/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 A pendulum consists of a \(2.0 \... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A pendulum consists of a \(2.0 \mathrm{~kg}\) stone swinging on a \(4.0 \mathrm{~m}\) string of negligible mass. The stone has a speed of \(8.0 \mathrm{~m} / \mathrm{s}\) when it passes its lowest point. (a) What is the speed when the string is at \(60^{\circ}\) to the vertical? (b) What is the greatest angle with the vertical that the string will reach during the stone's motion? (c) If the potential energy of the pendulum-Earth system is taken to be zero at the stone's lowest point, what is the total mechanical energy of the system?

Short Answer

Expert verified
(a) Speed at 60° is approximately 4.98 m/s. (b) Maximum angle is about 79.5°. (c) Total mechanical energy is 64.0 J.

Step by step solution

01

Understand the Problem

We have a stone of mass \(2.0\, \mathrm{kg}\) attached to a string of length \(4.0\, \mathrm{m}\). At its lowest point, the stone moves at \(8.0\, \mathrm{m/s}\). We need to determine the speed at \(60^{\circ}\), the maximum angle, and the total mechanical energy, considering potential energy zero at the lowest point.
02

Calculate Total Mechanical Energy

The total mechanical energy at the lowest point is purely kinetic since potential energy is zero there. Use the kinetic energy formula:\[ KE = \frac{1}{2}mv^2 \]Substitute \(m = 2.0\, \mathrm{kg}\) and \(v = 8.0\, \mathrm{m/s}\):\[ KE = \frac{1}{2} \times 2.0 \times 8.0^2 = 64.0 \mathrm{~J} \]Thus, the total mechanical energy \(E\) of the system is \(64.0\, \mathrm{J}\).
03

Find Speed at 60 Degrees

At \(60^{\circ}\), mechanical energy is conserved. Total energy \(E\) is the sum of kinetic and potential energy:\[ E = KE + PE = \frac{1}{2}mv^2 + mgh \]Height \(h\) at \(60^{\circ}\) can be found using \(h = L - L\cos\theta = 4.0 - 4.0\cos(60^{\circ}) = 2.0\, \mathrm{m}\). Calculate potential energy:\[ PE = mgh = 2.0 \times 9.8 \times 2.0 = 39.2 \mathrm{~J} \]Using \(E = 64.0\, \mathrm{J}\):\[ 64.0 = \frac{1}{2}mv^2 + 39.2 \]Solve for \(v\):\[ \frac{1}{2} \times 2.0 \times v^2 = 24.8 \Rightarrow v^2 = 24.8 \Rightarrow v = \sqrt{24.8} \approx 4.98 \, \mathrm{m/s} \]
04

Determine Maximum Angle

At the maximum swing, all mechanical energy is potential (kinetic energy is zero). Thus:\[ E = mgh_{max} \]Using \(E = 64.0\, \mathrm{J}\):\[ 64.0 = 2.0 \times 9.8 \times h_{max} \Rightarrow h_{max} = \frac{64.0}{19.6} \approx 3.27 \, \mathrm{m} \]\(h_{max} = L - L\cos\theta_{max}\), solve for \(\theta_{max}\):\[ 3.27 = 4.0 - 4.0\cos\theta_{max} \Rightarrow \cos\theta_{max} = 0.1825 \]Thus, \(\theta_{max} = \cos^{-1}(0.1825) \approx 79.5^{\circ}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mechanical Energy
Mechanical energy in a pendulum consists of both potential and kinetic energy. It stays constant as long as no energy is lost to air resistance or friction. In the pendulum system from our exercise, this mechanical energy includes the energy transformations between the kinetic energy of the moving stone and the potential energy we observe when the stone is elevated.
As the stone swings from its lowest point to a higher position, its speed decreases. This decrease occurs because some of the kinetic energy is converted into potential energy, rising the stone against the gravitational pull. When the pendulum falls back into its swing, the stored potential energy gets transformed back into kinetic energy, increasing speed.
  • Total mechanical energy at the lowest point is purely kinetic.
  • At any point in the pendulum's swing, mechanical energy is the sum of kinetic and potential energy.
Understanding how energy transfers work within a pendulum helps you comprehend more complex systems involving mechanical energy. It’s essential as mechanical energy principles are applicable in many real-world scenarios and technologies.
Kinetic Energy
Kinetic energy describes the energy of motion. For the pendulum, its maximum kinetic energy is at the lowest point in its path. This is when it's moving the fastest.
You can calculate kinetic energy using the formula:\[ KE = \frac{1}{2} m v^2 \]Here, "m" is your mass (in kilograms), and "v" is velocity (in meters per second). When the stone is at its lowest and fastest point, it has maximum kinetic energy, which in this exercise is 64 Joules.
When the pendulum reaches any other point, part of this kinetic energy translates into potential energy as it climbs up. Even at the angle of 60 degrees, the pendulum will still possess kinetic energy, just reduced because some of it converted into height (potential energy).
These principles enable us to predict the pendulum's speed at different points of its motion. It's an insight into why things slow down as they move up against gravity, essential in designing things that move, like cars or sports equipment.
Potential Energy
Potential energy represents the stored energy of position, particularly the potential to do work owing to an object's height. In a pendulum, it's zero at the lowest point—the reference height where potential energy transforms into kinetic energy fully. But as you raise the pendulum, potential energy builds.
Let's look at how it's calculated:\[ PE = mgh \]Where "m" is mass, "g" is the acceleration due to gravity (approximately 9.8 m/s²), and "h" is height above the reference point. At 60 degrees, the pendulum gains potential energy by increasing its height. In our exercise, this height is calculated using trigonometry: 2 meters from the lowest point. Therefore, potential energy becomes 39.2 Joules here.
  • Potential energy increases with height.
  • It becomes maximum when kinetic energy falls to zero at the pendulum's highest swing point.
Grasping how potential energy works give insight into systems storing energy in positions—think of a clock's weight or the water in a high reservoir. It's the framework for understanding energy exchanges and transformations everywhere.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A \(70.0 \mathrm{~kg}\) man jumping from a window lands in an elevated fire rescue net \(11.0 \mathrm{~m}\) below the window. He momentarily stops when he has stretched the net by \(1.50 \mathrm{~m}\). Assuming that mechanical energy is conserved during this process and that the net functions like an ideal spring, find the elastic potential energy of the net when it is stretched by \(1.50 \mathrm{~m}\).

A river descends \(15 \mathrm{~m}\) through rapids. The speed of the water is \(3.2 \mathrm{~m} / \mathrm{s}\) upon entering the rapids and \(13 \mathrm{~m} / \mathrm{s}\) upon leaving. What percentage of the gravitational potential energy of the water-Earth system is transferred to kinetic energy during the descent? (Hint: Consider the descent of, say, \(10 \mathrm{~kg}\) of water.)

A \(5.0 \mathrm{~g}\) marble is fired vertically upward using a spring gun. The spring must be compressed \(8.0 \mathrm{~cm}\) if the marble is to just reach a target \(20 \mathrm{~m}\) above the marble's position on the compressed spring. (a) What is the change \(\Delta U_{g}\) in the gravitational potential energy of the marble-Earth system during the \(20 \mathrm{~m}\) ascent? (b) What is the change \(\Delta U_{s}\) in the elastic potential energy of the spring during its launch of the marble? (c) What is the spring constant of the spring?

110 A \(5.0 \mathrm{~kg}\) block is projected at \(5.0 \mathrm{~m} / \mathrm{s}\) up a plane that is inclined at \(30^{\circ}\) with the horizontal. How far up along the plane does the block go (a) if the plane is frictionless and (b) if the coefficient of kinetic friction between the block and the plane is \(0.40 ?\) (c) In the latter case, what is the increase in thermal energy of block and plane during the block's ascent? (d) If the block then slides back down against the frictional force, what is the block's speed when it reaches the original projection point?

A \(70 \mathrm{~kg}\) firefighter slides, from rest, \(4.3 \mathrm{~m}\) down a vertical pole. (a) If the firefighter holds onto the pole lightly, so that the frictional force of the pole on her is negligible, what is her speed just before reaching the ground floor? (b) If the firefighter grasps the pole more firmly as she slides, so that the average frictional force of the pole on her is \(500 \mathrm{~N}\) upward, what is her speed just before reaching the ground floor?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.