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Two sinusoidal waves, identical except for phase, travel in the same direction along a string, producing the net wave \(y^{\prime}(x, t)=(3.0 \mathrm{~mm}) \sin (20 x-4.0 t+0.820 \mathrm{rad})\), with \(x\) in meters and \(t\) in seconds. What are (a) the wavelength \(\lambda\) of the two waves, (b) the phase difference between them, and (c) their amplitude \(y_{m} ?\)

Short Answer

Expert verified
(a) 0.314 m, (b) 0.820 rad, (c) 3.0 mm

Step by step solution

01

Identify the Wave Equation

The given wave equation is \(y'(x, t) = (3.0 \, \text{mm}) \sin (20x - 4.0t + 0.820 \, \text{rad})\). This equation represents the superposition of two waves, and we need to extract parameters like the angular wave number (\(k\)) and angular frequency (\(\omega\)).
02

Determine the Wavelength λ

In the wave equation \((k = 20)\), the angular wave number \(k\) is related to the wavelength \(\lambda\) by the formula \(k = \frac{2\pi}{\lambda}\). Solving for \(\lambda\), we have: \(\lambda = \frac{2\pi}{k} = \frac{2\pi}{20} = 0.314 \, \text{m}\).
03

Identify the Phase Constant

The phase constant provided in the equation is \(0.820 \, \text{rad}\). This is used to determine the phase difference between the two sinusoidal waves. For one of the waves, this phase constant \(\phi\) signifies the shift in phase.
04

Calculate the Phase Difference

The given wave is formed by the superposition of two waves, which results in the net phase shift \(\phi = 0.820 \, \text{rad}\). For two identical waves, the phase difference is usually \(\Delta \phi = 0\). Here, the phase difference enhancing this system’s amplitude is \(\Delta \phi = \phi = 0.820 \, \text{rad}\).
05

Determine the Amplitude of the Resulting Wave

The amplitude of the individual waves can be found through the given resulting amplitude \(3.0 \, \text{mm}\), considering constructive interference. Thus, the amplitude \(y_m\) of each original wave is also \(3.0 \, \text{mm}\), since full constructive interference occurs when the amplitude does not change.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wavelength calculation
The wavelength of a wave is a crucial aspect of understanding wave behavior, particularly when it comes to superposition. Wavelength, denoted by the symbol \( \lambda \), represents the distance over which the wave's shape repeats. In simpler terms, it's the length of one complete wave cycle. To calculate the wavelength, we use the relationship between the angular wave number \( k \) and the wavelength. From the wave equation, \( y'(x, t) = (3.0 \, \text{mm}) \sin (20x - 4.0t + 0.820 \, \text{rad}) \), we identify that the angular wave number \( k \) is equal to 20. The formula to find the wavelength from \( k \) is:\[\lambda = \frac{2\pi}{k}\]Plugging in the value of \( k \), we get:\[\lambda = \frac{2\pi}{20} = 0.314 \, \text{m}\]This tells us that the wavelength of the wave is 0.314 meters, which is the distance over which each full wave cycle occurs.
Phase difference
The concept of phase difference is crucial in wave superposition scenarios. Phase difference refers to the offset between the phases of two waves traveling through the same medium. The phase difference can significantly affect how waves combine.In our example, the net phase difference arises from the phase constant \( 0.820 \, \text{rad} \) in the given wave equation. Typically, this phase constant \( \phi \) indicates a shift in one wave compared to another. When we discuss phase difference, \( \Delta \phi \), it's the difference in the phase constants of the two waves. If wave sequences start at different points, the phase difference tells us how far these starting points are separated in terms of wave cycles. In this case, we have:
  • The phase constant is \( \phi = 0.820 \, \text{rad} \)
  • The phase difference \( \Delta \phi \) is also considered as \( 0.820 \, \text{rad} \) due to the alignment of the waves.
Hence, a phase difference of \( 0.820 \, \text{rad} \) signifies that one wave is a certain fraction of a wave cycle ahead of the other. Understanding this phase relationship can help explain how amplitudes combine, particularly when constructive or destructive interference occurs.
Wave amplitude
Wave amplitude is a measure of the energy carried by a wave, representing the maximum displacement from its rest position. Amplitude is essential for understanding superposition, as it dictates the intensity of the wave's effects when multiple waves interact.From the wave equation given, \( y'(x, t) = (3.0 \, \text{mm}) \sin (20x - 4.0t + 0.820 \, \text{rad}) \), we observe that the overall amplitude of the resulting wave is \( 3.0 \, \text{mm} \). It’s important to note that in a superposition scenario involving two waves, the resulting amplitude can vary based on the phase difference between the waves:
  • If the waves interfere constructively, they reinforce each other, resulting in a larger amplitude.
  • If they interfere destructively, the combined amplitude is reduced.
In our case, the exercise suggests constructive interference as the amplitude remains \( 3.0 \, \text{mm} \) without reduction. Therefore, the amplitude of each of the original waves is also \( 3.0 \, \text{mm} \), indicating perfect constructive interference where each wave supports and enhances the other fully.

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Most popular questions from this chapter

A \(100 \mathrm{~g}\) wire is held under a tension of \(250 \mathrm{~N}\) with one end at \(x=0\) and the other at \(x=10.0 \mathrm{~m}\). At time \(t=0\), pulse 1 is sent along the wire from the end at \(x=10.0 \mathrm{~m}\). At time \(t=30.0\) \(\mathrm{ms}\), pulse 2 is sent along the wire from the end at \(x=0 .\) At what position \(x\) do the pulses begin to meet?

A rope, under a tension of \(200 \mathrm{~N}\) and fixed at both ends, oscillates in a second-harmonic standing wave pattern. The displacement of the rope is given by $$ y=(0.10 \mathrm{~m})(\sin \pi x / 2) \sin 12 \pi t $$ where \(x=0\) at one end of the rope, \(x\) is in meters, and \(t\) is in seconds. What are (a) the length of the rope, (b) the speed of the waves on the rope, and (c) the mass of the rope? (d) If the rope oscillates in a third-harmonic standing wave pattern, what will be the period of oscillation?

A wave has a speed of \(240 \mathrm{~m} / \mathrm{s}\) and a wavelength of \(3.2 \mathrm{~m}\). What are the (a) frequency and (b) period of the wave?

The linear density of a string is \(1.6 \times 10^{-4} \mathrm{~kg} / \mathrm{m}\). A transverse wave on the string is described by the equation $$ y=(0.021 \mathrm{~m}) \sin \left[\left(2.0 \mathrm{~m}^{-1}\right) x+\left(30 \mathrm{~s}^{-1}\right) t\right] $$ What are (a) the wave speed and (b) the tension in the string?

The equation of a transverse wave traveling along a string is $$ y=(2.0 \mathrm{~mm}) \sin \left[\left(20 \mathrm{~m}^{-1}\right) x-\left(600 \mathrm{~s}^{-1}\right) t\right] . $$ Find the (a) amplitude, (b) frequency, (c) velocity (including sign), and (d) wavelength of the wave. (e) Find the maximum transverse speed of a particle in the string.

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