Chapter 3: Problem 47
Vectors \(\vec{A}\) and \(\vec{B}\) lie in an \(x y\) plane. \(\vec{A}\) has magnitude 8.00 and angle \(130^{\circ} ; \vec{B}\) has components \(B_{x}=-7.72\) and \(B_{y}=-9.20\) What are the angles between the negative direction of the \(y\) axis and (a) the direction of \(\vec{A},\) (b) the direction of the product \(\vec{A} \times \vec{B},\) and \((\mathrm{c})\) the direction of \(\vec{A} \times(\vec{B}+3.00 \hat{\mathrm{k}}) ?\)
Short Answer
Step by step solution
Calculate the angle for vector A
Calculate the cross product \( \vec{A} \times \vec{B} \)
Angle determination for \( \vec{A} \times \vec{B} \)
Calculate the cross product \( \vec{A} \times (\vec{B} + 3.00 \hat{k}) \)
Determine angle for \( \vec{A} \times (\vec{B} + 3.00 \hat{k}) \)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
An essential property of the cross product is that it results in a vector, unlike the dot product, which gives a scalar. To calculate it, use the determinant of a matrix composed of unit vectors and the components of \( \vec{A} \) and \( \vec{B} \):
- Start with a matrix:
\[ \vec{A} \times \vec{B} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \ a_1 & a_2 & a_3 \ b_1 & b_2 & b_3 \end{vmatrix} \] - Expand the determinant to find the vector components.
- The result gives you a new vector in the form \( c_1\hat{i} + c_2\hat{j} + c_3\hat{k} \).
Angle Calculation
When dealing with vector angles:
- Know the reference axis from which you measure your angle.
- If a vector \( \vec{A} \) makes an angle \( \theta_A \) with the x-axis, the angle from another axis, like the y-axis, might require subtracting or adding 90 degrees, depending on the direction.
- In cases where you need the angle between one of the vector's directions and another axis, trigonometry is your friend. Use \( \tan^{-1}(\frac{opposite}{adjacent}) \) to find angles in a right triangle formed by vector components.
Vector Components
To find components of a vector, especially when you know the magnitude and angle:
- Use trigonometry: \( A_x = A \cos(\theta) \) and \( A_y = A \sin(\theta) \) for a vector in 2D.
- In 3D, add the z-component if necessary: \( A_z = A \tan(\theta) \) if \( \theta \) is between the vector and the x-y plane.
- Each component represents the influence of the vector along a particular axis and can vary based on the angle and the plane in the question.
3D Vectors
To handle 3D vectors:
- Consider each component: In a vector \( \vec{V} = v_x\hat{i} + v_y\hat{j} + v_z\hat{k} \), each term represents the vector's projection along the associated axis.
- Represent forces or motions that require accounting for all three spatial dimensions.
- Mathematical operations like addition, subtraction, and especially the cross product require careful attention to each component’s interaction with others.