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A rifle is aimed horizontally at a target \(30 \mathrm{~m}\) away. The bullet hits the target \(1.9 \mathrm{~cm}\) below the aiming point. What are (a) the bullet's time of flight and (b) its speed as it emerges from the rifle?

Short Answer

Expert verified
(a) 0.062 s; (b) 484 m/s

Step by step solution

01

Understand the problem

The bullet is fired horizontally, meaning the initial vertical velocity is zero. It falls freely under gravity after leaving the rifle. We know the vertical displacement and the horizontal distance to the target.
02

Convert units

Convert the vertical displacement from centimeters to meters. Hence, the vertical displacement is \[ d_y = -1.9 \text{ cm} = -0.019 \text{ m} \]
03

Find time of flight

Use the equation for vertical motion under gravity: \[ d_y = \frac{1}{2}gt^2 \]where \( g = 9.81 \, \text{m/s}^2 \) is the acceleration due to gravity. Solve for time \( t \):\[ -0.019 = \frac{1}{2} \times 9.81 \times t^2 \]\[ t^2 = \frac{-0.019 \times 2}{9.81} \]\[ t = \sqrt{\frac{-0.038}{9.81}} \approx 0.062 \text{ s} \]
04

Calculate bullet speed

Use the horizontal motion equation. Since there is no horizontal acceleration, speed \( v \) is constant:\[ v = \frac{d_x}{t} \]where \( d_x = 30 \text{ m} \). Substitute the values:\[ v = \frac{30}{0.062} \approx 484 \text{ m/s} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Horizontal Velocity
When approaching projectile motion problems, understanding horizontal velocity is key. In these scenarios, horizontal velocity, denoted by \( v_x \), refers to the speed of the object moving along the horizontal axis. A crucial point to remember is that, in ideal projectile motion (neglecting air resistance), horizontal velocity remains constant. Why? Because there is no horizontal acceleration acting on the projectile. This means that once the bullet leaves the rifle, its horizontal speed, as calculated in problems, does not change.
In our rifle example, the question required us to find the bullet's speed as it emerged from the rifle. Knowing the bullet travels 30 meters horizontally and falls a measurable distance vertically without the influence of horizontal forces allows us to calculate this constant speed. We use the equation \( v_x = \frac{d_x}{t} \), where \( d_x \) is the horizontal distance, and \( t \) is the time of flight, to compute the horizontal speed.
Vertical Displacement
In projectile motion, we also deal with vertical displacement, defined as the change in vertical position of the projectile. Denoted typically by \( d_y \), vertical displacement occurs due to the influence of gravity once the object is in motion. It's important to convert units appropriately, as our example does from centimeters to meters, ensuring consistency with other metric measurements.
In the case of the bullet, its initial vertical velocity is zero because it is aimed horizontally. As a result of gravity, the bullet moves downward, creating vertical displacement. The equation \( d_y = \frac{1}{2}gt^2 \) allows us to connect vertical displacement with time and gravitational acceleration, helping us determine how long an object remains in motion before hitting a target and how much it descends vertically.
Acceleration Due to Gravity
One of the most critical forces in projectile motion is the acceleration due to gravity, represented by \( g \). On Earth's surface, \( g \) equals approximately \( 9.81 \, \text{m/s}^2 \). This uniform acceleration only affects vertical motion, not horizontal motion. It causes the vertical velocity of the projectile to increase as it falls.
The constant nature of gravity simplifies calculations. In the rifle problem, for instance, the gun fires the bullet horizontally, and the force of gravity accelerates the bullet downwards at \( 9.81 \, \text{m/s}^2 \). This understanding allows us to predict how much vertical displacement occurs over time, illuminating gravity's consistent and predictable impact in physical scenarios.

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Most popular questions from this chapter

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