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An elevator cab that weighs \(27.8 \mathrm{kN}\) moves upward. What is the tension in the cable if the cab's speed is (a) increasing at a rate of \(1.22 \mathrm{~m} / \mathrm{s}^{2}\) and \((\mathrm{b})\) decreasing at a rate of \(1.22 \mathrm{~m} / \mathrm{s}^{2} ?\)

Short Answer

Expert verified
(a) 31,258.8 N; (b) 24,341.2 N.

Step by step solution

01

Understand the Problem

We need to find the tension in the cable of an elevator that moves upward. There are two scenarios: (a) the speed of the elevator is increasing, and (b) the speed of the elevator is decreasing.
02

Define Known Variables

Given: \( W = 27.8 \text{kN} = 27,800\, \text{N} \) (weight of the elevator in newtons), \( a = 1.22 \, \text{m/s}^2 \) (acceleration).
03

Set Up the Free Body Diagram

For an upward-moving elevator:- when speed increases, tension \( T \) is greater than weight \( W \). - when speed decreases, tension \( T \) is less than weight \( W \).
04

Calculate Tension for Increasing Speed

For the elevator moving upward with increasing speed:The net force (\( F_{net} \)) is given by \( F_{net} = T - W \). Thus, \( T = W + ma \).Here, \( m = \frac{W}{g} = \frac{27,800 \text{ N}}{9.8 \text{ m/s}^2} \). Substitute the given values:\[ T = 27,800 + \left( \frac{27,800}{9.8} \right) \times 1.22 \]Solve for \( T \).
05

Calculate Tension for Decreasing Speed

For decreasing speed:The equation is \( F_{net} = T - W = -ma \) which results in \( T = W - ma \).Using the same calculation for mass:\[ T = 27,800 - \left( \frac{27,800}{9.8} \right) \times 1.22 \]Solve for \( T \).
06

Solve for Mass and Final Tension Values

First, calculate total mass: \( m = \frac{27,800}{9.8} = 2836.73 \text{ kg} \).For increasing speed:\[ T = 27,800 + 2836.73 \times 1.22 = 31,258.8 \text{ N} \]For decreasing speed:\[ T = 27,800 - 2836.73 \times 1.22 = 24,341.2 \text{ N} \]
07

Review and Interpret

For the scenario where the elevator's speed is increasing, the tension in the cable is greater because it must counteract gravity and provide the extra force to accelerate upward. Conversely, if the speed is decreasing, the tension needed is less than the elevator's weight since gravity aids the acceleration downwards.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Elevator Physics
When we think about elevators, we often picture the smooth start and stop as we ascend or descend floors in a building. This experience is not just about the mechanical movement of the elevator; it involves principles of physics. To understand elevator physics, we should look at how forces interact with the elevator cab.
There are two main forces at play:
  • The tension in the cable that pulls the elevator upward.
  • The gravitational force or weight that pulls it downward.
When an elevator changes speed or direction, it experiences acceleration. The resulting tension in the cable differs based on whether the elevator is speeding up or slowing down.
This basic understanding of forces helps us explore the principles governing elevator dynamics, especially how tension in the cable is determined.
Newton's Second Law
Newton's Second Law of Motion is a key principle in understanding the motion of objects, including elevators. The law states that the force acting on an object is equal to the mass of the object multiplied by its acceleration \[ F = ma \]. This principle helps us understand how different forces contribute to the elevator's motion.
In the context of the exercise, the formula is adjusted to determine tension in the cable. When the elevator is speeding up, the tension force ( \( T \) ) is expressed as the sum of the elevator's weight ( \( W \) ) and the product of mass and acceleration ( \( ma \) ) because both forces add up in the same direction:\[ T = W + ma \].
On the other hand, when the elevator slows down, the gravitational force works opposite to the tension,which reduces the tension required, given by: \[ T = W - ma \].
This straightforward principle becomes very handy in calculating cable tension during elevator rides.
Free Body Diagram
A free body diagram is a simple sketch that shows all the forces acting on an object. It’s a powerful tool to visualize and solve physics problems! For the elevator problem, the free body diagram helps us understand how the different forces—tension and weight—act on the cab.
When creating a free body diagram for an elevator:
  • Draw the elevator cab as a box.
  • Arrow one pointing upwards depicts the tension force (T) from the cable.
  • Arrow two pointing downwards represents the gravitational force or weight (W).
The length and direction of these arrows convey the magnitude and direction of forces. By analyzing the diagram, you can see how tension balances and counteracts weight depending on the situation—whether the elevator is accelerating upward or decelerating.
This visual representation makes it easier to apply Newton’s Second Law to solve for unknowns like tension.
Acceleration and Velocity
Acceleration and velocity are two core concepts in motion. Understanding them is crucial for interpreting elevator dynamics.
Acceleration is the rate at which velocity changes over time. In an elevator:
  • If the cab's speed is increasing, we say it has positive acceleration.
  • When speed decreases, that's a negative acceleration or deceleration.
Velocity, on the other hand, refers to the speed of the elevator in a specific direction.
In our exercise: - The cab moving upward with increasing speed means higher tension in the cable, since it must overcome gravity and add additional force. - But if it's slowing down while moving upward, gravity assists the change, so less tension is needed compared to the cab’s weight.
By considering both acceleration and velocity, we gain a deeper understanding of how forces like tension and gravity interact with moving objects.

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