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A \(4.0 \mathrm{~kg}\) mess kit sliding on a frictionless surface explodes into two \(2.0 \mathrm{~kg}\) parts: \(3.0 \mathrm{~m} / \mathrm{s},\) due north, and \(5.0 \mathrm{~m} / \mathrm{s}, 30^{\circ}\) north of cast. What is the original speed of the mess kit?

Short Answer

Expert verified
The original speed of the mess kit was 3.52 m/s.

Step by step solution

01

Understand the Conservation of Momentum

Because the mess kit is on a frictionless surface, momentum is conserved. This means that before the explosion, the total momentum of the system was equal to the total momentum after the explosion.
02

Define System and Original Momentum

Before the explosion, the entire mess kit with a mass of 4.0 kg was moving at some velocity \(v\) that we need to find. The initial momentum \(p_{initial}\) is calculated as \(4.0 \, \mathrm{kg} \times v\).
03

Calculate the Momentum After Explosion

After the explosion, we have two parts: one going due north (mass = 2.0 kg, velocity = 3.0 m/s) and another going 30° north of east (mass = 2.0 kg, velocity = 5.0 m/s). We will break these velocities into components and calculate the momentum for each.
04

Determine Component Momentum of Each Part

For the northern part (A):- Momentum north is \(p_{north,A} = 2.0 \, \mathrm{kg} \times 3.0 \, \mathrm{m/s} = 6.0 \, \mathrm{kg \, m/s}\).For the part going north of east (B):- Momentum north is \(p_{north,B} = 2.0 \, \mathrm{kg} \times 5.0 \, \mathrm{m/s} \times \sin(30^{\circ}) = 5.0 \, \mathrm{kg \, m/s}\).- Momentum east is \(p_{east,B} = 2.0 \, \mathrm{kg} \times 5.0 \, \mathrm{m/s} \times \cos(30^{\circ}) = 8.66 \, \mathrm{kg \, m/s}\).
05

Apply Conservation of Momentum on North-South Axis

The total momentum before and after the explosion in the north-south direction must be equal, therefore:\(4.0 \, \mathrm{kg} \times v_{y} = 6.0 \, \mathrm{kg \, m/s} + 5.0 \, \mathrm{kg \, m/s} = 11.0 \, \mathrm{kg \, m/s}\).This gives us \(v_{y} = \frac{11.0}{4.0} = 2.75 \, \mathrm{m/s}\).
06

Apply Conservation of Momentum on East-West Axis

Since there was no initial eastward momentum, the initial velocity in the east direction was zero, hence:\(4.0 \, \mathrm{kg} \times v_{x} = 8.66 \, \mathrm{kg \, m/s}\).This gives us \(v_{x} = \frac{8.66}{4.0} = 2.165 \, \mathrm{m/s}\) eastward.
07

Calculate Original Speed of the Mess Kit

The original speed \(v\) of the mess kit is the magnitude of the velocity vector \((v_{x}, v_{y})\).Hence,\[ v = \sqrt{(v_{x})^2 + (v_{y})^2} = \sqrt{(2.165)^2 + (2.75)^2} = 3.52 \, \mathrm{m/s}. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Frictionless Surface
A frictionless surface is an idealized concept that allows us to study the conservation of momentum without the complication of frictional forces acting against motion. In real-world applications, friction often plays a significant role. However, treating a surface as frictionless in physics problems allows us to focus solely on the fundamental principles of motion and momentum.
  • On a frictionless surface, objects move without resistance, maintaining their speed and direction unless acted upon by another force.
  • This scenario is especially helpful in illustrating the law of conservation of momentum because it eliminates external forces.
  • Applications range from ice skating, where friction is minimized, to celestial mechanics, like the movement of satellites in space.
In this specific exercise, the fact that the mess kit explodes on a frictionless surface is key. It ensures that the only changes in the system's momentum result from internal forces. No energy is lost to friction, so our calculations for the speed and direction post-explosion focus entirely on the conservation of momentum principle.
Momentum Components
When dealing with momentum, especially in two-dimensional motion, breaking down velocity into components can simplify calculations. Momentum is a vector quantity, having both magnitude and direction.
  • Breaking down velocities into components allows us to separately handle motions along perpendicular axes (commonly north-south and east-west).
  • This breakdown uses trigonometric functions: sine for the north-south component and cosine for the east-west component when dealing with angles.
  • In the exercise, two parts of the mess kit have components due to different directions: one to the north and the other at 30° north of east.
By calculating the momentum of each component separately, we ensure that we adhere to the conservation laws accurately. This approach facilitates finding the initial conditions before the explosion effectively.
Vector Magnitude
Vector magnitude is a crucial concept in physics, particularly when we need to determine the resultant vector from two or more components. After breaking velocities into components, we often need to find the original or resultant speed, which is a scalar value.
  • The magnitude of a vector is found using the Pythagorean theorem in a two-dimensional plane: \[ v = \sqrt{(v_{x})^2 + (v_{y})^2} \] where \(v_{x}\) and \(v_{y}\) are the velocity components along the east and north directions.
  • Finding this magnitude provides the overall speed of the object resulting from combining its directional movements.
  • In our exercise, after determining the velocity components separately, we use their vector magnitude to find the mess kit's initial speed.
This technique is essential in many physics problems where direction and magnitude need to be combined to form a complete picture of an object's motion.
Physics Problem Solving
Solving physics problems often requires a strategic approach that involves identifying known quantities, determining what needs to be calculated, and systematically applying relevant principles.
  • Begin by understanding the problem's context and identifying every piece of given information. In our case, it's the explosion of a mess kit into two masses on a frictionless surface.
  • Break down complex motions into simpler ones and use physics principles like the conservation of momentum to find unknowns.
  • Ensure calculations include all necessary components, such as considering vector components and using trigonometry when directions and angles are involved.
For this exercise, we systematically applied the conservation of momentum to each axis separately before combining these results to find the original speed. This methodical approach is standard practice in physics, ensuring solutions are meticulous and thorough.

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Most popular questions from this chapter

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