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Calculate the rotational inertia of a wheel that has a kinetic energy of \(24400 \mathrm{~J}\) when rotating at \(602 \mathrm{rev} / \mathrm{min}\).

Short Answer

Expert verified
The rotational inertia of the wheel is approximately 12.27 kg·m².

Step by step solution

01

Convert Rotational Speed to Radians per Second

The rotational speed is given in revolutions per minute (rpm), which we need to convert to radians per second (rad/s). Given \(602 \text{ rev/min}\), the conversion is: 1 rev = \(2\pi\) radians\[ \omega = 602 \text{ rev/min} \times \frac{2\pi \text{ rad}}{1 \text{ rev}} \times \frac{1 \text{ min}}{60 \text{ s}} = \frac{602 \times 2\pi}{60} \text{ rad/s} \approx 63.052 \text{ rad/s} \]
02

Use the Kinetic Energy Formula for Rotation

The kinetic energy for a rotating object is given by the formula:\[ KE = \frac{1}{2} I \omega^2 \]where \(KE\) is the kinetic energy, \(I\) is the rotational inertia, and \(\omega\) is the angular velocity.
03

Solve for Rotational Inertia

Rearrange the formula from Step 2 to solve for \(I\):\[ I = \frac{2 \cdot KE}{\omega^2} \]Substitute the known values (\(KE = 24400 \text{ J}\) and \(\omega = 63.052 \text{ rad/s}\)):\[ I = \frac{2 \cdot 24400}{63.052^2} \approx \frac{48800}{3975.548} \approx 12.27 \text{ kg} \cdot \text{m}^2 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy in the context of rotational motion describes the energy an object possesses due to its rotation. It is given by the formula \[ KE = \frac{1}{2} I \omega^2 \]where \( KE \) is the kinetic energy, \( I \) is the rotational inertia, and \( \omega \) is the angular velocity. This formula is similar to the translational kinetic energy formula \( KE = \frac{1}{2} mv^2 \), but instead of mass \( m \) and velocity \( v \), it uses rotational inertia and angular velocity. In rotation, kinetic energy arises from the motion around a pivot or axis. Understanding this helps us analyze objects' energy aspects, whether spinning on an axis or moving along a path. Note that rotational kinetic energy is dependent on both how heavy the object is and how fast it spins.
Angular Velocity
Angular velocity is a measure of how quickly an object rotates around a specific point or axis. It is represented by \( \omega \) and typically measured in radians per second (rad/s). To understand angular velocity, consider it as the rotational equivalent of linear speed. Angular velocity
  • Relates to the number of radians an object turns through per unit of time.
  • Can be calculated by converting units from revolutions per minute (rpm) to radians per second, as each complete revolution is equivalent to \( 2\pi \) radians.
  • For example, to convert 602 rpm to rad/s, you use the formula:\[ \omega = 602 \text{ rev/min} \times \frac{2\pi \text{ rad}}{1 \text{ rev}} \times \frac{1 \text{ min}}{60 \text{ s}} \approx 63.052 \text{ rad/s} \]
Understanding angular velocity is crucial for problems involving rotating objects, as it plays a key role in determining other physical properties such as kinetic energy.
Conversion of Units
Conversion of units is an essential skill to correctly calculate physical properties like angular velocity, especially when dealing with rotational motion. Proper unit conversion ensures that calculations align with the formula's requirements and that final results have the correct dimensions.To convert units related to rotational motion, such as changing revolutions per minute to radians per second:
  • Recognize that each revolution equals \( 2\pi \) radians.
  • Convert minutes to seconds by using the conversion factor: 1 minute = 60 seconds.
  • Apply these conversion factors carefully to get the result in the desired units, such as:\[ \omega = 602 \text{ rev/min} \times \frac{2\pi \text{ rad}}{1 \text{ rev}} \times \frac{1 \text{ min}}{60 \text{ s}} \approx 63.052 \text{ rad/s}\]
Mastering the process of conversion helps prevent errors and enables correct application of physics concepts.
Rotational Motion
Rotational motion refers to the movement of an object around a central point or axis. Unlike linear motion, where an object moves along a straight path, rotational motion describes how an object turns or spins. This type of motion is common in many physical systems, from wheels and gears to planets orbiting stars.In rotational motion, several key concepts are important to understand:
  • **Rotational Inertia**: This is analogous to mass in translational motion. It measures an object's resistance to changes in its rotational state and depends on how mass is distributed relative to the axis of rotation.
  • **Angular Velocity**: Describes how fast an object rotates. It's directly linked with the rotational kinetic energy of the object.
  • **Kinetic Energy**: As explained earlier, it's the energy due to the rotation, given by \( KE = \frac{1}{2} I \omega^2 \).
Understanding these concepts allows us to analyze and predict the behavior of rotating systems efficiently. Whether designing machinery or studying physical phenomena, grasping the fundamentals of rotational motion is crucial.

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Most popular questions from this chapter

The flywheel of an engine is rotating at \(25.0 \mathrm{rad} / \mathrm{s}\). When the engine is turned off, the flywheel slows at a constant rate and stops in \(20.0 \mathrm{~s}\). Calculate (a) the angular acceleration of the flywheel, (b) the angle through which the flywheel rotates in stopping, and (c) the number of revolutions made by the flywheel in stopping.

A golf ball is launched at an angle of \(20^{\circ}\) to the horizontal, with a speed of \(60 \mathrm{~m} / \mathrm{s}\) and a rotation rate of \(90 \mathrm{rad} / \mathrm{s}\). Neglecting air drag, determine the number of revolutions the ball makes by the time it reaches maximum height.

The angular acceleration of a wheel is \(\alpha=6.0 t^{4}-4.0 t^{2}\), with \(\alpha\) in radians per second-squared and \(t\) in seconds. At time \(t=0\), the wheel has an angular velocity of \(+2.0 \mathrm{rad} / \mathrm{s}\) and an angular position of \(+1.0 \mathrm{rad}\). Write expressions for (a) the angular velocity \((\mathrm{rad} / \mathrm{s})\) and (b) the angular position (rad) as functions of time (s).

If a \(32.0 \mathrm{~N} \cdot \mathrm{m}\) torque on a wheel causes angular acceleration \(25.0 \mathrm{rad} / \mathrm{s}^{2}\), what is the wheel's rotational inertia?

A disk rotates about its central axis starting from rest and accelerates with constant angular acceleration. At one time it is rotating at \(10 \mathrm{rev} / \mathrm{s} ; 60\) revolutions later, its angular speed is \(15 \mathrm{rev} / \mathrm{s}\). Calculate (a) the angular acceleration, (b) the time required to complete the 60 revolutions, (c) the time required to reach the 10 rev/s angular speed, and (d) the number of revolutions from rest until the time the disk reaches the 10 rev/s angular speed.

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