/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 A certain helium-neon laser emit... [FREE SOLUTION] | 91Ó°ÊÓ

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A certain helium-neon laser emits red light in a narrow band of wavelengths centered at \(632.8 \mathrm{nm}\) and with a "wavelength width" (such as on the scale of Fig. \(33-1\) ) of \(0.0100 \mathrm{nm}\). What is the corresponding "frequency width" for the emission?

Short Answer

Expert verified
The frequency width is approximately \(7.49 \times 10^6 \text{Hz}\).

Step by step solution

01

Understand Wavelength Width and Frequency Width

The problem states that the laser emits a light with a central wavelength of \(\lambda = 632.8 \, \text{nm}\) and a wavelength width (range of wavelengths) of \(\Delta \lambda = 0.0100 \, \text{nm}\). We need to find the frequency width \(\Delta f\), which corresponds to this change in wavelength.
02

Use the Relationship between Wavelength and Frequency

The relationship between the speed of light \(c\), wavelength \(\lambda\), and frequency \(f\) is given by \(c = \lambda f\). Frequency \(f\) can be expressed as \(f = \frac{c}{\lambda}\). Since we have a wavelength width, the frequency width can be determined using derivatives or small changes: \(\Delta f = -\frac{c}{\lambda^2} \cdot \Delta \lambda\).
03

Calculate the Frequency Width Using Given Values

We have \(\lambda = 632.8 \, \text{nm} = 632.8 \times 10^{-9} \, \text{m}\), \(\Delta \lambda = 0.0100 \, \text{nm} = 0.0100 \times 10^{-9} \, \text{m}\), and the speed of light \(c = 3.00 \times 10^8 \, \text{m/s}\). Substitute these values into the formula for \(\Delta f\): \[\Delta f = -\frac{3.00 \times 10^8}{(632.8 \times 10^{-9})^2} \cdot (0.0100 \times 10^{-9})\].
04

Compute the Result

Calculate the value: \[\Delta f = -\frac{3.00 \times 10^8}{(632.8 \times 10^{-9})^2} \cdot (0.0100 \times 10^{-9})\]Compute step by step: 1. Calculate \((632.8 \times 10^{-9})^2 = 4.00518464 \times 10^{-19}\).2. Find \(b = \frac{3.00 \times 10^8}{4.00518464 \times 10^{-19}} = 7.49 \times 10^{14} \text{Hz/m}\).3. Multiply by \(0.0100 \times 10^{-9}\) to get \(\Delta f = 7.49 \times 10^{9} \times 0.0100 \times 10^{-9} = 7.49 \times 10^6\).Therefore, the frequency width \(\Delta f = 7.49 \times 10^6 \, \text{Hz}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wavelength
Wavelength is a fundamental concept in quantum optics and plays a crucial role in understanding light behavior. It refers to the distance between two consecutive peaks of a wave. For laser light, which is highly coherent and monochromatic, this distance helps define the light's color and its interaction with matter.
The unit of wavelength is typically nanometers (nm) when working with light, with 1 nanometer being one-billionth of a meter. The problem deals with a central wavelength of 632.8 nm for the laser, meaning that this is the average distance between wave peaks in the emitted red light.
Understanding wavelength is critical for fields such as spectroscopy, telecommunications, and laser technology, where precise wavelength control is necessary. Changes or "widths" in wavelength, like the 0.0100 nm in the problem, can indicate the range over which a laser emits light and affect calculations for other properties such as frequency.
Frequency
Frequency is another crucial property of light, describing how many wave cycles pass a given point in one second. It is measured in Hertz (Hz). The relationship between frequency and wavelength is inversely proportional: as one increases, the other decreases.
In the context of the exercise, we determine the frequency from the given central wavelength using the formula:
  • \( f = \frac{c}{\lambda} \)
This computation is essential because frequency relates directly to energy through Planck's equation. In quantum optics, it provides insights into how light behaves and interacts with matter. Understanding frequency is vital for applications like laser design and optical communication where accurate frequency control is necessary.
The calculation of frequency width, \(\Delta f\), is tied to changes in wavelength, as shown by the formula:
  • \( \Delta f = -\frac{c}{\lambda^2} \cdot \Delta \lambda \)
This shows how a small shift in wavelength results in a change in frequency, impacting energy and coherence in laser applications.
Speed of Light
The speed of light, commonly denoted as \(c\), is a constant fundamental to understanding electromagnetic waves, including light. It is approximately \(3.00 \times 10^8 \) meters per second in a vacuum.
This fundamental constant connects wavelength and frequency, described by the equation:
  • \( c = \lambda f \)
Knowing the speed of light allows us to calculate either wavelength or frequency if the other variable is known. In practice, it forms the backbone of calculations across various fields, from relativity to quantum optics.
In our exercise, it serves as the bridge to convert wavelength data into frequency data through formula manipulation. This understanding is crucial for deriving properties of light lasers and for ensuring precise workings of optical instruments.
Laser Emission
Laser emission refers to the coherent and monochromatic light that lasers produce, which is distinct due to specific properties like wavelength and frequency. Lasers work by emitting light via a process of optical amplification based on the stimulated emission of electromagnetic radiation.
A helium-neon laser, as in the exercise, specifically emits red light due to the combination of helium and neon gas atoms. This emission occurs at a known wavelength, allowing precise applications in fields such as medicine, communication, and industry.
Laser emission is characterized by:
  • Coherence: Waves are in phase, leading to constructive interference and concentrated power output.
  • Monochromaticity: Emission occurs at a singular wavelength.
  • Directionality: The beam is well-collimated and travels in a specific direction.
Understanding these properties is crucial when working with laser technologies as they determine how the laser interacts with materials and is applied in different sectors. These attributes also tie back into the importance of precision in calculations pertaining to wavelength and frequency, as seen in the exercise where emission characteristics drive the need for such analysis.

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Most popular questions from this chapter

The magnetic component of an electromagnetic wave in vacuum has an amplitude of \(85.8 \mathrm{nT}\) and an angular wave number of \(4.00 \mathrm{~m}^{-1} .\) What are (a) the frequency of the wave, (b) the rms value of the electric component, and (c) the intensity of the light?

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