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A woman who can row a boat at \(6.4 \mathrm{~km} / \mathrm{h}\) in still water faces a long, straight river with a width of \(6.4 \mathrm{~km}\) and a current of \(3.2 \mathrm{~km} / \mathrm{h}\). Let i point directly across the river and j point directly downstream. If she rows in a straight line to a point directly opposite her starting position, (a) at what angle to ì must she point the boat and (b) how long will she take? (c) How long will she take if, instead, she rows \(3.2 \mathrm{~km}\) down the river and then back to her starting point? (d) How long if she rows \(3.2 \mathrm{~km}\) up the river and then back to her starting point? (e) At what angle to i should she point the boat if she wants to cross the river in the shortest possible time? (f) How long is that shortest time?

Short Answer

Expert verified
(a) \(210^\circ\), (b) 1.156 hours, (c) 1.333 hours, (d) 1.333 hours, (e) \(0^\circ\), (f) 1 hour.

Step by step solution

01

Determine the Effective Speed Across the River

To remain directly opposite of her starting point, the woman must correct for the river's current by rowing at an angle. Let the angle be \( \theta \), where she rows at a speed of \( 6.4 \text{ km/h} \) at an angle to the direction pointed directly across the river (\( i \)). Her effective speed across is \( 6.4 \cos(\theta) \), and downstream due to river current is \( 6.4 \sin(\theta) + 3.2 \) (the current speed). For her to remain directly opposite, the downstream speed must be zero: \( 6.4 \sin(\theta) + 3.2 = 0 \). Solving for \( \theta \), we have \( \sin(\theta) = -0.5 \). Therefore, \( \theta = 210^\circ \).
02

Calculate the Crossing Time (Part b)

Given the angle to remain directly opposite, her effective speed across the river is \( 6.4\cos(210^\circ) = -5.536 \text{ km/h} \). Since the width of the river is \( 6.4 \text{ km} \), the time to cross is the width divided by the effective speed: \[ t = \frac{6.4}{5.536} \approx 1.156 \text{ hours} \].
03

Time for Round Trip Downstream (Part c)

The boat speed in still water is \( 6.4 \text{ km/h} \), but when rowing downstream, add the river's current speed: \( 6.4 + 3.2 = 9.6 \text{ km/h} \). Therefore, time downstream for 3.2 km: \[ t_{\text{down}} = \frac{3.2}{9.6} \approx 0.333 \text{ hours} \]. Then upstream, her speed is \(6.4 - 3.2 = 3.2 \text{ km/h} \). So time upstream for 3.2 km is \[ t_{\text{up}} = \frac{3.2}{3.2} = 1 \text{ hour} \]. Total round-trip time = \( t_{\text{down}} + t_{\text{up}} \approx 1.333 \text{ hours} \).
04

Time for Round Trip Upstream (Part d)

First, row 3.2 km upstream. Because her rowing speed against the current is \(6.4 - 3.2 = 3.2 \text{ km/h} \), time taken is: \[ t_{\text{up}} = \frac{3.2}{3.2} = 1 \text{ hour} \]. Then, return downstream allowing the current to assist: speed \(6.4 + 3.2 = 9.6 \text{ km/h} \), so \[ t_{\text{down}} = \frac{3.2}{9.6} \approx 0.333 \text{ hours} \]. Total round-trip time \( t_{\text{up}} + t_{\text{down}} = 1.333 \text{ hours} \).
05

Crossing the Shortest Possible Time (Part e)

To cross in the shortest time, disregard the downstream correction. Row straight across with \( \theta = 0^\circ \). Her effective speed is then simply \( 6.4 \text{ km/h} \).
06

Determine the Shortest Time (Part f)

With a direct crossing, time is simply the river width divided by the straight speed: \[ t = \frac{6.4}{6.4} = 1 \text{ hour} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relative Velocity
When the woman rows across the river, she has to account for the current to ensure that she reaches her intended destination. This concept is known as relative velocity. In simple terms, relative velocity is the velocity of an object considering the velocities of other influencing factors, such as the current of the river in this case.

Imagine the woman rowing directly across at her full speed of 6.4 km/h without considering the current. The river's current, moving at 3.2 km/h, would push her downstream. Thus, to achieve her desired destination directly across the river, she needs to incorporate the current's velocity into her planning. This involves adjusting the angle at which she rows, influencing her relative velocity components in two directions:
  • Across the river (perpendicular to the current).
  • Along with the river (in the direction of the current).

By considering the current, she ensures that her path results in her desired endpoint across the river. Understanding relative velocity simplifies determining the right angle and speed needed to navigate accurately.
Angle of Crossing
The angle at which the rower crosses the river is vital for compensating for the current. If she rows straight across, the current would carry her downstream. Instead, she must row at an angle to negate this effect. The key is finding the correct angle, denoted by \(\theta\), to ensure she ends up directly opposite her starting point.

To find this angle, consider her speed in still water (6.4 km/h). When adjusting for the current, the downstream velocity component must cancel out. If the downstream speed needs to be zero, according to the problem:

\[6.4 \sin(\theta) + 3.2 = 0\]

Solving this equation gives her the correct angle \(\theta = 210^\circ\). This angle ensures that the upstream rowing component perfectly counters the river's current, allowing her to reach her target directly across the river.
Time of Crossing
Time to cross the river depends on the effective speed across the river. This effective speed is determined using the angle of crossing. Given the boat can row at 6.4 km/h in still water and her calculated angle \(\theta\), her effective speed is defined by:

\[v_{\text{effective}} = 6.4 \cos(210^\circ) = -5.536 \text{ km/h}\]

Despite the negative sign indicating direction, we care about the speed's magnitude. The width of the river is given as 6.4 km. Thus, the time to cross is:

\[t = \frac{6.4}{5.536} \approx 1.156 \text{ hours}\]

This calculation shows how quickly she can traverse the river when accounting for her angle of crossing. Understanding effective speed is crucial for determining crossing time accurately.
Current Effect on Motion
The river's current significantly affects her motion and travel time. When considering the current, it's essential to acknowledge its two main impacts:
  • Pushing downstream: The current at 3.2 km/h pulls her away from a straight crossing path.
  • Impact on time: Traveling upstream or downstream affects her total travel time.

**Crossing Without Correction:**
Without correcting for the current by setting an angle, she would need to row directly across at her full speed of 6.4 km/h. In this case, her shortest crossing time without current influence is just:
\[t = \frac{6.4}{6.4} = 1 \text{ hour}\]

**Round Trips Involving Current:**
In scenarios where she rows downstream and back or upstream and back, her travel time changes significantly. For instance:
  • Downstream: Faster due to additional current speed.
  • Upstream: Slower as the current resists her motion.

Recognizing the river current's role is fundamental for planning her journey effectively. This understanding ensures she not only reaches her destination but does so in the desired time frame.

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Most popular questions from this chapter

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