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A laser emits at \(424 \mathrm{nm}\) in a single pulse that lasts \(0.500 \mu \mathrm{s}\). The power of the pulse is \(2.80 \mathrm{MW}\). If we assume that the atoms contributing to the pulse underwent stimulated emission only once during the \(0.500 \mu \mathrm{s}\), how many atoms contributed?

Short Answer

Expert verified
Approximately 2.13 trillion atoms contributed to the pulse.

Step by step solution

01

Determine Energy of a Single Photon

The energy of a photon is given by the formula \( E = \frac{h c}{\lambda} \), where \( h \) is Planck's constant \( 6.626 \times 10^{-34} \text{ J s} \), \( c \) is the speed of light \( 3.00 \times 10^8 \text{ m/s} \), and \( \lambda \) is the wavelength \( 424 \text{ nm} = 424 \times 10^{-9} \text{ m} \). Substitute these values into the equation to find the energy of a single photon.
02

Calculate Total Energy of the Pulse

The power of the pulse is given as \( 2.80 \text{ MW} = 2.80 \times 10^6 \text{ W} \). Power is energy per unit time, so the total energy of the pulse is \( E_{\text{total}} = \text{Power} \times \text{time} = 2.80 \times 10^6 \text{ W} \times 0.500 \times 10^{-6} \text{ s} \). Calculate this to find the total energy output of the laser pulse.
03

Calculate the Number of Photons

Using the energy of a single photon from Step 1 and the total energy of the pulse from Step 2, compute the number of photons by dividing \( E_{\text{total}} \) by \( E \). The number of photons \( N \) is given by \( N = \frac{E_{\text{total}}}{E} \).
04

Relate the Number of Photons to Atoms

Assuming each photon corresponds to a single stimulated emission event by an atom (as the problem states that each atom contributes a photon), the number of atoms is equal to the number of photons calculated in Step 3.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Photon Energy
Photon energy is a fundamental concept in laser physics, playing a crucial role in understanding light's behavior. When we talk about the energy of a photon, we refer to a small packet of light energy. To calculate the energy of one photon, we use the equation:
  • \[ E = \frac{h c}{\lambda} \]

Here, \( E \) is the photon energy, \( h \) is Planck's constant \((6.626 \times 10^{-34} \text{ J s})\), \( c \) is the speed of light \((3.00 \times 10^8 \text{ m/s})\), and \( \lambda \) is the wavelength of the light.
This equation shows us that photon energy is inversely proportional to wavelength, meaning that shorter wavelengths have higher energies.
For instance, in the provided exercise, we deal with a wavelength of 424 nm, leading us to calculate a specific photon energy for that laser light.
Understanding photon energy helps us grasp how light can interact with matter, causing effects like electron excitation or changes in molecular structures.
Stimulated Emission
Stimulated emission is a pivotal process in the operation of lasers, where an incoming photon prompts an atom to emit a second photon of identical energy and phase.
This concept ties into how lasers produce coherent light, which is light where photons move in step, having identical frequency and phase.
When an atom is in an excited state, it can be induced to emit a photon via stimulated emission rather than spontaneous emission.
In a laser, this process is repeated many times, enabling the amplification of light. This is crucial in achieving the bright, directed beams characteristic of lasers.
In the context of the exercise, understanding stimulated emission allows us to relate the number of photons emitted with the number of atoms participating in the laser's pulse emission.
Atomic Physics
Atomic physics forms the conceptual bedrock for understanding how atoms interact with light, particularly in laser technology. An atom consists of a nucleus and orbiting electrons, which can exist in different energy states.
  • When a photon of adequate energy meets an atom, it can excite an electron from a lower to a higher energy state.
  • This high-energy state is not stable indefinitely, prompting the concept of emission.

Atomic transitions are integral in generating the light output in lasers, making laser physics heavily reliant on atomic physics principles.
In our exercise, atoms transition to a high-energy state and return to a lower state by emitting a photon during stimulated emission.
This understanding bridges the behavior of single atoms with the macroscopic light beam generated by lasers.
Wavelength
Wavelength defines the distance between consecutive peaks of a wave. It determines a light's color in the visible spectrum and its photon energy.
In the case of lasers, precisely controlling the wavelength ensures that the emitted light is coherent and monochromatic.
  • The wavelength of 424 nm in the exercise places the laser light within the visible spectrum, appearing as a violet hue.
  • Shorter wavelengths correlate with higher energies, dictating the photon interactions within medium materials.

Different applications require varying wavelengths depending on the desired effects and the material interaction.
For example, a laser intended for cutting metals will have a different wavelength than one designed for medical procedures.
This characteristic of wavelength affects how lasers are constructed and applied across various fields, illustrating its significance in laser physics.

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Most popular questions from this chapter

In an NMR experiment, the RF source oscillates at \(34 \mathrm{MHz}\) and magnetic resonance of the hydrogen atoms in the sample being investigated occurs when the external field \(\vec{B}_{\text {ext }}\) has magnitude 0.78 T. Assume that \(\vec{B}_{\text {int }}\) and \(\vec{B}_{\text {ext }}\) are in the same direction and take the proton magnetic moment component \(\mu_{z}\) to be \(1.41 \times 10^{-26} \mathrm{~J} / \mathrm{T}\). What is the magnitude of \(\vec{B}_{\text {int }} ?\)

Suppose two electrons in an atom have quantum numbers \(n=2\) and \(\ell=1 .\) (a) How many states are possible for those two electrons? (Keep in mind that the electrons are indistinguishable.) (b) If the Pauli exclusion principle did not apply to the electrons, how many states would be possible?

A hydrogen atom in its ground state actually has two possible, closely spaced energy levels because the electron is in the magnetic field \(\vec{B}\) of the proton (the nucleus). Accordingly, an energy is associated with the orientation of the electron's magnetic moment \(\vec{\mu}\) relative to \(\vec{B},\) and the electron is said to be either spin up (higher energy) or spin down (lower energy) in that field. If the electron is excited to the higher-energy level, it can de-excite by spin-flipping and emitting a photon. The wavelength associated with that photon is \(21 \mathrm{~cm}\). (Such a process occurs extensively in the Milky Way galaxy, and reception of the \(21 \mathrm{~cm}\) radiation by radio telescopes reveals where hydrogen gas lies between stars.) What is the effective magnitude of \(\vec{B}\) as experienced by the electron in the ground-state hydrogen atom?

Suppose that a hydrogen atom in its ground state moves \(80 \mathrm{~cm}\) through and perpendicular to a vertical magnetic field that has a magnetic field gradient \(d B / d z=1.6 \times 10^{2} \mathrm{~T} / \mathrm{m} .\) (a) What is the magnitude of force exerted by the field gradient on the atom due to the magnetic moment of the atom's electron, which we take to be 1 Bohr magneton? (b) What is the vertical displacement of the atom in the \(80 \mathrm{~cm}\) of travel if its speed is \(1.2 \times 10^{5} \mathrm{~m} / \mathrm{s} ?\)

If orbital angular momentum \(\vec{L}\) is measured along, say, a \(z\) axis to obtain a value for \(L_{z}\), show that $$\left(L_{x}^{2}+L_{y}^{2}\right)^{1 / 2}=\left[\ell(\ell+1)-m_{\ell}^{2}\right]^{1 / 2} h$$ is the most that can be said about the other two components of the orbital angular momentum.

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