Chapter 14: Problem 51
A garden hose with an internal diameter of \(1.9 \mathrm{~cm}\) is connected to a (stationary) lawn sprinkler that consists merely of a container with 24 holes, each \(0.13 \mathrm{~cm}\) in diameter. If the water in the hose has a speed of \(0.91 \mathrm{~m} / \mathrm{s}\), at what speed does it leave the sprinkler holes?
Short Answer
Step by step solution
Identify Known Values
Calculate the Cross-sectional Area of the Hose
Calculate the Cross-sectional Area of One Hole
Calculate the Total Area of the Sprinkler Holes
Apply Continuity Equation
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Continuity Equation
- \(A_1\) is the cross-sectional area at the first point
- \(v_1\) is the fluid velocity at the first point
- \(A_2\) is the cross-sectional area at the second point
- \(v_2\) is the fluid velocity at the second point
Incompressible Fluids
- Density remains constant.
- The volume flow rate is steady and unchanged.
Cross-sectional Area
- The larger the cross-sectional area, the slower a fluid will flow for a given flow rate.
- In a system like a hose and sprinkler, different sections will have varying cross-sectional areas impacting fluid dynamics.