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A small ball of mass \(0.75 \mathrm{~kg}\) is attached to one end of a 1.25-m-long massless rod, and the other end of the rod is hung from a pivot. When the resulting pendulum is \(30^{\circ}\) from the vertical, what is the magnitude of the gravitational torque calculated about the pivot?

Short Answer

Expert verified
The gravitational torque is approximately 4.59 N·m.

Step by step solution

01

Understand the Problem

We have a pendulum consisting of a ball of mass \(0.75\, \text{kg}\) attached to a massless rod of length \(1.25\, \text{m}\). The pendulum is displaced at an angle of \(30^{\circ}\) from the vertical. We need to find the gravitational torque at this angle about the pivot.
02

Define Torque Formula

Torque (\(\tau\)) is given by the formula:\[ \tau = r \cdot F \cdot \sin(\theta) \]where \(r\) is the distance from the pivot (radius), \(F\) is the force (in this case, the gravitational force), and \(\theta\) is the angle between the force direction and the line from the pivot to where the force is applied (30° in this situation).
03

Calculate the Gravitational Force

The gravitational force \(F\) is the weight of the ball, calculated using:\[ F = m \cdot g \]where \(m = 0.75\, \text{kg}\) and \(g = 9.8\, \text{m/s}^2\) (acceleration due to gravity). So,\[ F = 0.75 \times 9.8 = 7.35 \text{ N} \]
04

Substitute Values into Torque Equation

Substitute the known values into the torque equation:\[ \tau = 1.25 \times 7.35 \times \sin(30^{\circ}) \]Since \(\sin(30^{\circ}) = 0.5\), the equation becomes:\[ \tau = 1.25 \times 7.35 \times 0.5 \]
05

Calculate Torque

Compute the torque:\[ \tau = 1.25 \times 7.35 \times 0.5 = 4.59375 \text{ N} \cdot \text{m} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Force
Gravitational force is a fundamental force that pulls objects with mass toward each other. In the context of our pendulum exercise, the gravitational force acts downward towards the Earth, pulling the ball at the end of the pendulum rod. This force is mathematically expressed using the equation:\[ F = m \cdot g \]where \( F \) is the gravitational force, \( m \) is the mass of the object, and \( g \) is the acceleration due to Earth's gravity, which is approximately \( 9.8 \, \text{m/s}^2 \). In our example, with a ball of mass \( 0.75 \, \text{kg} \), the gravitational force is calculated as \( 7.35 \, \text{N} \).This gravitational force is essential as it contributes to the torque experienced by the pendulum as it swings. Understanding gravitational force not only helps in calculating torque but also in understanding many phenomena around us, from keeping planets in orbit to the motion of objects on Earth.
It is a key concept that underpins much of classical physics.
Pendulum Motion
Pendulum motion is a classic example of harmonic motion, where the movement of the pendulum is repetitive and oscillates around an equilibrium point. When you displace a pendulum and release it, it swings back and forth due to the gravitational force acting on it and the tension in the rod.Key aspects of pendulum motion include:
  • The restoring force which is the component of gravitational force that acts perpendicular to the rod.
  • The constant exchange between potential and kinetic energy, which allows the pendulum to keep moving once set in motion.
The pendulum's behavior is affected by several factors, such as the length of the rod and gravitational force. The length of the pendulum affects its period, which is the time taken for one complete cycle of the motion. The period \( T \) is given by:\[ T = 2\pi \sqrt{\frac{L}{g}} \]where \( L \) is the length of the pendulum and \( g \) is the gravitational acceleration. Understanding these principles can help visualize how a pendulum works, crucial for solving problems involving motion and forces in the system.
Angle of Displacement
The angle of displacement refers to the angle between the pendulum rod and the vertical line when the pendulum is at rest. It's a critical component in calculating torque and understanding pendulum motion.The displacement angle influences:
  • The component of the gravitational force that contributes to the movement of the pendulum.
  • The results of the torque calculation, as torque depends on the sine of this angle.
In the exercise, the pendulum is displaced by \( 30^{\circ} \) from the vertical. This angle impacts the gravitational torque as the sine of the angle determines how much of the gravitational force contributes to the torque. Mathematically, the torque \( \tau \) is calculated using:\[ \tau = r \cdot F \cdot \sin(\theta) \]where \( r \) is the radius (or length of the rod), \( F \) is the gravitational force, and \( \theta \) is the displacement angle. The sine function \( \sin(30^{\circ}) = 0.5 \) drastically alters the torque produced. Being aware of the role of displacement angle allows for better grasp of how force and motion interact in pendulum systems.

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