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A certain string can withstand a maximum tension of \(40 \mathrm{~N}\) without breaking. A child ties a \(0.37 \mathrm{~kg}\) stone to one end and, holding the other end, whirls the stone in a vertical circle of radius 0.91 \(\mathrm{m},\) slowly increasing the speed until the string breaks. (a) Where is the stone on its path when the string breaks? (b) What is the speed of the stone as the string breaks?

Short Answer

Expert verified
(a) At the bottom of the path. (b) Approximately 9.46 m/s.

Step by step solution

01

Analyze forces in the vertical circle

When the stone is moving in a vertical circle, the tension in the string is highest at the bottom of the path, because it has to support both the centripetal force and the weight of the stone. At the top, the tension is reduced because gravity also provides centripetal force. Therefore, the string most likely breaks when the stone is at the bottom of its path where the tension is maximum.
02

Calculate the tension at the bottom of the path

At the bottom of the path, the tension can be expressed by the equation: \[ T = m imes g + m imes \frac{v^2}{r} \] where \(T\) is tension, \(m\) is mass of the stone, \(g\) is the acceleration due to gravity \((9.8 \, m/s^2)\), \(v\) is the stone's speed, and \(r\) is the radius of the circle. Inserting the given values:\[ 40 = 0.37 imes 9.8 + 0.37 \times \frac{v^2}{0.91} \]
03

Solve for the stone's speed at maximum tension

Solving the equation for \(v\) involves isolating \(v\) on one side of the equation:\[ 40 = 3.626 + 0.406593 \, v^2 \]Subtract 3.626 from both sides: \[ 36.374 = 0.406593 \, v^2 \]Next, divide both sides by 0.406593: \[ v^2 = \frac{36.374}{0.406593} \approx 89.512 \]Finally, take the square root of both sides:\[ v \approx \sqrt{89.512} \approx 9.46 \, m/s \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tension in a String
When dealing with circular motion, understanding the tension in the string is crucial. Tension is a force that is exerted along the string and holds the object in motion within the constraints of that string. In this scenario, the stone tied to a string experiences tension as it is whirled in a circle.
The tension varies depending on the position of the stone along its path. The critical thing to note is that the string must be strong enough to not break. This is determined by the maximum tension the string can withstand, which in this case is 40 Newtons.
At different points along the vertical path, the forces acting against the string include:
  • The stone's weight, which pulls downwards due to gravity.
  • The centripetal force required to keep the stone moving in a circle, which pulls towards the center of the path.
It's important to analyze how these forces affect tension at key points—particularly the top and bottom of the circle—where gravitational force influences it differently. Knowing when the maximum tension occurs can help predict when a string might break, which typically happens at the bottom of the circle where tension is highest due to the combined effect of weight and centripetal force.
Vertical Circle Dynamics
The dynamics of an object moving in a vertical circle involve understanding how forces, speed, and motion interact. When a stone is swung in a vertical circle, several forces are at play. These forces include gravitational force, tension, and the inherent centripetal force needed to maintain the stone in its circular path.
Interestingly, the dynamics differ as the stone travels from the top of the circle to the bottom:
  • At the top of the circle, gravity helps provide the centripetal force, thereby reducing the need for tension in the string.
  • Conversely, at the bottom of the circle, tension must counteract gravity and provide the necessary centripetal force to keep the stone moving along the circle.
Understanding these dynamics is essential for predicting the motion pattern of the stone. This also helps in identifying the stress points in the string, which are crucial for determining when the string might break under increased speed.
Centripetal Force
Centripetal force is central to keeping any object moving in a circular path. It is directed toward the center of the circle and is necessary for maintaining circular motion. The absence of sufficient centripetal force will result in the object moving off in a tangent rather than adhering to the circle.
Several factors influence the centripetal force:
  • The mass of the object (in this case, the stone).
  • The speed at which the object is moving.
  • The radius of the circle, with a smaller radius requiring greater centripetal force to maintain the same speed.
In mathematical terms, centripetal force (\[ F_c \]) can be expressed as: \[ F_c = \frac{m \cdot v^2}{r} \] where \( m \) represents mass, \( v \) is speed, and \( r \) is the radius.
In the given exercise, analyzing the centripetal force helps in determining how much speed can be increased before the tension in the string exceeds the maximum it can withstand, hence causing it to break.

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Most popular questions from this chapter

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