/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 128 A cue stick strikes a stationary... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A cue stick strikes a stationary pool ball, with an average force of 32 N over a time of \(14 \mathrm{~ms}\). If the ball has mass \(0.20 \mathrm{~kg}\), what speed does it have just after impact?

Short Answer

Expert verified
The speed of the pool ball just after the impact is 2.24 m/s.

Step by step solution

01

Understand the Problem

To find the speed of the pool ball just after impact, we can use the impulse-momentum theorem, which states that the impulse on an object is equal to the change in momentum of that object. Impulse is given by the product of force and time, and momentum change depends on the mass and velocity of the ball.
02

Calculate Impulse

Impulse (J) can be calculated using the formula:\[ J = F imes t \]Substitute the given values: Force \( F = 32 \text{ N} \) and time \( t = 14 \text{ ms} = 14 \times 10^{-3} \text{ s} \).\[ J = 32 \times 14 \times 10^{-3} \text{ Ns} \]\[ J = 0.448 \text{ Ns} \]
03

Use Impulse to Find Change in Momentum

Since the ball was initially stationary, the change in momentum \( \Delta p \) is equal to the impulse:\[ \Delta p = J = 0.448 \text{ kg m/s} \]
04

Relate Change in Momentum to Speed

According to the momentum formula, \( p = m \cdot v \), where \( p \) is momentum, \( m \) is mass, and \( v \) is velocity. If the ball's initial momentum was zero, then:\[ \Delta p = m \cdot v_f - 0 = m \cdot v_f \]\[ v_f = \frac{\Delta p}{m} \]
05

Calculate Final Speed

Substitute the values into the formula to calculate the final speed:\[ v_f = \frac{0.448}{0.20} \]\[ v_f = 2.24 \text{ m/s} \]
06

Conclusion

The speed of the pool ball just after impact is \(2.24 \text{ m/s}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Impulse
Impulse is a concept in physics that reflects the effect of a force acting over a period of time. When thinking about impulse, visualize a force pushing or pulling an object for some time, causing it to move. The longer the force acts or the stronger the force is, the greater the change in motion of the object. In technical terms, impulse is the product of a force (\( F \)) and the time duration (\( t \)) it acts, which can be expressed as:
  • Impulse (\( J \)) = Force (\( F \)) × Time (\( t \))
When a cue stick hits a pool ball as in our exercise, this action represents an impulse. The force applied by the stick over that brief moment when it contacts the ball results in the ball accelerating from rest. The impulse imparted by the cue stick is calculated as the change in momentum of the pool ball, which we determined using the formula above.
Impulse is a helpful way to quantify the effects of a force in a short amount of time.
Momentum
Momentum is a fundamental concept in physics, symbolized as (\( p \)), often described as the "quantity of motion" of an object. It's a product of an object's mass (\( m \)) and its velocity (\( v \)), given by:
  • Momentum (\( p \)) = Mass (\( m \)) × Velocity (\( v \))
The larger the mass or velocity, the greater the momentum. In our pool ball scenario, we see the importance of this concept. Initially, the ball is at rest, meaning its momentum is zero. Yet, when the impulse acts on the ball (represented by the force of the cue stick), its momentum changes. The change in momentum is exactly what's equal to the impulse.
Momentum also reflects the conservation laws in physics - in isolated systems, the total momentum remains constant. This conservation law helps in solving many real-world mechanics problems, including understanding collisions and impacts.
Newtonian Mechanics
Newtonian Mechanics, or classical mechanics, is the foundation of describing motion in physical systems. This field is based on Newton's three laws of motion, which explain how forces affect the movement of objects. Statements about forces like those in our exercise find their basis here.
Specifically, Newton's second law connects directly to our discussion of impulse and momentum. It states that the rate of change of momentum of an object is proportional to the applied force, which can be formulated as:
  • Force (\( F \)) = Change in Momentum (\( \Delta p \)) / Change in Time (\( \Delta t \))
To see this connection to impulse, we multiply the force by the change in time to yield Impulse:
  • Impulse (\( J \)) = Force (\( F \)) × Time (\( t \))
These classical principles laid down by Newton explain the cue stick's effect on the pool ball in our given problem.
Comprehending these mechanics concepts ensures that students can accurately predict how objects behave under various forces, facilitating the solving of many practical physics problems.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A body of mass \(2.0 \mathrm{~kg}\) makes an clastic collision with another body at rest and continues to move in the original direction but with one-fourth of its original speed. (a) What is the mass of the other body? (b) What is the speed of the two-body center of mass if the initial speed of the \(2.0 \mathrm{~kg}\) body was \(4.0 \mathrm{~m} / \mathrm{s} ?\)

In a game of pool, the cue ball strikes another ball of the same mass and initially at rest. After the collision, the cue ball moves at \(3.50 \mathrm{~m} / \mathrm{s}\) along a line making an angle of \(22.0^{\circ}\) with the cue ball's original direction of motion, and the second ball has a speed of \(2.00 \mathrm{~m} / \mathrm{s}\). Find (a) the angle between the direction of motion of the second ball and the original direction of motion of the cue ball and (b) the original speed of the cue ball. (c) Is kinetic energy (of the centers of mass, don't consider the rotation) conserved?

two identical containers of sugar are connected by a cord that passes over a frictionless pulley. The cord and pulley have negligible mass, each container and its sugar together have a mass of \(500 \mathrm{~g}\), the centers of the containers are separated by \(50 \mathrm{~mm}\), and the containers are held fixed at the same height. What is the horizontal distance between the center of container 1 and the center of mass of the two-container system (a) initially and (b) after \(20 \mathrm{~g}\) of sugar is transferred from container 1 to container \(2 ?\) After the transfer and after the containers are released, (c) in what direction and (d) at what acceleration magnitude does the center of mass move?

A \(1400 \mathrm{~kg}\) car moving at \(5.3 \mathrm{~m} / \mathrm{s}\) is initially traveling north along the positive direction of a \(y\) axis. After completing a \(90^{\circ}\) right-hand turn in \(4.6 \mathrm{~s}\), the inattentive operator drives into a tree, which stops the car in \(350 \mathrm{~ms}\). In unit-vector notation, what is the impulse on the car (a) due to the turn and (b) due to the collision? What is the magnitude of the average force that acts on the car (c) during the turn and (d) during the collision? (e) What is the direction of the average force during the turn?

Block 1 of mass \(m_{1}\) slides along a frictionless floor and into a one- dimensional elastic collision with stationary block 2 of mass \(m_{2}=3 m_{1}\). Prior to the collision, the center of mass of the two-block system had a speed of \(3.00 \mathrm{~m} / \mathrm{s}\). Afterward, what are the speeds of (a) the center of mass and (b) block \(2 ?\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.