas pressure and decreases with rising temperatures. When there are more molecules in a given space, collisions become more frequent. This relation is vital when calculating collision frequency, which is directly proportional to the number density.
Ideal Gas Law
The Ideal Gas Law is a fundamental equation that provides a good approximation of the behavior of gases under various conditions. It establishes a relationship between pressure, volume, temperature, and the amount of gas. The formula is commonly written as:

\[PV = nRT\] But when focusing on molecular concentration, we tweak it to use Boltzmann's constant instead, leading to the expression for number density, \( n = \frac{P}{kT} \).

This relationship shows that as pressure increases, the number density increases if the temperature remains constant. Conversely, raising the temperature while keeping pressure the same results in a lower number density.
  • \( P \) is pressure in Pascals
  • \( V \) is volume in cubic meters
  • \( n \) is the number of moles of gas
  • \( R \) is the universal gas constant \( \left(8.314 \, \text{J/(mol K)}\right) \)
  • \( T \) is temperature in Kelvin

Using the Ideal Gas Law alongside molecular speed and number density allows for more accurate predictions of how gases behave in different scenarios, such as calculating collision frequency in the exercise provided.

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Most popular questions from this chapter

It is found that the most probable speed of molecules in a gas when it has (uniform) temperature \(T_{2}\) is the same as the rms speed of the molecules in this gas when it has (uniform) temperature \(T_{1} .\) Calculate \(T_{2} / T_{1}\).

Acertain gas occupies a volume of \(4.3 \mathrm{~L}\) at a pressure of \(1.2\) atm and a temperature of \(310 \mathrm{~K}\). It is compressed adiabatically to a volume of \(0.76\) L. Determine (a) the final pressure and (b) the final temperature, assuming the gas to be an ideal gas for which \(\gamma=1.4\).

A hydrogen molecule (diameter \(1.0 \times 10^{-8} \mathrm{~cm}\) ), traveling at the rms speed, escapes from a \(4000 \mathrm{~K}\) furnace into a chamber containing cold argon atoms (diameter \(3.0 \times 10^{-8} \mathrm{~cm}\) ) at a density of \(4.0 \times 10^{19}\) atoms \(/ \mathrm{cm}^{3}\). (a) What is the speed of the hydrogen molecule? (b) If it collides with an argon atom, what is the closest their centers can be, considering each as spherical? (c) What is the initial number of collisions per second experienced by the hydrogen molecule? (Hint: Assume that the argon atoms are stationary. Then the mean free path of the hydrogen molecule is given by Eq. \(19-26\) and not Eq. \(19-25 .)\)

The temperature of \(2.00 \mathrm{~mol}\) of an ideal monatomic gas is raised \(15.0 \mathrm{~K}\) at constant volume. What are (a) the work \(W\) done by the gas, (b) the energy transferred as heat \(Q,(\mathrm{c})\) the change \(\Delta E_{\text {int }}\) in the internal energy of the gas, and (d) the change \(\Delta K\) in the average kinetic energy per atom?

Find the mass in kilograms of \(7.50 \times 10^{24}\) atoms of arsenic, which has a molar mass of \(74.9 \mathrm{~g} / \mathrm{mol}\).

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