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A magnetic flux of \(7.0 \mathrm{mWb}\) is directed outward through the flat bottom face of the closed surface shown in Fig. \(32-40 .\) Along the flat top face (which has a radius of \(4.2 \mathrm{~cm}\) ) there is a \(0.40 \mathrm{~T}\) magnetic field \(\vec{B}\) directed perpendicular to the face. What are the (a) magnitude and (b) direction (inward or outward) of the magnetic flux through the curved part of the surface?

Short Answer

Expert verified
The magnitude is 0.0092 Wb and the direction is inward.

Step by step solution

01

Understanding the Problem

We have a closed surface comprising a flat bottom face and a curved top face with a magnetic flux of \(7.0\, \mathrm{mWb}\) directed outward through the bottom face. Along the flat top face, the magnetic field is \(0.40\, \mathrm{T}\), outward. We must find the magnetic flux through the curved surface.
02

Recall Gauss's Law for Magnetism

Gauss's Law for magnetism states that the net magnetic flux through any closed surface is zero, i.e., \( \Phi_{\text{net}} = \Phi_{\text{bottom}} + \Phi_{\text{top}} + \Phi_{\text{curved}} = 0 \). Since it's a closed surface, the total magnetic flux entering or exiting must sum to zero.
03

Calculate Magnetic Flux through the Top Surface

The magnetic flux \( \Phi_{\text{top}} \) is calculated using the formula \( \Phi = B \cdot A \), where \( B = 0.40\, \mathrm{T} \) and \( A \) is the area of the circle with radius \(4.2\, \mathrm{cm} = 0.042\, \mathrm{m}\). The area \( A \) is \( \pi \times (0.042)^2 \).
04

Compute the Flux through the Top Surface

Calculate the area: \[ A = \pi \times (0.042)^2 = \pi \times 0.001764 = 0.00554\, \mathrm{m}^2. \] Hence, \( \Phi_{\text{top}} = 0.40 \times 0.00554 \approx 0.002216\, \mathrm{Wb} \) directed outward.
05

Use Gauss's Law to Find Curved Surface Flux

Substitute the known values into Gauss's law equation: \[ \Phi_{\text{bottom}} + \Phi_{\text{top}} + \Phi_{\text{curved}} = 0 \] \( 0.007\, \mathrm{Wb} + 0.002216\, \mathrm{Wb} + \Phi_{\text{curved}} = 0 \) gives, \( \Phi_{\text{curved}} = -0.009216\, \mathrm{Wb} \).
06

Determine the Direction of the Flux through the Curved Surface

The negative sign in \( \Phi_{\text{curved}} = -0.009216\, \mathrm{Wb} \) indicates that the flux direction through the curved surface is inward.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gauss's Law for Magnetism
Gauss's Law for magnetism is an essential principle when discussing magnetic lines of force and flux. According to this law, the total magnetic flux through any closed surface always equates to zero. This concept forms the foundation for understanding how magnetic fields behave in enclosed areas. It essentially means that when you have a closed surface, like the one described in our problem, the total sum of magnetic flux going in and coming out must cancel each other out completely.
This is because magnetic monopoles do not exist – you can't have a net "magnetic charge" in a way. The magnetic lines of force form closed loops without a beginning or end. Consequently, across a closed surface, what enters must exit elsewhere, leaving no net magnetic flux. In our exercise, this means that the outward flux through one part of the surface must be compensated by inward flux through another part so that the total is zero.
Magnetic Field Calculation
Magnetic field calculations are critical to determine the magnetic flux passing through a particular surface. The magnetic flux (\( \Phi \)), through a surface, is calculated by multiplying the magnetic field strength (\( B \)) by the area of the surface (\( A \)) that the field passes through. Mathematically this is expressed as \( \Phi = B \cdot A \).
In our exercise, the top face of the cup shaped surface has a magnetic field of \( 0.40 \, \mathrm{T} \). The area of this circular face is calculated using the formula for the area of a circle, \( A = \pi r^2 \), where \( r \) is the radius. With a radius of \( 4.2 \, \mathrm{cm} = 0.042 \, \mathrm{m}, \) the calculation shows that the area is \( 0.00554 \, \mathrm{m}^2 \). Thus, when you multiply this area by the magnetic field, the resulting magnetic flux through the top surface is \( 0.002216 \, \mathrm{Wb} \).
Closed Surface Flux
When dealing with closed surface flux, it's crucial to note the directionality of the flux and use Gauss’s Law effectively. In our exercise with a closed surface, we were provided two pieces of flux information: the flux directed outward through the bottom surface, and the magnetic field on the top surface.
Since total flux through a closed surface must be zero according to Gauss’s law, the flux through the curved section becomes an unknown we calculate. Here, the bottom flux was \( 0.007 \, \mathrm{Wb} \), directed outward. The top flux, calculated from the provided magnetic field, was \( 0.002216 \, \mathrm{Wb} \), also outward.
By using Gauss's Law and summing these known values, we can calculate the magnetic flux through the curved surface. Through algebra, if \( \Phi_{\text{bottom}} + \Phi_{\text{top}} + \Phi_{\text{curved}} = 0, \) then \( \Phi_{\text{curved}} = -0.009216 \, \mathrm{Wb}. \) The negative sign indicates that this flux is inward, balancing the outward fluxes from the other parts of the closed surface.

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Most popular questions from this chapter

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