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A \(140 \mathrm{~g}\) ball with speed \(7.8 \mathrm{~m} / \mathrm{s}\) strikes a wall perpendicularly and rebounds in the opposite direction with the same speed. The collision lasts \(3.80 \mathrm{~ms}\). What are the magnitudes of the (a) impulse and (b) average force on the wall from the ball during the elastic collision?

Short Answer

Expert verified
Impulse: 2.184 Ns, Average Force: 574.74 N.

Step by step solution

01

Understand Impulse Formula

Impulse is defined as the change in momentum of an object when a force is applied over a specific time interval. The formula for impulse (\( J \)) is given by \( J = \Delta p = m(v_f - v_i) \), where \( m \) is the mass, \( v_f \) is the final velocity, and \( v_i \) is the initial velocity.
02

Calculate Change in Velocity

Since the ball rebounds with the same speed in the opposite direction, we need to account for the change in direction when calculating velocity. The initial velocity \( v_i = 7.8 \, \text{m/s} \) and the final velocity \( v_f = -7.8 \, \text{m/s} \). Thus, the change in velocity is \( v_f - v_i = -7.8 - 7.8 = -15.6 \, \text{m/s} \).
03

Find Impulse

Using the impulse formula, substitute the given values: \( m = 0.140 \, \text{kg} \), and change in velocity \( \Delta v = -15.6 \, \text{m/s} \). Therefore, \( J = 0.140 \, \text{kg} \times (-15.6 \, \text{m/s}) = -2.184 \, \text{Ns} \). Since impulse is a vector, its magnitude is \( 2.184 \, \text{Ns} \).
04

Convert Time Units

The collision duration is provided in milliseconds: \( t = 3.80 \, \text{ms} = 3.80 \, \text{ms} \times \frac{1\, \text{s}}{1000 \, \text{ms}} = 0.0038 \, \text{s} \).
05

Calculate Average Force

Average force is found using the formula \( F_{avg} = \frac{J}{t} \). We have \( J = 2.184 \, \text{Ns} \) and \( t = 0.0038 \, \text{s} \). Thus, \( F_{avg} = \frac{2.184}{0.0038} \approx 574.74 \, \text{N} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum
Momentum is a fundamental concept in physics, describing the quantity of motion an object possesses. It is given by the product of an object's mass and its velocity: \( p = m imes v \). Here, \( p \) is momentum, \( m \) is mass, and \( v \) is velocity. Momentum is a vector quantity, which means it has both magnitude and direction.

In the scenario of the ball striking the wall, we calculate the initial and final momentum of the ball. Since it changes direction while maintaining the same speed, there's a significant change in momentum. This change in momentum, from moving towards the wall to moving away, is a crucial component in our calculations of impulse. The formula for change in momentum \( \Delta p \) is therefore: \( \Delta p = m(v_f - v_i) \).

Understanding momentum provides insights into how forces interact with objects over time. It illustrates why massive objects moving at high speeds have more momentum and require more effort to stop compared to lighter, slower-moving objects.
Average Force
The average force exerted during a collision is not static but is calculated over the time duration of interaction. It provides a means to quantify the effect of a force over finite time intervals rather than instantaneous points.

For our ball, once we have calculated the impulse—which is the change in momentum of the ball, \( J = \Delta p \)—we can use it to determine the average force \( F_{avg} \). The formula to find average force is:
  • \( F_{avg} = \frac{J}{t} \)
where \( t \) is the time duration of the collision. In this case, the impulse is known, having a magnitude of \( 2.184 \, \text{Ns} \), and with a collision time of \( 0.0038 \, \text{s} \), we calculate the average force exerted on the wall to be \( 574.74 \, \text{N} \).

This concept of average force is indispensable for understanding the practicality of how forces are applied in real-world, non-instantaneous events. It helps engineers and physicists design systems where force application needs to be controlled, such as in car crash safety designs.
Collision
A collision refers to an event where two or more bodies exert forces on each other for a short duration. In physics, collisions are generally categorized based on energy conservation: elastic, inelastic, and perfectly inelastic.

In the given scenario, the ball experiences an elastic collision with the wall. This means the kinetic energy of the ball is conserved even after hitting and rebounding from the wall. Here, the ball's velocity is reversed but its magnitude remains the same, signifying no loss of kinetic energy to heat or deformation.

During such collisions:
  • Momentum before and after is conserved.
  • The velocity change is central to the concept of impulse.
Through analyzing these collision events, one can better understand physical interactions and how forces transform through instantaneous, high-impact occurrences that characterize collisions seen in sports, vehicle impacts, and more.

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Most popular questions from this chapter

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