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Find (a) "north cross west," (b) "down dot south," (c) "east cross up," (d) "west dot west," and (e) "south cross south." Let each "vector" have unit magnitude.

Short Answer

Expert verified
(a) -\( \hat{k} \), (b) 0, (c) -\( \hat{j} \), (d) 1, (e) \( \vec{0} \).

Step by step solution

01

Understanding Directional Vectors

In this problem, we're dealing with directional vectors where each direction (north, south, east, west, up, down) has a unit magnitude. This means that each vector is represented as a unit vector on a coordinate system. For convenience, we can represent north as \( \hat{i} \), east as \( \hat{j} \), up as \( \hat{k} \), and so on, where each of these vectors has a length of 1.
02

Calculate "north cross west"

The cross product of two vectors gives a vector that is perpendicular to both. If we specify north as \( \hat{j} \) and west as \( -\hat{i} \), then \( \hat{j} \times -\hat{i} = -\hat{k} \). Therefore, "north cross west" results in the vector \( -\hat{k} \).
03

Calculate "down dot south"

The dot product of two perpendicular unit vectors is 0. So, if down is -\( \hat{k} \) and south is -\( \hat{j} \), then \( (-\hat{k}) \cdot (-\hat{j}) = 0 \). Hence, "down dot south" is 0.
04

Calculate "east cross up"

For this cross product, we use east as \( \hat{i} \) and up as \( \hat{k} \). The result, \( \hat{i} \times \hat{k} = -\hat{j} \), indicates "east cross up" is \( -\hat{j} \).
05

Calculate "west dot west"

The dot product of a unit vector with itself is 1. If west is -\( \hat{i} \), then \( (-\hat{i}) \cdot (-\hat{i}) = 1 \). Therefore, "west dot west" is 1.
06

Calculate "south cross south"

The cross product of any vector with itself is always the zero vector. If south is -\( \hat{j} \), then \( (-\hat{j}) \times (-\hat{j}) = \vec{0} \). Hence, "south cross south" is \( \vec{0} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Directional Vectors
Directional vectors are fundamental in understanding the movements in 3D space. When you think about directions like north, south, east, west, up, and down, you can imagine these as arrows pointing in specific directions on a coordinate system. Each of these directions can be represented by unit vectors, which have a length of one.
  • North: Typically represented as \( \hat{j} \).
  • East: Represented as \( \hat{i} \).
  • Up: Shown as \( \hat{k} \).
  • South: Opposite of north, as \( -\hat{j} \).
  • West: Opposite of east, as \( -\hat{i} \).
  • Down: Opposite of up, as \( -\hat{k} \).
Using these vectors on a coordinate system allows us to translate physical directions into mathematical terms, which can then be manipulated using vector operations.
Cross Product
The cross product is a powerful tool in vector operations. When you take the cross product of two vectors, the result is another vector that is perpendicular to the plane formed by the original two vectors. This operation is very useful in physics and engineering to find vectors orthogonal to given planes.
When calculating the cross product:
  • The order matters: \( \vec{A} \times \vec{B} eq \vec{B} \times \vec{A} \).
  • The result is a vector: For vectors \( \hat{j} \) (north) and \( -\hat{i} \) (west), their cross product is \( -\hat{k} \). This vector points in the direction perpendicular to both north and west.
  • If the same direction vectors are used, like \( \vec{C} \times \vec{C} \), the result is the zero vector \( \vec{0} \), as there’s no defined plane.
Remember, the cross product is crucial when needing to determine orientation in space, like when assessing torques or magnetic forces.
Dot Product
The dot product is one of the most straightforward vector operations. It allows you to measure how much one vector extends in the direction of another. The dot product turns two vectors into a scalar (a single number), which can be particularly useful for calculating work done or projection calculations.
To compute the dot product:
  • The product is zero if vectors are perpendicular, as they have no common direction. For instance, \( (-\hat{k}) \cdot (-\hat{j}) = 0 \).
  • It's equal to the product of the magnitudes of the vectors times the cosine of the angle between them. For vectors in the same direction, the dot product is the square of their magnitude. For \( -\hat{i} \), the dot product with itself is \( 1 \).
The dot product also helps in determining the angle between vectors and checking for orthogonality. If the result is zero, the vectors are perpendicular.
Unit Vectors
Unit vectors are the building blocks of vector mathematics. Having a length of one, unit vectors provide the direction without affecting the magnitude of calculations. They serve as the default vectors along the coordinate axes, playing a crucial role in vector normalization.
  • A unit vector in any direction maintains its magnitude as one.
  • They simplify vector expressions and calculations. When you represent complex vectors using unit vectors, it allows for easier operations such as addition and scalar multiplication.
  • In 3D space, the primary unit vectors include \( \hat{i} \), \( \hat{j} \), and \( \hat{k} \).
By breaking vectors into components along these unit vectors, it becomes more manageable to solve vector problems and perform operations.

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Most popular questions from this chapter

A golfer takes three putts to get the ball into the hole. The first putt displaces the ball \(3.66 \mathrm{~m}\) north, the second \(1.83 \mathrm{~m}\) southeast, and the third \(0.91 \mathrm{~m}\) southwest. What are (a) the magnitude and (b) the direction of the displacement needed to get the ball into the hole on the first putt?

Express the following angles in radians: (a) \(20.0^{\circ},\) (b) \(50.0^{\circ}\), (c) \(100^{\circ} .\) Convert the following angles to degrees: (d) \(0.330 \mathrm{rad}\), (e) \(2.10 \mathrm{rad},\) (f) 7.70 rad.

A vector \(\vec{B},\) with a magnitude of \(8.0 \mathrm{~m},\) is added to a vector \(\vec{A},\) which lies along an \(x\) axis. The sum of these two vectors is a third vector that lies along the \(y\) axis and has a magnitude that is twice the magnitude of \(\vec{A}\). What is the magnitude of \(\vec{A}\) ?

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A car is driven east for a distance of \(50 \mathrm{~km},\) then north for \(30 \mathrm{~km},\) and then in a direction \(30^{\circ}\) east of north for \(25 \mathrm{~km} .\) Sketch the vector diagram and determine (a) the magnitude and (b) the angle of the car's total displacement from its starting point.

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