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A magnetic rod with length \(6.00 \mathrm{~cm},\) radius \(3.00 \mathrm{~mm},\) and (uniform) magnetization \(2.70 \times 10^{3} \mathrm{~A} / \mathrm{m}\) can turn about its center like a compass needle. It is placed in a uniform magnetic field \(\vec{B}\) of magnitude \(35.0 \mathrm{mT}\), such that the directions of its dipole moment and \(\vec{B}\) make an angle of \(68.0^{\circ} .\) (a) What is the magnitude of the torque on the rod due to \(\vec{B} ?\) (b) What is the change in the orientation energy of the rod if the angle changes to \(34.0^{\circ} ?\)

Short Answer

Expert verified
The torque is approximately 1.48 × 10^{-4} N·m and the energy change is -8.22 × 10^{-5} J.

Step by step solution

01

Understanding Torque Formula

Torque (\( \tau \)) on a magnetic dipole in a magnetic field can be calculated using the formula:\[\tau = \mu B \sin \theta\]where \( \mu \)is the magnetic moment, \( B \)is the magnetic field, and \( \theta \)is the angle between the dipole moment and the magnetic field.
02

Calculate Magnetic Dipole Moment

The magnetic dipole moment \( \mu \)of the rod is given by the product of its magnetization \( M \)and its volume. The volume \( V \)of the rod is calculated using \( V = \pi r^2 l \)where \( r \)is the radius and \( l \)is the length. Thus, \( V = \pi \times (3\times10^{-3}\,\text{m})^2 \times 0.06\,\text{m} \approx 1.696 \times 10^{-6}\,\text{m}^3 \).The dipole moment is then \( \mu = M V = 2.70 \times 10^3\,\text{A/m} \times 1.696 \times 10^{-6}\,\text{m}^3 \approx 4.58 \times 10^{-3}\,\text{A}\cdot\text{m}^2 \).
03

Calculate Torque

Using the calculated magnetic dipole moment \( \mu = 4.58 \times 10^{-3}\,\text{A}\cdot\text{m}^2 \), the magnetic field \( B = 35.0 \times 10^{-3}\,\text{T} \), and angle \( \theta = 68.0^{\circ} \), we calculate the torque:\[\tau = 4.58 \times 10^{-3} \times 35.0 \times 10^{-3} \times \sin(68.0^{\circ}) \approx 1.48 \times 10^{-4}\,\text{N}\cdot\text{m} \].
04

Calculate Energy Change Formula

The change in orientation energy \( \Delta U \)when an angle changes from \( \theta_1 \)to \( \theta_2 \)is given by:\[\Delta U = -\mu B (\cos \theta_2 - \cos \theta_1)\].
05

Calculate Energy Change

Substitute \( \mu = 4.58 \times 10^{-3}\,\text{A}\cdot\text{m}^2 \), \( B = 35.0 \times 10^{-3}\,\text{T} \), \( \theta_1 = 68.0^{\circ} \), and \( \theta_2 = 34.0^{\circ} \)into the equation:\[\Delta U = -4.58 \times 10^{-3} \times 35.0 \times 10^{-3} \times (\cos 34.0^{\circ} - \cos 68.0^{\circ}) \approx -8.22 \times 10^{-5}\,\text{J}\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Dipole Moment
The concept of a magnetic dipole moment is fundamental in understanding how magnetic objects interact with external magnetic fields. The magnetic dipole moment \( \mu \) represents the strength and orientation of a magnet's magnetic field. It's akin to the electric dipole moment, but instead of dealing with electric charges, it's focused on magnetic poles.
In our context, the magnetic rod's dipole moment is determined by its magnetization \( M \) and its volume \( V \). The magnetization \( M \), measured in amperes per meter \( \mathrm{A/m} \), represents the magnet's magnetic field at its surface. Volume, typically calculated as \( V = \pi r^2 l \) for a cylindrical shape, depends on the dimensions of the rod.
The dipole moment \( \mu \) is a vector quantity, symbolizing both magnitude and direction. In mathematical terms, it's given by:
\[ \mu = M \times V \]
It signifies how strong the rod acts as a magnet and the direction its north pole points. This moment plays a crucial role in calculating forces and torques exerted by surrounding magnetic fields.
Orientation Energy
Orientation energy deals with how a magnetic dipole responds to a magnetic field. It's like how a compass needle aligns itself with the Earth's magnetic field. The energy involved in changing the dipole's orientation relative to the magnetic field is termed as orientation energy.
The energy \( U \) of a dipole in a magnetic field \( \vec{B} \) is calculated as:
\[ U = -\mu B \cos \theta \]
Here, \( \mu \) is the dipole moment, \( B \) is the magnetic field strength, and \( \theta \) is the angle between the dipole moment and the magnetic field. The negative sign indicates that the system prefers to lower its energy by aligning with the field.
When the orientation changes, say from angle \( \theta_1 \) to \( \theta_2 \), there is a change in energy \( \Delta U \) calculated as:
\[ \Delta U = -\mu B (\cos \theta_2 - \cos \theta_1) \]
This concept is similar to potential energy changes in a gravitational field, reflecting the energy expense (or gain) as a dipole re-orients under magnetic influence.
Magnetization
Magnetization is a measure of how much a material becomes magnetized when placed in an external magnetic field. It's analogous to how easily a material can conduct electricity. But here, we're gauging the material's response to magnetic fields.
Measured in amperes per meter \( \mathrm{A/m} \), magnetization \( M \) describes the density of magnetic dipole moments in a given volume. In simpler terms, it's the intensity of magnetic moments per unit volume of the material. This concept helps quantify the material's overall magnetic character.
When a magnetic rod is characterized by uniform magnetization, this means its magnetic properties are consistent throughout its volume. In practice, this magnetization determines how the rod behaves in an external magnetic field. It directly influences the calculated magnetic dipole moment, thus affecting the torque experienced by the rod and its orientation energy.
Understanding magnetization is pivotal in designing magnetic materials for various applications, from industrial magnets to data storage devices. It's an underlying principle that dictates the effectiveness and efficiency of such materials in practical scenarios.

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Most popular questions from this chapter

A capacitor with parallel circular plates of radius \(R=1.20 \mathrm{~cm}\) is discharging via a current of 12.0 A. Consider a loop of radius \(R / 3\) that is centered on the central axis between the plates. (a) How much displacement current is encircled by the loop? The maximum induced magnetic field has a magnitude of \(12.0 \mathrm{mT}\). At what radius (b) inside and (c) outside the capacitor gap is the magnitude of the induced magnetic field \(3.00 \mathrm{mT} ?\)

Shows a circular region of radius \(R=3.00 \mathrm{~cm}\) in which an electric flux is directed out of the plane of the page. The flux encircled by a concentric circle of radius \(r\) is given by \(\Phi_{E, \text { enc }}=(0.600 \mathrm{~V} \cdot \mathrm{m} / \mathrm{s})\) \((r / R) t,\) where \(r \leq R\) and \(t\) is in seconds. What is the magnitude of the induced magnetic field at radial distances (a) \(2.00 \mathrm{~cm}\) and (b) \(5.00 \mathrm{~cm} ?\)

Abar magnet lies near a paper cylinder. (a) Sketch the magnetic field lines that pass through the surface of the cylinder. (b) What is the sign of \(\vec{B} \cdot d \vec{A}\) for every area \(d \vec{A}\) on the surface? (c) Does this contradict Gauss' law for magnetism? Explain.

A Gaussian surface in the shape of a right circular cylinder with end caps has a radius of \(12.0 \mathrm{~cm}\) and a length of \(80.0 \mathrm{~cm} .\) Through one end there is an inward magnetic flux of \(25.0 \mu \mathrm{Wb}\). At the other end there is a uniform magnetic field of \(1.60 \mathrm{mT}\), normal to the surface and directed outward. What are the (a) magnitude and (b) direction (inward or outward) of the net magnetic flux through the curved surface?

The magnitude of the magnetic dipole moment of Earth is \(8.0 \times 10^{22} \mathrm{~J} / \mathrm{T}\). (a) If the origin of this magnetism were a magnetized iron sphere at the center of Earth, what would be its radius? (b) What fraction of the volume of Earth would such a sphere occupy? Assume complete alignment of the dipoles. The density of Earth's inner core is \(14 \mathrm{~g} / \mathrm{cm}^{3} .\) The magnetic dipole moment of an iron atom is \(2.1 \times 10^{-23} \mathrm{~J} / \mathrm{T}\). (Note: Earth's inner core is in fact thought to be in both liquid and solid forms and partly iron, but a permanent magnet as the source of Earth's magnetism has been ruled out by several considerations. For one, the temperature is certainly above the Curie point.)

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