Chapter 26: Problem 47
A heating element is made by maintaining a potential difference of \(75.0 \mathrm{~V}\) across the length of a Nichrome wire that has a \(2.60 \times 10^{-6} \mathrm{~m}^{2}\) cross section. Nichrome has a resistivity of \(5.00 \times 10^{-7} \Omega \cdot \mathrm{m} .\) (a) If the element dissipates \(5000 \mathrm{~W}\), what is its length? (b) If \(100 \mathrm{~V}\) is used to obtain the same dissipation rate, what should the length be?
Short Answer
Step by step solution
Understanding the Problem
Using Power and Ohm's Law
Calculating Resistance for 75 V
Finding Length for 75 V
Repeating For 100 V
Finding Length for 100 V
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ohm's Law
- \( V = IR \)
For example, if you know the voltage and resistance, you can rearrange the formula to calculate the current:
- \( I = \frac{V}{R} \)
- \( P = VI \)
- \( V = \frac{P}{I} \)
Nichrome Wire
- High resistivity: This makes it better for generating heat when electrical current passes through.
- Corrosion resistance: It withstands damage from oxidation, maintaining its performance over time.
- Stability: It remains stable even at the high temperatures it generates due to its high melting point.
- \( R = \frac{\rho L}{A} \)
Power Dissipation
Power can be calculated using different variations, depending on the known quantities, with the most common being:
- \( P = VI \surmise\)
- \( P = I^2R \surmise\)
- \( P = \frac{V^2}{R} \surmise\)
Resistivity
It is denoted by the symbol \( \rho \) and is expressed in ohm-meters \( \Omega \cdot m \).
- Lower resistivity indicates a material that easily allows electric current to flow.
- Higher resistivity means the material resists the flow of electricity to a greater extent.
- The relationship between resistance, resistivity, length, and cross-sectional area is given by:\( R = \frac{\rho L}{A} \)