Chapter 4: Problem 16
The velocity \(\vec{v}\) of a particle moving in the \(x y\) plane is given by \(\vec{v}=\left(6.0 t-4.0 t^{2}\right) \hat{\mathrm{i}}+8.0 \hat{\mathrm{j}},\) with \(\vec{v}\) in meters per second and \(t(>0)\) in seconds. (a) What is the acceleration when \(t=3.0 \mathrm{~s} ?\) (b) When (if ever) is the acceleration zero? (c) When (if ever) is the velocity zero? (d) When (if ever) does the speed equal \(10 \mathrm{~m} / \mathrm{s} ?\)
Short Answer
Step by step solution
Understand and Differentiate the Velocity Equation for Acceleration
Differentiate the i-component to Obtain Acceleration
Differentiate the j-component to Obtain Acceleration
Combine Components for Total Acceleration Vector
Calculate the Acceleration at \( t=3.0 \) s
Find When Acceleration is Zero
Find When Velocity is Zero
Find When Speed Equals 10 m/s
Solve Quadratic for Tangibility of Speed
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Velocity
Understanding the components of velocity:
- **The \( \hat{\mathrm{i}} \) component** varies with time, indicating that the speed in the x-direction changes as time progresses.
- **The \( \hat{\mathrm{j}} \) component** is constant at 8.0 m/s. This component reveals a steady speed in the y-direction.
When examining conditions such as when the velocity is zero, both components must be zero simultaneously. However, since our j-component is constant, the velocity vector never truly reaches zero.
Acceleration
Here's what you need to understand about acceleration:
- **Differentiating the i-component of velocity** \(6.0t - 4.0t^2\) leads to the i-component of acceleration: \(6.0 - 8.0t\).
- **Differentiating the constant j-component** (8.0) gives 0, meaning there's no change in speed in the y-direction.
Finding when acceleration is zero requires setting the i-component of acceleration to zero, which occurs when \( t = 0.75 \) seconds. This signifies a moment when the particle changes its speed but not its direction.
Differentiation
For the exercise:
- We differentiate each component of the velocity vector to derive the respective components of the acceleration vector.
- Observing the constant explains why its derivative is zero—it doesn't change with time, hence no resulting acceleration in its direction.