/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Find the mechanical energy of a ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the mechanical energy of a block-spring system having a spring constant of \(1.3 \mathrm{~N} / \mathrm{cm}\) and an oscillation amplitude of \(2.4 \mathrm{~cm}\),

Short Answer

Expert verified
The mechanical energy is \(0.03744 \mathrm{~J}\).

Step by step solution

01

Convert Units

Convert the spring constant from \(\mathrm{N/cm}\) to \(\mathrm{N/m}\) by multiplying by 100 (since there are 100 cm in a meter). The spring constant \(k\) becomes \(1.3 \times 100 = 130 \mathrm{~N/m}\).
02

Understand the Formula of Mechanical Energy

Recall that the mechanical energy \(E\) of a spring-block system is given by the formula: \(E = \frac{1}{2} k A^2\), where \(k\) is the spring constant and \(A\) is the amplitude of oscillation.
03

Substitute the Values into the Formula

Substitute the values of \(k = 130 \mathrm{~N/m}\) and \(A = 2.4 \mathrm{~cm} = 0.024 \mathrm{~m}\) into the formula. This gives: \(E = \frac{1}{2} \times 130 \times (0.024)^2\).
04

Perform the Calculations

Calculate \(E = \frac{1}{2} \times 130 \times 0.000576 = \frac{1}{2} \times 0.07488 = 0.03744 \mathrm{~J}\).
05

Interpret the Result

The total mechanical energy of the block-spring system is \(0.03744 \mathrm{~J}\). This energy is conserved and is the sum of kinetic and potential energy as the system oscillates.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spring Constant
The concept of a spring constant is essential in understanding how springs behave. It is denoted by the symbol \(k\) and essentially represents how stiff or rigid a spring is. A higher spring constant means a stiffer spring that requires more force to stretch or compress it by a certain distance.
In the context of a spring-block system, the spring constant plays a vital role in determining the mechanical energy of the system. It is expressed in units of force per unit length, such as \(\mathrm{N/cm}\) or \(\mathrm{N/m}\).
- A larger spring constant \(k\) results in greater potential energy when the spring is compressed or stretched.- The spring constant is crucial for calculations involving oscillations and wave mechanics, particularly in formulas like the one for mechanical energy: \(E = \frac{1}{2} k A^2\).
Oscillation Amplitude
Oscillation amplitude refers to the maximum displacement or distance that an object moves from its equilibrium position during oscillation. In a spring-block system, the amplitude tells us how far the block moves from the center point in either direction.
Understanding amplitude is essential in calculating the mechanical energy of the system. It is part of the energy formula \(E = \frac{1}{2} k A^2\), where \(A\) is the oscillation amplitude. This formula shows that the energy of the system is proportional to the square of the amplitude.
- A larger amplitude results in greater mechanical energy in the spring-block system.- The amplitude is measured in distance units, such as centimeters \((\mathrm{cm})\) or meters \((\mathrm{m})\), but it's crucial to keep unit consistency when performing calculations.
Unit Conversion
Unit conversion is an important step when solving physics problems to ensure all units are consistent, especially in calculations involving formulas with variables expressed in different units.
For the spring constant and amplitude, unit conversion might be necessary:
- Convert the spring constant from \(\mathrm{N/cm}\) to \(\mathrm{N/m}\) by multiplying it by 100. This is because there are 100 centimeters in a meter.- Convert the amplitude from centimeters to meters by dividing by 100. This ensures that both the spring constant and amplitude are in compatible units of meters.
Correct unit conversion ensures that your calculations are accurate, and helps prevent errors in the final result, especially in formulas involving variables like those in mechanics and wave equations.
Spring-Block System
A spring-block system is a classic physics model used to study motion and energy in mechanical systems. It consists of a block attached to a spring, which can oscillate back and forth around a point of equilibrium.
The mechanical energy of this system is a combination of potential energy stored in the spring when it is compressed or stretched, and kinetic energy when the block is in motion.
- As the block moves, this energy converts between potential and kinetic forms, but the total energy remains constant in the absence of friction or external forces. - Understanding this concept is crucial for solving problems related to oscillations and harmonic motion, as this model is foundational in studying how forces and energy interact in a mechanical system.

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Most popular questions from this chapter

The vibration frequencies of atoms in solids at normal temperatures are of the order of \(10^{13} \mathrm{~Hz}\). Imagine the atoms to be connected to one another by springs. Suppose that a single silver atom in a solid vibrates with this frequency and that all the other atoms are at rest. Compute the effective spring constant. One mole of silver \(\left(6.02 \times 10^{23}\right.\) atoms ) has a mass of \(108 \mathrm{~g}\).

In an electric shaver, the blade moves back and forth over a distance of \(2.0 \mathrm{~mm}\) in simple harmonic motion, with frequency \(120 \mathrm{~Hz}\). Find (a) the amplitude, (b) the maximum blade speed, and (c) the magnitude of the maximum blade acceleration.

A block weighing \(20 \mathrm{~N}\) oscillates at one end of a vertical spring for which \(k=100 \mathrm{~N} / \mathrm{m} ;\) the other end of the spring is attached to a ceiling. At a certain instant the spring is stretched \(0.30\) \(\mathrm{m}\) beyond its relaxed length (the length when no object is attached) and the block has zero velocity. (a) What is the net force on the block at this instant? What are the (b) amplitude and (c) period of the resulting simple harmonic motion? (d) What is the maximum kinetic energy of the block as it oscillates?

A grandfather clock has a pendulum that consists of a thin brass disk of radius \(r=15.00 \mathrm{~cm}\) and mass \(1.000\) kg that is attached to a long thin rod of negligible mass. The pendulum swings freely about an axis perpendicular to the rod and through the end of the rod opposite the disk, as shown in Fig. 15-54. If the pendulum is to have a period of \(2.000 \mathrm{~s}\) for small oscillations at a place where \(g=9.800 \mathrm{~m} / \mathrm{s}^{2}\), what must be the rod length \(L\) to the nearest tenth of a millimeter?

A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance \(d\) from the 50 \(\mathrm{cm}\) mark. The period of oscillation is \(2.5 \mathrm{~s}\). Find \(d\).

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