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A wheel, starting from rest, rotates with a constant angular acceleration of \(2.00 \mathrm{rad} / \mathrm{s}^{2}\). During a certain \(3.00 \mathrm{~s}\) interval, it turns through \(90.0\) rad. (a) What is the angular velocity of the wheel at the start of the \(3.00 \mathrm{~s}\) interval? (b) How long has the wheel been turning before the start of the \(3.00\) s interval?

Short Answer

Expert verified
(a) Initial angular velocity: 27.0 rad/s. (b) Time before interval: 13.5 s.

Step by step solution

01

Understand the given variables and formulae

We are given the angular acceleration \(\alpha = 2.00 \, \mathrm{rad/s^2}\) and the time interval \(t = 3.00 \, \mathrm{s}\). The angular displacement during this interval is \(\theta = 90.0 \, \mathrm{rad}\). We need to find the initial angular velocity \(\omega_i\) at the beginning of this interval and the time before this interval started.
02

Use the formula for angular displacement

The formula for angular displacement with constant angular acceleration is:\[ \theta = \omega_i t + \frac{1}{2} \alpha t^2 \]We can substitute the known values into this formula to solve for \(\omega_i\):\[ 90.0 = \omega_i(3.00) + \frac{1}{2} (2.00)(3.00)^2 \]
03

Solve for initial angular velocity

Plugging in the values and solving the above equation, we have:\[ 90.0 = 3.00\omega_i + \frac{1}{2} (2.00)(9.00) \]This simplifies to:\[ 90.0 = 3.00\omega_i + 9.00 \]Subtract \(9.00\) from both sides:\[ 81.0 = 3.00\omega_i \]Divide by \(3.00\) to find \(\omega_i\):\[ \omega_i = 27.0 \, \mathrm{rad/s} \]
04

Find the time before the interval started

To find how long the wheel has been turning before the 3 s interval, use the formula:\[ \omega_f = \omega_i + \alpha t \]Since the wheel starts from rest:\[ \omega_f = 0 + 2.00 \times t_b \]Where \(t_b\) is the time before the interval. We know \(\omega_i = 27.0 \, \mathrm{rad/s}\) at the start of the 3 s interval, therefore:\[ 27.0 = 0 + 2.00 \times t_b \]Solve for \(t_b\):\[ t_b = \frac{27.0}{2.00} = 13.5 \, \mathrm{s} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Acceleration
Angular acceleration is a measure of how quickly the angular velocity of an object changes with time. Think of it as the rotational counterpart of linear acceleration. When a wheel starts from rest and you apply a constant force, it begins to spin faster and faster. This increase in spin rate is quantified by angular acceleration, denoted as \( \alpha \).

The units for angular acceleration are radian per second squared \( \mathrm{rad/s^2} \). This tells us how many radians of angular velocity are being added every second. In the exercise, the wheel has an angular acceleration of \( 2.00 \, \mathrm{rad/s^2} \). This means every second, the wheel’s angular velocity increases by \( 2.00 \, \mathrm{rad/s} \), assuming no other forces are acting to reduce it.

Understanding angular acceleration helps us predict how an object will rotate over time and is crucial in solving problems involving rotational motion.
Angular Velocity
Angular velocity refers to the rate at which an object rotates around a point or an axis. It is similar to linear velocity, but instead of measuring in meters per second \( \mathrm{m/s} \), it's expressed in radians per second \( \mathrm{rad/s} \). If you imagine a wheel spinning, the angular velocity tells you how fast it's spinning.

In the problem, before the 3-second interval starts, we calculate an initial angular velocity \( \omega_i \) of \( 27.0 \, \mathrm{rad/s} \). This means that, at the beginning of this interval, the wheel was rotating at a speed of \( 27.0 \, \mathrm{rad/s} \).

Angular velocity is crucial for understanding how fast something is spinning at any given moment and is a key variable in rotational motion equations.
Kinematics Equations
Kinematics equations are powerful tools in physics that help us describe the motion of objects. These equations relate quantities such as displacement, velocity, acceleration, and time.

For angular motion, we adapt linear kinematics equations to account for rotations:
  • \( \theta = \omega_i t + \frac{1}{2} \alpha t^2 \): This formula calculates the angular displacement when you know the initial angular velocity, angular acceleration, and time.
  • \( \omega_f = \omega_i + \alpha t \): This helps find the final angular velocity when you know an object's initial angular velocity and how long it's been accelerating.
In our exercise, we use these formulas to determine both the initial angular velocity and the time the wheel has been rotating prior to a given interval. Using kinematics efficiently allows us to solve complex rotation problems with ease.

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Most popular questions from this chapter

A drum rotates around its central axis at an angular velocity of \(12.60 \mathrm{rad} / \mathrm{s}\). If the drum then slows at a constant rate of \(4.20 \mathrm{rad} / \mathrm{s}^{2}\) (a) how much time does it take and (b) through what angle does it rotate in coming to rest?

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The angular position of a point on the rim of a rotating wheel is given by \(\theta=4.0 t-3.0 t^{2}+t^{3}\), where \(\theta\) is in radians and \(t\) is in seconds. What are the angular velocities at (a) \(t=2.0 \mathrm{~s}\) and \((\mathrm{b}) t=4.0 \mathrm{~s} ?(\mathrm{c})\) What is the average angular acceleration for the time interval that begins at \(t=2.0 \mathrm{~s}\) and ends at \(t=4.0 \mathrm{~s}\) ? What are the instantaneous angular accelerations at (d) the beginning and (e) the end of this time interval?

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