/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 An automobile crankshaft transfe... [FREE SOLUTION] | 91Ó°ÊÓ

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An automobile crankshaft transfers energy from the engine to the axle at the rate of \(100 \mathrm{hp}(=74.6 \mathrm{~kW})\) when rotating at a speed of 1800 rev/min. What torque (in newton-meters) does the crankshaft deliver?

Short Answer

Expert verified
The torque delivered is approximately 396 Nm.

Step by step solution

01

Convert Power

Given the power of the crankshaft is \( 100 \text{ hp} \), which is equivalent to \( 74.6 \text{ kW} \). Since we are dealing with kW, the conversion from horsepower to kilowatts is not necessary in this case as it is already provided.
02

Convert Rotational Speed

The rotational speed is given as \( 1800 \text{ rev/min} \). We need to convert this to radians per second. We use the conversion \( 1 \text{ rev} = 2\pi \text{ radians} \). Thus,\[1800 \text{ rev/min} \times \frac{2\pi \text{ radians}}{1 \text{ rev}} \times \frac{1 \text{ min}}{60 \text{ sec}} = 188.5 \text{ rad/s}\]
03

Calculate Torque

Using the formula for power in terms of torque:\[ P = \tau \omega \]where \( P \) is power, \( \tau \) is torque, and \( \omega \) is angular velocity. We rearrange to find torque:\[ \tau = \frac{P}{\omega} \]Substitute the known values:\[ \tau = \frac{74.6 \times 10^3 \text{ W}}{188.5 \text{ rad/s}} \approx 396 \text{ Nm} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Conversion
One of the essential concepts in physics is power conversion, particularly when dealing with machinery and engines. Power, which indicates the rate of energy transfer, is often given in different units depending on the context.
For example, an automobile's engine power might initially be stated in horsepower (hp), a unit commonly used in automotive settings.
However, it is often converted into kilowatts (kW), which is a more standardized unit of power expression internationally.
  • 1 horsepower (hp) is approximately equal to 0.746 kilowatts (kW).
  • Conversely, 1 kilowatt equals around 1.341 horsepower.
For students learning about power conversion, it’s crucial to become comfortable with converting between these units. In physics problems, ensuring the units match when inserted into equations is pivotal for accurate calculations. Always double-check that power is in the correct unit before proceeding with further calculations.
Rotational Speed
Rotational speed is a key factor in physics, particularly in mechanics where motion involves rotation around an axis, such as in engines.
It defines how fast an object spins and is usually measured in revolutions per minute (rev/min). However, in many physics calculations, rotational speed is required in radians per second (rad/s) to align with angular measurements.
This conversion uses the fact:
  • 1 revolution = 2Ï€ radians
  • 1 minute = 60 seconds
Therefore, converting rev/min to rad/s involves multiplying by \(\frac{2\pi}{60}\). For example, 1800 rev/min converts to 188.5 rad/s. Mastering this conversion is necessary to solve dynamic problems involving rotation efficiently.
Angular Velocity
Angular velocity, denoted by \(\omega\), is a vector quantity that represents the axis rotation speed of an object. It’s an essential concept in understanding rotational dynamics. Angular velocity is measured in radians per second (rad/s), and it helps in linking linear and rotational motions.
In situations where torque is exerted within a rotating system, such as engines, determining angular velocity provides insight into how rapidly the object rotates.
  • It helps to keep track of changes in rotation over time,
  • Is used in the formula for calculating torque from power: \( au = \frac{P}{\omega}\)
Understanding angular velocity's vector nature, with both magnitude and direction, clarifies how rotational speed impacts system stability and performance.
Physics Problem Solving
Physics problem solving often involves breaking down complex situations into more manageable parts. This approach is particularly crucial for exercises involving calculations like torque.
Let's examine a step-by-step method:
  • Identify the given information and what needs solving.
  • Conduct necessary unit conversions, such as power in kilowatts and rotational speed in radians per second.
  • Use appropriate formulas, such as \(P = \tau \omega\), which links power (\(P\)), torque (\(\tau\)) and angular velocity (\(\omega\)).
  • Solve for the unknown variable.
Additionally, confirming units are consistent throughout the calculation ensures that the solution is accurate. This systematic approach not only helps solve complex problems but also enhances understanding by illustrating the interconnectedness of physical concepts like power and rotational dynamics.

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Most popular questions from this chapter

A thin rod of length \(0.75 \mathrm{~m}\) and mass \(0.42 \mathrm{~kg}\) is suspended freely from one end. It is pulled to one side and then allowed to swing like a pendulum, passing through its lowest position with angular speed \(4.0 \mathrm{rad} / \mathrm{s}\). Neglecting friction and air resistance, find (a) the rod's kinetic energy at its lowest position and (b) how far above that position the center of mass rises.

A yo-yo-shaped device mounted on a horizontal frictionless axis is used to lift a 30 \(\mathrm{kg}\) box as shown in Fig. \(10-56\). The outer radius \(R\) of the device is \(0.50 \mathrm{~m}\), and the radius \(r\) of the hub is \(0.20 \mathrm{~m}\). When a constant horizontal force \(\vec{F}_{\text {app }}\) of magnitude \(140 \mathrm{~N}\) is applied to a rope wrapped around the outside of the device, the box, which is suspended from a rope wrapped around the hub, has an upward acceleration of magnitude \(0.80 \mathrm{~m} / \mathrm{s}^{2} .\) What is the rotational inertia of the device about its axis of rotation?

Trucks can be run on energy stored in a rotating flywheel, with an electric motor getting the flywheel up to its top speed of \(200 \pi \mathrm{rad} / \mathrm{s}\). One such flywheel is a solid, uniform cylinder with a mass of \(500 \mathrm{~kg}\) and a radius of \(1.0 \mathrm{~m} .\) (a) What is the kinetic energy of the flywheel after charging? (b) If the truck uses an average power of \(8.0 \mathrm{~kW}\), for how many minutes can it operate between chargings?

A record turntable is rotating at \(33 \frac{1}{3}\) rev/min. A watermelon seed is on the turntable \(6.0 \mathrm{~cm}\) from the axis of rotation. (a) Calculate the acceleration of the seed, assuming that it does not slip. (b) What is the minimum value of the coefficient of static friction between the seed and the turntable if the seed is not to slip? (c) Suppose that the turntable achieves its angular speed by starting from rest and undergoing a constant angular acceleration for \(0.25 \mathrm{~s}\). Calculate the minimum coefficient of static friction required for the seed not to slip during the acceleration period.

A small ball with mass \(1.30 \mathrm{~kg}\) is mounted on one end of a rod \(0.780 \mathrm{~m}\) long and of negligible mass. The system rotates in a horizontal circle about the other end of the rod at 5010 rev/min. (a) Calculate the rotational inertia of the system about the axis of rotation. (b) There is an air drag of \(2.30 \times 10^{-2} \mathrm{~N}\) on the ball, directed opposite its motion. What torque must be applied to the system to keep it rotating at constant speed?

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