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Prove that the displacement current in a parallel-plate capacitor of capacitance \(C\) can be written as \(i_{d}=C(d V / d t),\) where \(V\) is the potential difference between the plates.

Short Answer

Expert verified
The displacement current is given by \(i_d = C \frac{dV}{dt}\).

Step by step solution

01

Understand Displacement Current

The displacement current is a concept introduced by Maxwell to account for changing electric fields in cases where there is no actual movement of charge through a medium, like in the gap of a capacitor. In essence, displacement current allows us to use Ampère's Law with Maxwell's addition to determine magnetic fields in a circuit with time-varying electric fields.
02

Recall the Relationship between Capacitance, Charge, and Voltage

For a capacitor, the relationship between charge \(Q\), capacitance \(C\), and voltage \(V\) is given by the formula \(Q = C \cdot V\). The displacement current is related to the time rate of change of charge on the capacitor.
03

Express the Time Rate of Change of Charge

Since \(Q = C \cdot V\), differentiate both sides with respect to time \(t\) to find the rate at which charge changes: \(\frac{dQ}{dt} = C \cdot \frac{dV}{dt}\). This expression shows how the charge on the capacitor changes as the voltage changes over time.
04

Identify the Expression for Displacement Current

In the context of the displacement current \(i_d\), the changing electric field in the capacitor results in a current equivalent to the time rate of change of charge, i.e., \(i_d = \frac{dQ}{dt}\). Substituting from the expression derived in Step 3, we have \(i_d = C \cdot \frac{dV}{dt}\). This shows the displacement current in terms of capacitance \(C\) and the rate of change of potential difference \(\frac{dV}{dt}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

parallel-plate capacitor
A parallel-plate capacitor is a simple electrical component that consists of two conductive plates facing each other, separated by a certain distance. This setup is used to store electrical energy in the form of an electric field between the plates.
Capacitors are fundamental components in various electronic devices. They can store and release energy quickly when needed.
  • The capacity of a capacitor to store charge is determined by the surface area of the plates and the distance between them; hence often termed as a parallel-plate setup.
  • The material between the plates can affect the capacitor's ability to store charge; this is referred to as the dielectric.
  • The electric field between the plates is uniform, which simplifies calculations and analyses.
The parallel arrangement of plates makes it easy to visualize and understand how capacitors store energy and contribute to the operation of complex electrical circuits.
Maxwell's equations
Maxwell's equations are a set of four fundamental equations in electromagnetism describing how electric charges and currents produce electric and magnetic fields. These equations form the foundation for classical electrodynamics, electric circuits, optics, and electric technologies.
Maxwell's equations are given as:
  • Gauss's Law: Describes the distribution of electric charge in space.
  • Gauss's Law for Magnetism: States that there are no magnetic monopoles.
  • Faraday's Law of Induction: Explains how a time-varying magnetic field creates an electric field.
  • Ampère's Law with Maxwell's Addition: Reveals how a time-varying electric field induces a magnetic field.
These equations not only unify electricity and magnetism into electromagnetism but also introduce the displacement current concept, which is crucial in solving problems involving time-varying fields, like in the operation of the parallel-plate capacitor.
Ampère's Law with Maxwell's addition
Ampère's Law originally states that magnetic fields can be generated by electric currents (moving charges). However, Maxwell identified instances where magnetic fields appeared without physical currents.
To address this, he introduced the concept of displacement current, which coupled changing electric fields to magnetic fields. This modification is known as Ampère's Law with Maxwell's addition.
In its modern form, Ampère's Law is written as: \[ \oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 (I + \varepsilon_0 \frac{d\Phi_E}{dt}) \] Here, the extra term \(\varepsilon_0 \frac{d\Phi_E}{dt}\) accounts for the displacement current caused by changing electric fields.
  • The displacement current term becomes critically important in situations where no actual charge is moving, such as in a charging or discharging capacitor.
  • This addition allows us to generalize Ampère's Law to dynamic situations involving time-varying electromagnetic fields.
Understanding this concept helps us analyze situations like electromagnetic wave propagation, where dynamic fields continuously interact.
capacitance and voltage relationship
The relationship between capacitance, charge, and voltage is a cornerstone of circuit theory and electromagnetism. Understanding this relationship is essential for analyzing circuits that involve capacitors, such as RC circuits and filtering systems.
The fundamental formula for a capacitor is: \[ Q = C \times V \] Where:
  • \(Q\) is the charge stored on the plates,
  • \(C\) is the capacitance, which reflects the capacitor's ability to store charge,
  • \(V\) is the voltage, or potential difference, across the plates.
By differentiating this equation with respect to time, we obtain the expression for the rate at which charge is changing, which relates directly to the displacement current: \[ i_{d} = \frac{dQ}{dt} = C \cdot \frac{dV}{dt} \]
This relationship highlights how changes in voltage over time lead to displacement currents, emphasizing how capacitors respond dynamically in circuits.

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Most popular questions from this chapter

An electron with kinetic energy \(K_{e}\) travels in a circular path that is perpendicular to a uniform magnetic field, which is in the positive direction of a \(z\) axis. The electron's motion is subject only to the force due to the field. (a) Show that the magnetic dipole moment of the electron due to its orbital motion has magnitude \(\mu=K_{e} / B\) and that it is in the direction opposite that of \(\vec{B}\). What are the (b) magnitude and (c) direction of the magnetic dipole moment of a positive ion with kinetic energy \(K_{i}\) under the same circumstances? (d) An ionized gas consists of \(5.3 \times 10^{21}\) electrons/m \(^{3}\) and the same number density of ions. Take the average electron kinetic energy to be \(6.2 \times 10^{-20} \mathrm{~J}\) and the average ion kinetic energy to be \(7.6 \times 10^{-21} \mathrm{~J}\). Calculate the magnetization of the gas when it is in a magnetic field of \(1.2 \mathrm{~T}\).

If an electron in an atom has orbital angular momentum with \(m_{e}\) values limited by ±3 , how many values of (a) \(L_{\text {orb }, z}\) and (b) \(\mu_{\text {orb }, z}\) can the electron have? In terms of \(h, m,\) and \(e,\) what is the greatest allowed magnitude for (c) \(L_{\text {orb }, z}\) and \(\left(\right.\) d) \(\mu_{\text {orb }, z} ?\) (e) What is the greatest allowed magnitude for the \(z\) component of the electron's net angular momentum (orbital plus spin)? (f) How many values (signs included) are allowed for the \(z\) component of its net angular momentum?

Assume the average value of the vertical component of Earth's magnetic field is \(43 \mu \mathrm{T}\) (downward) for all of Arizona, which has an area of \(2.95 \times 10^{5} \mathrm{~km}^{2}\). What then are the (a) magnitude and (b) direction (inward or outward) of the net magnetic flux through the rest of Earth's surface (the entire surface excluding Arizona)?

An electron is placed in a magnetic field \(\vec{B}\) that is directed along a \(z\) axis. The energy difference between parallel and antiparallel alignments of the \(z\) component of the electron's spin magnetic moment with \(\vec{B}\) is \(6.00 \times 10^{-25} \mathrm{~J}\). What is the magnitude of \(\vec{B} ?\)

At what rate must the potential difference between the plates of a parallel- plate capacitor with a \(2.0 \mu \mathrm{F}\) capacitance be changed to produce a displacement current of 1.5 A?

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