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What must be the magnitude of a uniform electric field if it is to have the same energy density as that possessed by a \(0.50 \mathrm{~T}\) magnetic field?

Short Answer

Expert verified
The magnitude of the electric field must be approximately \(470404.23 \mathrm{~N/C}\).

Step by step solution

01

Understanding Energy Density

Energy density of a field is the amount of energy stored per unit volume. For electric fields, the energy density is given by \( u_E = \frac{1}{2} \varepsilon_0 E^2 \), where \( E \) is the electric field's magnitude and \( \varepsilon_0 = 8.85 \times 10^{-12} \mathrm{~F/m} \) is the permittivity of free space. For magnetic fields, it is \( u_B = \frac{1}{2} \frac{B^2}{\mu_0} \), where \( B \) is the magnetic flux density and \( \mu_0 = 4\pi \times 10^{-7} \mathrm{~T \cdot m/A} \) is the permeability of free space.
02

Setting Up the Equality of Energy Densities

To find the electric field magnitude with an energy density equal to the magnetic field's, set the energy densities equal: \( \frac{1}{2} \varepsilon_0 E^2 = \frac{1}{2} \frac{B^2}{\mu_0} \). Here, \( B = 0.50 \mathrm{~T} \).
03

Solving for Electric Field Magnitude

Simplifying the equality, we have \( \varepsilon_0 E^2 = \frac{B^2}{\mu_0} \). Solving for \( E \), we get \( E = \sqrt{\frac{1}{\varepsilon_0} \cdot \frac{B^2}{\mu_0}} \). Plugging in the values, \( E = \sqrt{\frac{1}{8.85 \times 10^{-12}} \cdot \frac{(0.5)^2}{4\pi \times 10^{-7}}} \).
04

Calculating the Electric Field Magnitude

Calculate \( E = \sqrt{\frac{1}{8.85 \times 10^{-12}} \cdot \frac{0.25}{4\pi \times 10^{-7}}} \). Simplifying yields \( E \approx \sqrt{\frac{0.25}{3.54 \times 10^{-18}}} \approx 470404.23 \mathrm{~N/C} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Density
Understanding energy density is crucial when exploring fields like electric and magnetic fields. Energy density refers to the quantity of energy stored in a given unit of space. It's like comparing how much 'stuff' you can pack into a box, but in this case, it's energy.

For electric fields, you can calculate energy density using the formula:
  • \( u_E = \frac{1}{2} \varepsilon_0 E^2 \)
This means the energy density is influenced by the square of the electric field \(E\) and the permittivity of free space \(\varepsilon_0\). This formula highlights how a stronger electric field leads to more energy stored.

In magnetic fields, energy density is calculated as:
  • \( u_B = \frac{1}{2} \frac{B^2}{\mu_0} \)
The equation emphasizes the interaction between the magnetic flux density \(B\) and the permeability of free space \(\mu_0\). Understanding energy density can help to determine how you compare these fields in terms of energy stored.
Permittivity of Free Space
Permittivity of free space, denoted as \(\varepsilon_0\), is an essential constant in physics, particularly electromagnetism. It is a measure of how much electric field is permittable in a vacuum without any matter. Think of it as the degree to which electric field lines can spread in a vacuum.

This constant plays a vital role in calculating the electric field's energy density using the formula:
  • \( u_E = \frac{1}{2} \varepsilon_0 E^2 \)
In this context, \(\varepsilon_0\) essentially modulates how much energy can be stored in the electric field per unit volume. The value of permittivity of free space is approximately \(8.85 \times 10^{-12}\) F/m (farads per meter).

This fundamental constant is crucial for equations involving capacitors and electrostatic fields, allowing scientists and engineers to predict and measure electric field behaviors effectively.
Magnetic Flux Density
Magnetic flux density, symbolized by \(B\), is another cornerstone concept in electromagnetism, describing how dense the magnetic field lines are in a given area. You can think of it like trying to determine how many magnetic 'arrows' you have in a particular space — the more arrows, the denser the field.

The formula for magnetic field energy density is represented as:
  • \( u_B = \frac{1}{2} \frac{B^2}{\mu_0} \)
Here, \(B\) is crucial as it determines how much energy is stored in the magnetic field. A stronger magnetic flux density signifies a stronger magnetic field and thus, a higher energy density.

This concept is essential, especially in the design of electromagnets and for understanding phenomena such as magnetic induction, where changes in magnetic flux density can induce electric currents.
Permeability of Free Space
The permeability of free space, denoted by \(\mu_0\), is pivotal in understanding magnetic fields in physics. It quantifies the extent to which a magnetic field can penetrate free space, analogous to how air allows sound waves to travel.

In the equation for energy density:
  • \( u_B = \frac{1}{2} \frac{B^2}{\mu_0} \)
\(\mu_0\) acts as a scaling factor that affects how energy density is computed in magnetic fields. The smaller \(\mu_0\), the more influence \(B\) has on energy density, and vice versa. Its approximate value is \(4\pi \times 10^{-7}\) T·m/A (tesla meter per ampere).

Permeability of free space is fundamental in studying circuits, transformers, and electromagnetic waves, offering insights into how magnetic fields interact with materials and structures.

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Most popular questions from this chapter

A uniform magnetic field \(\vec{B}\) is perpendicular to the plane of a circular loop of diameter \(10 \mathrm{~cm}\) formed from wire of diameter \(2.5 \mathrm{~mm}\) and resistivity \(1.69 \times\) \(10^{-8} \Omega \cdot \mathrm{m} .\) At what rate must the magnitude of \(\vec{B}\) change to induce a 10 A current in the loop?

A toroidal inductor with an inductance of \(90.0 \mathrm{mH}\) encloses a volume of \(0.0200 \mathrm{~m}^{3}\). If the average energy density in the toroid is \(70.0 \mathrm{~J} / \mathrm{m}^{3},\) what is the current through the inductor?

A circular coil has a \(10.0 \mathrm{~cm}\) radius and consists of 30.0 closely wound turns of wire. An externally produced magnetic field of magnitude \(2.60 \mathrm{mT}\) is perpendicular to the coil. (a) If no current is in the coil, what magnetic flux links its turns? (b) When the current in the coil is \(3.80 \mathrm{~A}\) in a certain direction, the net flux through the coil is found to vanish. What is the inductance of the coil?

A coil with an inductance of \(2.0 \mathrm{H}\) and a resistance of \(10 \Omega\) is suddenly connected to an ideal battery with \(\mathscr{E}=100 \mathrm{~V}\). At \(0.10 \mathrm{~s}\) after the connection is made, what is the rate at which (a) energy is being stored in the magnetic field, (b) thermal energy is appearing in the resistance, and (c) energy is being delivered by the battery?

Two long, parallel copper wires of diameter \(2.5 \mathrm{~mm}\) carry currents of 10 A in opposite directions. (a) Assuming that their central axes are \(20 \mathrm{~mm}\) apart, calculate the magnetic flux per meter of wire that exists in the space between those axes. (b) What percentage of this flux lies inside the wires? (c) Repeat part (a) for parallel currents.

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