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Four \(18.0 \Omega\) resistors are connected in parallel across a \(25.0 \mathrm{~V}\) ideal battery. What is the current through the battery?

Short Answer

Expert verified
The current through the battery is approximately 5.56 A.

Step by step solution

01

Understand the Formula for Resistors in Parallel

The total or equivalent resistance \( R_\text{eq} \) for resistors in parallel is calculated using the formula: \( \frac{1}{R_\text{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \ldots \), where each \( R \) is the resistance of an individual resistor. Since all resistors have the same resistance of \( 18.0 \Omega \), the formula simplifies to \( \frac{1}{R_\text{eq}} = \frac{1}{18.0} + \frac{1}{18.0} + \frac{1}{18.0} + \frac{1}{18.0} \).
02

Calculate the Equivalent Resistance

Plug in the values into the formula: \( \frac{1}{R_\text{eq}} = \frac{4}{18.0} \). Simplify this to get \( R_\text{eq} = \frac{18.0}{4} \). Therefore, \( R_\text{eq} = 4.5 \Omega \).
03

Use Ohm's Law to Find the Total Current

Ohm's Law states \( V = I \cdot R \), where \( V \) is the voltage, \( I \) is the current, and \( R \) is the resistance. We rearrange it to find the current: \( I = \frac{V}{R} \). Substituting the known values, \( I = \frac{25.0\, \text{V}}{4.5\, \Omega} \).
04

Calculate the Current

Divide the voltage by the equivalent resistance to find the current: \( I = \frac{25.0}{4.5} \). This results in \( I \approx 5.56 \text{ A} \). So, the current through the battery is approximately \( 5.56 \) amperes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ohm's Law
Ohm's Law is a basic and essential principle in electronics and electrical engineering. It describes the relationship between voltage, current, and resistance in an electrical circuit. More specifically, it states that the voltage across a conductor is directly proportional to the current flowing through it, given by the formula:\[ V = I \times R \]where:
  • \( V \) is the voltage across the conductor in volts (V),
  • \( I \) is the current through the conductor in amperes (A), and
  • \( R \) is the resistance of the conductor in ohms (\( \Omega \)).
To find any one of these values, you can rearrange the formula. For instance, to find the current, use:\[ I = \frac{V}{R} \]When solving problems involving circuits, like calculating the current through a battery, understanding Ohm's Law is crucial. It helps you see how changes in resistance or voltage affect the current in the circuit. Whenever you have the voltage and the resistance, you can always calculate the current using this simple relationship.
Equivalent Resistance
When dealing with multiple resistors in a circuit, especially in complex configurations, calculating the equivalent resistance simplifies analysis. For resistors arranged in parallel, the equivalent resistance \( R_{eq} \) is calculated using the formula:\[ \frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \ldots \]In parallel circuits, the total resistance is always less than the smallest individual resistance. In our exercise, where we have four resistors each with a resistance of \( 18.0 \Omega \), the equivalent resistance can be found by applying the formula:\[ \frac{1}{R_{eq}} = \frac{1}{18.0} + \frac{1}{18.0} + \frac{1}{18.0} + \frac{1}{18.0} = \frac{4}{18.0} \]Ultimately, solving this gives us:\[ R_{eq} = \frac{18.0}{4} = 4.5 \Omega \]This value helps in further calculations, such as determining the total current in the circuit using Ohm's Law.
Current Calculation
Current calculation is often the final step in analyzing a circuit. Once you know the voltage across and the equivalent resistance of a circuit, you can calculate the total current flowing through it. Again, Ohm's Law becomes your best friend. For our case:\[ I = \frac{V}{R_{eq}} \]With a provided voltage of \( 25.0 \text{ V} \) and an equivalent resistance of \( 4.5 \Omega \), the calculation becomes straightforward:\[ I = \frac{25.0}{4.5} \approx 5.56 \text{ A} \]So, the current through the battery is approximately \( 5.56 \text{ A} \). This calculation reinforces the fact that with lower equivalent resistance, larger currents can flow through a circuit for a given voltage. Comprehensive understanding of this process is important for predicting how circuits will behave and for designing safe electrical systems.

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Most popular questions from this chapter

A certain car battery with a \(12.0 \mathrm{~V} \mathrm{emf}\) has an initial charge of \(120 \mathrm{~A} \cdot \mathrm{h}\). Assuming that the potential across the terminals stays constant until the battery is completely discharged, for how many hours can it deliver energy at the rate of \(100 \mathrm{~W} ?\)

The starting motor of a car is turning too slowly, and the mechanic has to decide whether to replace the motor, the cable, or the battery. The car's manual says that the \(12 \mathrm{~V}\) battery should have no more than \(0.020 \Omega\) internal resistance, the motor no more than \(0.200 \Omega\) resistance, and the cable no more than \(0.040 \Omega\) resistance. The mechanic turns on the motor and measures \(11.4 \mathrm{~V}\) across the battery, \(3.0 \mathrm{~V}\) across the cable, and a current of \(50 \mathrm{~A}\). Which part is defective?

What multiple of the time constant \(\tau\) gives the time taken by an initially uncharged capacitor in an \(R C\) series circuit to be charged to \(99.0 \%\) of its final charge?

A total resistance of \(3.00 \Omega\) is to be produced by connecting an unknown resistance to a \(12.0 \Omega\) resistance. (a) What must be the value of the unknown resistance, and (b) should it be connected in series or in parallel?

A capacitor with an initial potential difference of \(100 \mathrm{~V}\) is discharged through a resistor when a switch between them is closed at \(t=0 .\) At \(t=10.0 \mathrm{~s},\) the potential difference across the capacitor is \(1.00 \mathrm{~V}\). (a) What is the time constant of the circuit? (b) What is the potential difference across the capacitor at \(t=17.0 \mathrm{~s} ?\)

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