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A \(10 \mathrm{~kg}\) monkey climbs up a massless rope that runs over a frictionless tree limb and back down to a \(15 \mathrm{~kg}\) package on the ground (Fig. 5-54). (a) What is the magnitude of the least acceleration the monkey must have if it is to lift the package off the ground? If, after the package has been lifted, the monkey stops its climb and holds onto the rope, what are the (b) magnitude and (c) direction of the monkey's acceleration and (d) the tension in the rope?

Short Answer

Expert verified
(a) 4.9 m/s²; (b) 1.96 m/s²; (c) Downward; (d) 78.4 N

Step by step solution

01

Understand the System

The monkey and the package are connected by a rope over a frictionless limb. The monkey must climb the rope to lift the package off the ground.
02

Analyze Forces on the Monkey and Package

For the monkey with mass 10 kg, the force due to gravity is \(F_m = m_m g = 10 \times 9.8 = 98 \text{ N}\). For the package with mass 15 kg, the gravitational force is \(F_p = m_p g = 15 \times 9.8 = 147 \text{ N}\).
03

Calculate Minimum Acceleration (a)

To lift the package, the monkey must exert a force greater than 147 N. The difference in forces, given by the minimum net force required, is \(F = m_p \times a - m_m \times g\), which simplifies to \(a = \frac{147 - 98}{10} = 4.9 \text{ m/s}^2\).
04

Determine System Behavior Once Package is Lifted

If the package is lifted and the monkey stops climbing, the net force is zero because both objects will accelerate together.
05

Calculate Monkey's Acceleration (b and c)

When the monkey stops, both the monkey and package move under the same force of gravity pulling them. Both will accelerate at the effective acceleration given by the larger mass: \(a' = \frac{(m_p - m_m) \times g}{m_p + m_m} = \frac{(15-10) \times 9.8}{15+10} = 1.96\text{ m/s}^2\). The acceleration is downward.
06

Calculate Tension in the Rope (d)

With acceleration of both objects, the tension can be found by either object. For the monkey, tension \(T = m_m(g + a') = 10(9.8-1.96) = 78.4\text{ N}\). This is the tension in the rope.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force and Acceleration
Force and acceleration are crucial concepts in understanding how objects move. According to Newton's Second Law of Motion, the force exerted on an object is directly proportional to the acceleration of the object and is dependent on the mass of the object. This is expressed with the formula: \[ F = m imes a \] where \( F \) is the force in newtons, \( m \) is the mass in kilograms, and \( a \) is the acceleration in meters per second squared. In the situation with the monkey and the package, force and acceleration play an essential role. The monkey must apply a force greater than the gravitational force on the package to lift it. Here, the minimum force needed for the monkey to accelerate upwards and lift the package is determined by the difference in gravitational forces between the monkey and the package. Given that the monkey's mass is 10 kg and the package's mass is 15 kg, the required upward force results in a calculation for minimum acceleration. This ensures the package is lifted off the ground, emphasizing the direct relationship between force, mass, and acceleration.
Tension in a Rope
Tension is a force exerted along a rope or string when it is pulled tight by forces acting from each end. It is crucial to understand that tension is the same throughout a rope if the rope is massless and there is no friction. This consistency makes calculations simpler. For the monkey climbing the rope, tension is an important factor. Initially, while climbing, the monkey creates tension due to the force of its weight and additional force needed for acceleration. Once the package is lifted, and if the monkey stops climbing, the entire system of the monkey, rope, and package becomes a scenario of balanced forces. When equilibrium is reached, the tension in the rope equates to the force exerted by the weight of the monkey minus any net acceleration. When the monkey stops after lifting the package, the effective acceleration leads to tension that reflects gravitational pull on both, and this can be calculated as described in the exercise solution. Hence, tension is carefully balanced with gravitational forces and any additional movement by the monkey.
Gravitational Force
Gravitational force is the force with which the earth attracts a body towards its center. It plays a pivotal role in various physics problems, especially those involving vertical motion, like this one. The force of gravity acting on an object is calculated using the formula: \[ F_g = m imes g \] where \( F_g \) is the gravitational force, \( m \) is the mass, and \( g \) is the acceleration due to gravity, approximately \( 9.8 \, \text{m/s}^2 \) on the surface of the earth.In the context of the monkey and the package, gravitational force acts downward on both. The monkey, weighing 10 kg, experiences a gravitational force of 98 N, while the heavier package, at 15 kg, undergoes 147 N of gravitational pull. Understanding these forces allows us to calculate necessary actions to counteract gravity, like the monkey's acceleration and tension in the rope, to lift the package off the ground. Gravitational force thus sets a baseline that the monkey must overcome to achieve upward motion.

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Most popular questions from this chapter

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