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A coil with an inductance of \(2.0 \mathrm{H}\) and a resistance of \(10 \Omega\) is suddenly connected to an ideal battery with \(\mathscr{E}=100 \mathrm{~V}\). (a) What is the equilibrium current? (b) How much energy is stored in the magnetic field when this current exists in the coil?

Short Answer

Expert verified
(a) 10 A; (b) 100 J

Step by step solution

01

Understand the Problem

We need to find two things: (a) the equilibrium current in the coil after it's connected to a 100 V battery and (b) the energy stored in the magnetic field when this current flows. The coil has an inductance of 2.0 H and a resistance of 10 Ω.
02

Calculate the Equilibrium Current

When the circuit reaches equilibrium, the inductor behaves like a simple resistor. Therefore, the voltage across the resistor-inductor series is given by Ohm's Law: \( V = IR \). The EMF of the battery is \( \mathscr{E} = 100 \text{ V} \). Thus, the equilibrium current \( I \) can be calculated as:\[ I = \frac{\mathscr{E}}{R} = \frac{100}{10} = 10 \text{ A} \]
03

Calculate Energy Stored in the Magnetic Field

The energy \( U \) stored in the magnetic field of an inductor is given by the formula:\[ U = \frac{1}{2}LI^2 \]where \( L = 2.0 \text{ H} \) and \( I = 10 \text{ A} \). Substituting these values, we find:\[ U = \frac{1}{2} \times 2.0 \times (10)^2 = 100 \text{ J} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium Current
The concept of equilibrium current is crucial when dealing with circuits involving inductors. When a circuit reaches an equilibrium, it means the system has settled into a stable state where currents and voltages are consistent over time. In the context of an inductor connected to a battery, initially, there is no current because the inductor resists changes in current. Over time, the inductor allows the current to increase. Eventually, the effect of the inductor fades as if it has become just a regular piece of wire.

At equilibrium, the inductor doesn't oppose the change anymore and behaves only like a resistor with resistance, letting the battery's voltage fully drop across the resistor. This is when Ohm's Law becomes helpful.
  • Voltage across inductor at equilibrium: Equivalent to zero
  • Voltage across resistor: Equals the battery's emf
Solving for the equilibrium current using Ohm's Law, we find that the equilibrium current is given by:
\[ I = \frac{\mathscr{E}}{R} \]
Plugging in the values, \( \mathscr{E} = 100 \text{ V} \) and \( R = 10 \Omega \), results in an equilibrium current of 10 A.
Ohm's Law
Ohm's Law is a foundational principle in the study of electrical circuits, establishing the simple relationship between voltage, current, and resistance. According to Ohm's Law, the current (\( I \)) flowing through a conductor between two points is directly proportional to the voltage (\( V \)) across the two points and inversely proportional to the resistance (\( R \)) of the conductor. The law is mathematically expressed as:
\[ V = IR \]
In the case of our coil, when the circuit reaches equilibrium, Ohm's Law helps determine the current flowing through the resistor part of the resistor-inductor series.

This simple relationship is instrumental in calculating the current because it allows us to find the current by rearranging the equation to:
  • \( I = \frac{V}{R} \)
By applying Ohm's Law in circuits with resistors and obtaining the equilibrium current in scenarios where an inductor is present, we can predict the behavior of various electrical components accurately in a circuit.
Energy Stored in Magnetic Field
In circuits containing inductors, an important aspect is the energy stored in the magnetic field. When an electric current passes through an inductor, it creates a magnetic field around it. The energy stored in this magnetic field is a critical feature of inductors, particularly in applications involving magnetic energy storage and electromagnetic devices. The formula used to determine the energy stored in the magnetic field within an inductor is:
\[ U = \frac{1}{2}LI^2 \]
Where \( U \) is the energy, \( L \) is the inductance, and \( I \) is the current.

Applying this to the given problem:
  • Inductance \( L = 2.0 \text{ H} \)
  • Current \( I = 10 \text{ A} \)
We calculate the energy to be:
\[ U = \frac{1}{2} \times 2.0 \times 10^2 \]
This results in the energy stored as \( 100 \text{ J} \). Such energy is harnessed in various applications like transformers and inductive kickbacks, showcasing the versatility and usefulness of magnetic fields in energetic systems.

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Most popular questions from this chapter

A toroidal inductor with an inductance of \(90.0 \mathrm{mH}\) encloses a volume of \(0.0200 \mathrm{~m}^{3}\). If the average energy density in the toroid is \(70.0 \mathrm{~J} / \mathrm{m}^{3},\) what is the current through the inductor?

A loop antenna of area \(2.00 \mathrm{~cm}^{2}\) and resistance \(5.21 \mu \Omega\) is perpendicular to a uniform magnetic field of magnitude \(17.0 \mu \mathrm{T}\). The field magnitude drops to zero in \(2.96 \mathrm{~ms} .\) How much thermal energy is produced in the loop by the change in field?

Two identical long wires of radius \(a=1.53 \mathrm{~mm}\) are parallel and carry identical currents in opposite directions. Their center-to-center separation is \(d=14.2 \mathrm{~cm} .\) Neglect the flux within the wires but consider the flux in the region between the wires. What is the inductance per unit length of the wires?

The magnetic field in the interstellar space of our galaxy has a magnitude of about \(10^{-10} \mathrm{~T}\). How much energy is stored in this field in a cube 10 light-years on edge? (For scale, note that the nearest star is 4.3 light-years distant and the radius of the galaxy is about \(8 \times 10^{4}\) light-years. \()\)

Coil 1 has \(L_{1}=25 \mathrm{mH}\) and \(N_{1}=100\) turns. Coil 2 has \(L_{2}=40 \mathrm{mH}\) and \(N_{2}=200\) turns. The coils are fixed in place; their mutual inductance \(M\) is \(3.0 \mathrm{mH}\). A \(6.0 \mathrm{~mA}\) current in coil 1 is changing at the rate of \(4.0 \mathrm{~A} / \mathrm{s}\). (a) What magnetic flux \(\Phi_{12}\) links coil \(1,\) and \((b)\) what self-induced emf appears in that coil? (c) What magnetic flux \(\Phi_{21}\) links coil \(2,\) and \((\mathrm{d})\) what mutually induced emf appears in that coil?

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