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Two sinusoidal waves of the same frequency travel in the same direction along a string. If \(y_{m 1}=3.0 \mathrm{~cm}, y_{m 2}=4.0 \mathrm{~cm}\), \(\phi_{1}=0\), and \(\phi_{2}=\pi / 2 \mathrm{rad}\), what is the amplitude of the resultant wave?

Short Answer

Expert verified
The amplitude of the resultant wave is 5 cm.

Step by step solution

01

Understanding the problem

We have two sinusoidal waves traveling in the same direction along a string. The task is to find the amplitude of their resultant wave. The waves have the same frequency but different amplitudes and phase angles.
02

Identifying known values

From the problem, we have:- Amplitude of the first wave, \(y_{m1} = 3.0\, \text{cm}\).- Amplitude of the second wave, \(y_{m2} = 4.0\, \text{cm}\).- Phase angle of the first wave, \(\phi_1 = 0\, \text{rad}\).- Phase angle of the second wave, \(\phi_2 = \frac{\pi}{2}\, \text{rad}\).
03

Using the superposition principle

The resultant wave is obtained by superposing the two waves. The amplitude \(A\) of the resultant wave is given by the formula:\[A = \sqrt{y_{m1}^2 + y_{m2}^2 + 2y_{m1}y_{m2}\cos(\phi_2-\phi_1)}\]
04

Calculating the cosine term

Since one phase angle is 0, the difference in phase angles is:\(\phi_2 - \phi_1 = \frac{\pi}{2} - 0 = \frac{\pi}{2}\).Therefore, \(\cos(\frac{\pi}{2}) = 0\).
05

Calculating the resultant amplitude

Substituting the values into the formula:\[A = \sqrt{3.0^2 + 4.0^2 + 2 \times 3.0 \times 4.0 \times 0}\]\[A = \sqrt{9 + 16}\]\[A = \sqrt{25}\]\[A = 5\, \text{cm}\]
06

Conclusion

The amplitude of the resultant wave is calculated to be 5 cm, meaning this is the combined effect of both waves' amplitudes when taking their phases into account.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Superposition Principle
The superposition principle is central to understanding wave interference. It explains how different waves can add up to create a resultant wave. Imagine two people throwing rocks into a pond. The ripples from each rock overlap. Similarly, in wave interference, waves that overlap in space add together to form a new wave. This is called superposition.

When two waves meet, their amplitudes (the height of their peaks) add up at every point along the wave. This can result in either constructive or destructive interference. Constructive interference occurs when waves are in phase. This means their peaks line up, resulting in a wave with a larger amplitude. Destructive interference happens when waves are out of phase, and their peaks and troughs cancel each other out, producing a smaller amplitude. Superposition allows us to calculate the exact form of the resultant wave by considering the amplitudes and phase differences of the individual waves.
Amplitude Calculation
Calculating the amplitude of a resultant wave involves combining the individual amplitudes of the original waves, taking into account their phase difference. For two waves, the formula to find the resultant amplitude is given by:

\[A = \sqrt{y_{m1}^2 + y_{m2}^2 + 2y_{m1}y_{m2}\cos(\phi_2-\phi_1)}\]

Here,
  • \(y_{m1}\) and \(y_{m2}\) are the amplitudes of the individual waves.
  • \(\phi_1\) and \(\phi_2\) are their respective phase angles.
The cosine term accounts for the phase difference between the waves. If the waves have a phase difference of \(\frac{\pi}{2}\), the cosine becomes zero, meaning there is no contribution from the term involving the product of amplitudes. This can simplify calculations significantly, especially when one phase angle is zero. The result is that the amplitude of the resultant wave is the square root of the sum of squares of the individual amplitudes. It's a straightforward yet powerful way to determine how two waves combine to form a single waveform.
Phase Difference
Phase difference is a key concept in understanding how waves interact. It's the relative shift between the peaks of two waves. This is critical in determining the type of interference that will occur.
  • A phase difference of zero means the waves are perfectly in phase. They add constructively, resulting in maximum amplitude.
  • A phase difference of \(\pi\) (or 180 degrees) indicates that the waves are out of phase, leading to destructive interference.
  • When the phase difference is \(\frac{\pi}{2}\), as seen in our exercise, the waves neither fully construct nor destruct, but result in partial interference.
When calculating the resultant wave, knowing the phase difference is crucial. It determines how much the waves will reinforce or cancel each other. In practical terms, this can affect anything from sound intensity in acoustics to light brightness in optics. Understanding phase difference helps us comprehend how waves behave in various real-world scenarios.

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Most popular questions from this chapter

Two waves are generated on a string of length \(3.0\) \(\mathrm{m}\) to produce a three-loop standing wave with an amplitude of \(1.0 \mathrm{~cm} .\) The wave speed is \(100 \mathrm{~m} / \mathrm{s}\). Let the equation for one of the waves be of the form \(y(x, t)=y_{m} \sin (k x+\omega t) .\) In the equation for the other wave, what are (a) \(y_{m}\), (b) \(k,(\mathrm{c}) \omega\), and (d) the sign in front of \(\omega\) ?

A sinusoidal wave is traveling on a string with speed \(40 \mathrm{~cm} / \mathrm{s}\). The displacement of the particles of the string at \(x=10 \mathrm{~cm}\) varies with time according to \(y=(5.0 \mathrm{~cm}) \sin \left[1.0-\left(4.0 \mathrm{~s}^{-1}\right) t\right]\). The linear density of the string is \(4.0 \mathrm{~g} / \mathrm{cm}\). What are (a) the frequency and (b) the wavelength of the wave? If the wave equation is of the form \(y(x, t)=y_{m} \sin (k x \pm \omega t)\), what are (c) \(y_{m},(\mathrm{~d}) k,(\mathrm{e}) \omega\), and (f) the correct choice of sign in front of \(\omega ?(\mathrm{~g})\) What is the tension in the string?

The function \(y(x, t)=(15,0 \mathrm{~cm}) \cos (\pi x-15 \pi t)\), with \(x\) in meters and \(t\) in seconds, describes a wave on a taut string. What is the transverse speed for a point on the string at an instant when that point has the displacement \(y=+12.0 \mathrm{~cm} ?\)

The speed of a transverse wave on a string is \(170 \mathrm{~m} / \mathrm{s}\) when the string tension is \(120 \mathrm{~N}\). To what value must the tension be changed to raise the wave speed to \(180 \mathrm{~m} / \mathrm{s}\) ?

A sand scorpion can detect the motion of a nearby beetle (its prey) by the waves the motion sends along the sand surface (Fig. \(16-29\) ). The waves are of two types: transverse waves traveling at \(v_{t}=50 \mathrm{~m} / \mathrm{s}\) and longitudinal waves traveling at \(v_{l}=150 \mathrm{~m} / \mathrm{s} .\) If a sudden motion sends out such waves, a scorpion can tell the distance of the beetle from the difference \(\Delta t\) in the arrival times of the waves at its leg nearest the beetle. If \(\Delta t=4.0 \mathrm{~ms}\) what is the beetle's distance?

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