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An x-ray beam of a certain wavelength is incident on an \(\mathrm{NaCl}\) crystal, at \(30.0^{\circ}\) to a certain family of reflecting planes of spacing \(39.8 \mathrm{pm} .\) If the reflection from those planes is of the first order, what is the wavelength of the x rays?

Short Answer

Expert verified
The wavelength of the x-rays is 39.8 pm.

Step by step solution

01

Understand the Bragg's Law

Bragg's Law is given by the formula \(n \lambda = 2d \sin \theta\), where \(n\) is the order of reflection, \(\lambda\) is the wavelength of the x-rays, \(d\) is the interplanar spacing, and \(\theta\) is the angle of incidence.
02

Identify Known Values

From the problem, the known values are: \(d = 39.8 \text{ pm}\), \(n=1\) (first order), and \(\theta = 30.0^{\circ}\).
03

Substitute Values into Bragg's Law

Substituting known values into Bragg's Law: \(1 \times \lambda = 2 \times 39.8 \text{ pm} \times \sin(30.0^{\circ})\).
04

Calculate the Sine of the Angle

The sine of 30 degrees is 0.5. So, \(\sin(30.0^{\circ}) = 0.5\).
05

Solve for \(\lambda\)

Plug \(\sin(30.0^{\circ})\) into the equation: \(\lambda = 2 \times 39.8 \text{ pm} \times 0.5\). This simplifies to \(\lambda = 39.8 \text{ pm}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

X-ray Diffraction
X-ray diffraction is a key technique used to investigate the structure of crystalline materials. When x-rays are directed at a crystal, they scatter in various directions. If the conditions are right, the scattered waves can interfere constructively, forming a diffraction pattern. This technique takes advantage of the wave nature of x-rays. X-rays have very short wavelengths, typically in the range of 0.01 to 10 nanometers. These wavelengths are similar in size to the spacing between atoms in a crystal lattice, allowing x-rays to diffract through the crystal. By measuring the angles and intensities of these diffracted rays, scientists can gather information about the crystal structure.
  • Applications: Valuable in determining the atomic and molecular structure of materials.
  • Requirements: Requires x-ray source, crystal sample, and detection apparatus.
This process is vital in fields such as chemistry, physics, and material science for understanding the internal arrangement and characteristics of materials.
Crystal Structure
The term "crystal structure" refers to the orderly and repeating arrangement of atoms within a crystal. This structure is defined by the unit cell, a small repeating unit that comprises the entire crystal lattice.The sodium chloride (\(\mathrm{NaCl}\)) mentioned in the exercise belongs to this family of structures, often forming cubic lattice shapes. The symmetric structure of crystals leads to the interesting phenomenon of diffraction when exposed to x-rays.
  • Unit Cell: The smallest repeating unit of a crystal structure, determining the crystal's shape and symmetry.
  • Interplanar Spacing (\(d\)): The distance between parallel planes of atoms, crucial in calculating diffraction.
Understanding crystal structures is essential for characterizing materials and predicting their properties like hardness, melting point, and conductivity.
Wavelength Calculation
Wavelength calculation is a crucial component in using Bragg's Law, which relates the x-ray wavelength to the diffraction angle and the spacing between crystal planes (\(d\)).In this exercise, Bragg's Law, \(n \lambda = 2d \sin \theta\), is used. Here:
  • \(\lambda\) is the wavelength of the x-rays,
  • \(d\) denotes the interplanar spacing,
  • \(\theta\) is the diffraction angle, and
  • \(n\) is the order of reflection.
Plugging given values such as \(d = 39.8 \, \text{pm}\) and \(\theta = 30^{\circ}\) into this equation, students solve for \(\lambda\).This process of calculation is foundational in x-ray crystallography, aiding researchers in pinpointing the wavelengths necessary for different crystal investigations. By mastering this, students can unlock detailed insights into materials' molecular structures.

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Most popular questions from this chapter

A \(0.10-\mathrm{mm}\) -wide slit is illuminated by light of wavelength \(589 \mathrm{nm}\). Consider a point \(P\) on a viewing screen on which the diffraction pattern of the slit is viewed; the point is at \(30^{\circ}\) from the central axis of the slit. What is the phase difference between the Huygens wavelets arriving at point \(P\) from the top and midpoint of the slit?

A diffraction grating having 180 lines/mm is illuminated with a light signal containing only two wavelengths, \(\lambda_{1}=400 \mathrm{nm}\) and \(\lambda_{2}=500 \mathrm{nm}\). The signal is incident perpendicularly on the grating. (a) What is the angular separation between the secondorder maxima of these two wavelengths? (b) What is the smallest angle at which two of the resulting maxima are superimposed? (c) What is the highest order for which maxima for both wavelengths are present in the diffraction pattern?

The telescopes on some commercial surveillance satellites can resolve objects on the ground as small as \(85 \mathrm{~cm}\) across (see Google Earth), and the telescopes on military surveillance satellites reportedly can resolve objects as small as \(10 \mathrm{~cm}\) across. Assume first that object resolution is determined entirely by Rayleigh's criterion and is not degraded by turbulence in the atmosphere. Also assume that the satellites are at a typical altitude of \(400 \mathrm{~km}\) and that the wavelength of visible light is \(550 \mathrm{nm}\). What would be the required diameter of the telescope aperture for (a) \(85 \mathrm{~cm}\) resolution and (b) \(10 \mathrm{~cm}\) resolution? (c) Now, considering that turbulence is certain to degrade resolution and that the aperture diameter of the Hubble Space Telescope is \(2.4 \mathrm{~m},\) what can you say about the answer to (b) and about how the military surveillance resolutions are accomplished?

Light of wavelength \(600 \mathrm{nm}\) is incident normally on a diffraction grating. Two adjacent maxima occur at angles given by \(\sin \theta=0.2\) and \(\sin \theta=0.3 .\) The fourth-order maxima are missing. (a) What is the separation between adjacent slits? (b) What is the smallest slit width this grating can have? For that slit width, what are the (c) largest, (d) second largest, and (e) third largest values of the order number \(m\) of the maxima produced by the grating?

An \(x\) -ray beam of wavelengths from 95.0 to \(140 \mathrm{pm}\) is incident at \(\theta=45.0^{\circ}\) to a family of reflecting planes with spacing \(d=275 \mathrm{pm}\). What are the (a) longest wavelength \(\lambda\) and (b) associated order number \(m\) and the (c) shortest \(\lambda\) and (d) associated \(m\) of the intensity maxima in the diffraction of the beam?

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