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Prove that it is not possible to determine both wavelength of incident radiation and spacing of reflecting planes in a crystal by measuring the Bragg angles for several orders.

Short Answer

Expert verified
It's not feasible to determine both \( \lambda \) and \( d \) solely from \( \theta \) measurements; both variables are intertwined in the equation.

Step by step solution

01

Understanding Bragg's Law

Bragg's Law relates the wavelength of the incident radiation \( \lambda \), the spacing of the reflecting crystal planes \( d \), and the Bragg angle \( \theta \). The law is expressed by \[ n\lambda = 2d \sin \theta \] where \( n \) is the order of the reflection.
02

Applying Bragg's Law to Different Orders

For different orders’ \( n_1 \), \( n_2 \), \( n_3 \), etc., the same \( d \) and \( \lambda \), you can write separate equations: \[ n_1\lambda = 2d \sin \theta_1 \] \[ n_2\lambda = 2d \sin \theta_2 \] and so on.
03

Analyzing the Equations

If you measure \( \theta \) for different orders \( n \), each equation includes both unknowns \( \lambda \) and \( d \). Notice every equation for different orders has a different angle \( \theta \) but still depends on both \( \lambda \) and \( d \).
04

Attempting to Solve for Both Unknowns

From the equations, you cannot separate \( \lambda \) and \( d \) independently by only using different \( \theta \) measurements, since all are interconnected. This means you cannot uniquely identify both \( \lambda \) and \( d \) because they are scaled together.
05

Conclusion

The inability to decouple \( \lambda \) and \( d \) from these equations when only \( \theta \) varies for numerous orders supports the conclusion: you cannot determine both assuming just \( \theta \) measurements for different \( n \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wavelength Measurement
Wavelength measurement is a critical concept in understanding how radiation interacts with materials. In the context of Bragg's Law, wavelength refers to the distance between consecutive peaks of a wave. Measurement of wavelength is essential in revealing details about the structure of crystals.
By using X-rays or similar radiation, scientists can infer the wavelength by monitoring changes in reflective properties. These interactions occur when the wavelength is compatible with the scale of atomic spacing in the crystal.
However, when both the wavelength \( \lambda \) and the crystal plane spacing \( d \) are unknowns, deducing \( \lambda \) becomes challenging if relying solely on Bragg angles \( \theta \) for different orders \( n \). The equations governed by Bragg's Law intertwine \( \lambda \) and \( d \), making their independent determination impossible by just looking at angle variations. Trying various Bragg angles helps observe changes in reflection, but doesn’t break the dependence between \( \lambda \) and \( d \).
Crystal Plane Spacing
Crystal plane spacing \( d \) is a fundamental parameter in crystallography, representing the physical distance between parallel planes of atoms inside a crystal.
This spacing affects how waves are diffracted off the crystal. In Bragg's Law, \( d \) is critical, as it directly influences the angle \( \theta \) for which waves constructively interfere.
When unknown, as it often is, \( d \) needs to be considered alongside wavelength \( \lambda \). Attempting to solve Bragg's equation with both \( d \) and \( \lambda \) unknown results in an interdependent system. Without external calibration or assumed values for one of the parameters, separating their individual contributions by just altering Bragg angle remains unattainable. This limitation makes it necessary to have some known quantity or secondary method to independently confirm either \( d \) or \( \lambda \).
Bragg Angle
The Bragg angle \( \theta \) is pivotal to Bragg's Law, as it is the angle at which constructive interference occurs between reflected waves. It directly links with the measurable reflection of waves from crystal planes.
By varying \( \theta \), scientists can observe changes in reflection intensity. This angle is not enough, however, to separate or solve for both wavelength \( \lambda \) and crystal spacing \( d \).
The reason stems from the dependency induced between \( \lambda \) and \( d \) in the geometric arrangement given by Bragg's Law: \[ n\lambda = 2d \sin \theta \]. While distinct \( \theta \) values provide different data points, they do not offer enough information to decouple these two parameters. Other analytical techniques or reference data are often needed to resolve either \( \lambda \) or \( d \) independently, making crystal analysis both an art and a science.

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Most popular questions from this chapter

A spy satellite orbiting at \(160 \mathrm{~km}\) above Earth's surface has a lens with a focal length of \(3.6 \mathrm{~m}\) and can resolve objects on the ground as small as \(30 \mathrm{~cm}\). For example, it can easily measure the size of an aircraft's air intake port. What is the effective diameter of the lens as determined by diffraction consideration alone? Assume \(\lambda=550 \mathrm{nm}\).

(A) How many bright fringes appear between the first diffraction-envelope minima to either side of the central maximum in a double-slit pattern if \(\lambda=550 \mathrm{nm}, d=0.150 \mathrm{~mm}\) and \(a=30.0 \mu \mathrm{m} ?\) (b) What is the ratio of the intensity of the third bright fringe to the intensity of the central fringe?

If you look at something \(40 \mathrm{~m}\) from you, what is the smallest length (perpendicular to your line of sight) that you can resolve, according to Rayleigh's criterion? Assume the pupil of your eye has a diameter of \(4.00 \mathrm{~mm}\), and use \(500 \mathrm{nm}\) as the wavelength of the light reaching you.

What must be the ratio of the slit width to the wavelength for a single slit to have the first diffraction minimum at \(\theta=45.0^{\circ} ?\)

In the single-slit diffraction experiment of Fig. \(36-4,\) let the wavelength of the light be \(500 \mathrm{nm}\), the slit width be \(6.00 \mu \mathrm{m}\), and the viewing screen be at distance \(D=3.00 \mathrm{~m}\). Let a \(y\) axis extend upward along the viewing screen, with its origin at the center of the diffraction pattern. Also let \(I_{P}\) represent the intensity of the diffracted light at point \(P\) at \(y=15.0 \mathrm{~cm} .\) (a) What is the ratio of \(I_{P}\) to the intensity \(I_{m}\) at the center of the pattern? (b) Determine where point \(P\) is in the diffraction pattern by giving the maximum and minimum between which it lies, or the two minima between which it lies.

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