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In an oscillating \(L C\) circuit, when \(75.0 \%\) of the total energy is stored in the inductor's magnetic field, (a) what multiple of the maximum charge is on the capacitor and (b) what multiple of the maximum current is in the inductor?

Short Answer

Expert verified
(a) 0.5 times maximum charge, (b) 0.866 times maximum current.

Step by step solution

01

Understand Energy Distribution in LC Circuit

In an LC circuit, energy oscillates between the inductor's magnetic field and the capacitor's electric field. Let \( U \) be total energy. When a certain percentage of this energy is stored in the inductor, the sum of energy in the capacitor's electric field and the inductor's magnetic field equals \( U \).
02

Express Energy in Inductor

The magnetic energy in the inductor, \( U_L \), is \( U_L = \frac{1}{2} L I^2 \), where \( L \) is inductance and \( I \) is the current. Given \( U_L = 0.75 U \), relate this to other circuit parameters.
03

Express Energy in Capacitor

The energy in the capacitor, \( U_C \), is \( U_C = \frac{1}{2} C V^2 \), where \( C \) is capacitance and \( V \) is voltage. When \( U_L = 0.75 U \), then \( U_C = 0.25 U \).
04

Relate Maximum Energy Capacitor to Charge

Using the relationship \( U = \frac{1}{2} C V_{max}^2 \), and charge \( Q = C V \), we find \( U_C = \frac{Q^2}{2C} \). Hence \( Q = \sqrt{0.25} Q_{max} = 0.5 Q_{max} \), with \( Q_{max} \) being maximum charge.
05

Relate Maximum Energy Inductor to Current

Using the relationship \( U = \frac{1}{2} L I_{max}^2 \), \( U_L = \frac{L I^2}{2} \). Hence, \( I = \/sqrt{0.75} I_{max} \approx 0.866 I_{max} \), with \( I_{max} \) being the maximum current.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Distribution
In an LC circuit, energy is continuously exchanged between two main components: the inductor and the capacitor. During this process, the energy oscillates back and forth from the magnetic field of the inductor to the electric field of the capacitor. At any given moment, the total energy in the circuit, denoted as \( U \), is split between these two fields.
For example, if 75% of the total energy is stored in the inductor's magnetic field, the remaining 25% is then in the capacitor's electric field. The equation reflecting this distribution is \( U = U_L + U_C \), where \( U_L \) is the energy stored in the inductor, and \( U_C \) is the energy stored in the capacitor. Understanding this interchange of energy is crucial in analyzing and predicting the behavior of LC circuits.
When working with LC circuits, remember:
  • Energy in the inductor is described by its magnetic field.
  • Energy in the capacitor is stored as electric potential.
  • The sum of energies in both components equals the total energy \( U \).
Inductor's Magnetic Field
The magnetic field in an inductor in an LC circuit stores energy that is proportional to the square of the current flowing through it. This energy is often referred to as magnetic energy and is given by the formula \( U_L = \frac{1}{2} L I^2 \), where \( L \) is the inductance and \( I \) is the current at a specific instant.
When 75% of the LC circuit's energy is stored in this magnetic field, we apply \( U_L = 0.75 U \). This condition provides insights into how the current at that moment relates to the maximum current, \( I_{max} \).
To use the energy equation effectively:
  • Identify the inductance (\( L \)).
  • Measure or calculate the current (\( I \)) at the instant of interest.
  • Check how the energy relates to the total circuit energy \( U \).
Maximum Charge
The charge stored in the capacitor of an LC circuit is central to its functioning. This charge builds up as energy is transferred from the magnetic field of the inductor to the electric field of the capacitor. The formula for the electrical energy stored in the capacitor is \( U_C = \frac{1}{2} C V^2 \), where \( C \) is the capacitance and \( V \) is the voltage across the capacitor.
When the energy stored in the capacitor equals 25% of the total, we can use the relationship \( U_C = \frac{Q^2}{2C} \) to find the charge \( Q \) at that moment. Solving, we find \( Q = 0.5 Q_{max} \), where \( Q_{max} \) is the maximum charge the capacitor can hold.
Keep in mind:
  • The relationship \( Q = C V \) relates charge and voltage.
  • The charge at any instant can be determined from the energy stored.
  • Maximum charge is key to setting the boundaries of circuit capacity.
Maximum Current
In the oscillation of an LC circuit, the current through the inductor reaches a maximum when energy is entirely stored in the magnetic field of the inductor. The concept of maximum current, \( I_{max} \), is pivotal, as it characterizes the peak energy transfer rate.
When energy distribution indicates that 75% of the circuit's total energy is in the inductor, we can derive the relationship \( I = \sqrt{0.75} I_{max} \) or approximately \( 0.866 I_{max} \). This formula allows us to find the current at the time of energy measurement, in relation to its maximum value.
For practical application:
  • Use \( U_L = \frac{1}{2} L I^2 \) to understand energy at any current level.
  • Relate the current at any instant to maximum possible current \( I_{max} \).
  • Ensure inductors and components can handle peak currents specified by \( I_{max} \).

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Most popular questions from this chapter

What resistance \(R\) should be connected in series with an inductance \(L=220 \mathrm{mH}\) and capacitance \(C=12.0 \mu \mathrm{F}\) for the maximum charge on the capacitor to decay to \(99.0 \%\) of its initial value in 50.0 cycles? (Assume \(\left.\omega^{\prime} \approx \omega .\right)\)

an \(L C\) circuit oscillates at a frequency of \(10.4 \mathrm{kHz}\). (a) If the capacitance is \(340 \mu \mathrm{F},\) what is the inductance? (b) If the maximum current is \(7.20 \mathrm{~mA},\) what is the total energy in the circuit? (c) What is the maximum charge on the capacitor?

In an oscillating \(L C\) circuit in which \(C=4.00 \mu \mathrm{F},\) the maximum potential difference across the capacitor during the oscillations is \(1.50 \mathrm{~V}\) and the maximum current through the inductor is \(50.0 \mathrm{~mA}\). What are (a) the inductance \(L\) and (b) the frequency of the oscillations? (c) How much time is required for the charge on the capacitor to rise from zero to its maximum value?

An oscillating \(L C\) circuit consisting of a \(1.0 \mathrm{nF}\) capacitor and a \(3.0 \mathrm{mH}\) coil has a maximum voltage of \(3.0 \mathrm{~V}\). What are (a) the maximum charge on the capacitor, (b) the maximum current through the circuit, and (c) the maximum energy stored in the magnetic field of the coil?

In an oscillating series \(R L C\) circuit, show that \(\Delta U / U,\) the fraction of the energy lost per cycle of oscillation, is given to a close approximation by \(2 \pi R / \omega L\). The quantity \(\omega L / R\) is often called the \(Q\) of the circuit (for quality). A high-Q circuit has low resistance and a low fractional energy loss \((=2 \pi / Q)\) per cycle.

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