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What is the current in a wire of radius \(R=3.40 \mathrm{~mm}\) if the magnitude of the current density is given by (a) \(J_{a}=J_{0} r / R\) and (b) \(J_{b}=J_{0}(1-r / R),\) in which \(r\) is the radial distance and \(J_{0}=5.50 \times 10^{4} \mathrm{~A} / \mathrm{m}^{2} ?\) (c) Which function maximizes the current density near the wire's surface?

Short Answer

Expert verified
(a) \( I_a = \frac{2\pi J_0 R^2}{3} \); (b) \( I_b = \frac{\pi J_0 R^2}{3} \); (c) \( J_a \) maximizes the surface current density.

Step by step solution

01

Understanding Current Density

Current density is a measure of the electric current per unit area of cross-section. In this exercise, we are given two different current density functions: \(J_a = J_0 \frac{r}{R}\) and \(J_b = J_0(1 - \frac{r}{R})\). The task is to calculate the total current \(I\) in the wire for each of these density functions, and to determine which function results in a higher current near the wire's surface.
02

Calculate Total Current For First Density Function (J_a)

The current \(I\) is calculated by integrating the current density over the cross-sectional area of the wire. For \(J_a\), this will be: \[ I_a = \int_0^R J_a \, 2\pi r \, dr = \int_0^R J_0 \frac{r}{R} \, 2\pi r \, dr. \]Substituting the given values, we have:\[ I_a = \frac{2\pi J_0}{R} \int_0^R r^2 \, dr. \]Evaluating this integral gives:\[ I_a = \frac{2\pi J_0}{R} \left[ \frac{r^3}{3} \right]_0^R = \frac{2\pi J_0}{R} \cdot \frac{R^3}{3} = \frac{2\pi J_0 R^2}{3}. \]
03

Calculate Total Current For Second Density Function (J_b)

For \(J_b\), calculate the current as:\[ I_b = \int_0^R J_b \, 2\pi r \, dr = \int_0^R J_0 (1 - \frac{r}{R}) \, 2\pi r \, dr. \]Simplify and evaluate:\[ I_b = 2\pi J_0 \int_0^R \left(r - \frac{r^2}{R}\right) dr = 2\pi J_0 \left( \frac{r^2}{2} - \frac{r^3}{3R} \right)_0^R. \]Solving this gives:\[ I_b = 2\pi J_0 \left( \frac{R^2}{2} - \frac{R^2}{3} \right) = 2\pi J_0 \left( \frac{3R^2}{6} - \frac{2R^2}{6} \right) = \frac{\pi J_0 R^2}{3}. \]
04

Compare and Analyze Results

The calculated total currents are \( I_a = \frac{2\pi J_0 R^2}{3} \) for the first density function and \( I_b = \frac{\pi J_0 R^2}{3} \) for the second. Clearly, \( I_a \) is greater than \( I_b \). This means the first function, \( J_a \), gives a higher total current.
05

Determine Function Maximizing Current Density Near Surface

Near the surface of the wire, where \( r \approx R \), the function \( J_a = J_0 \frac{r}{R} \) is maximized as \( J_a \to J_0 \) when \( r = R \). Meanwhile, \( J_b = J_0(1 - \frac{r}{R}) \to 0 \) as \( r \to R \). Thus, \( J_a \) maximizes the current density near the wire's surface.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Current
Electric current is the flow of electric charge through a conductor. It is measured in amperes (A). Current can be imagined like water flowing through a pipe; the faster the flow, the higher the current.
In conducting materials like metals, electric currents are carried by electrons moving through the material. The direction of current is defined by the flow of positive charges, even though it's typically electrons (with a negative charge) that move.
The relationship between electric current and current density is an important aspect to consider. Here, the current density (\( J \)) describes how much current passes through a unit area of a wire. Therefore, it's the electric current per unit area, expressed in amperes per square meter (A/m²). Current density allows us to determine the distribution of electric current flow across various sections of a conductor, especially when it isn't uniform.
Integration in Physics
Integration is a fundamental concept in physics used to calculate quantities like area, volume, work, and more from variable densities or distributions.
In the case of calculating total current from current density, integration helps sum up infinitesimally small elements of current over a cross-sectional area. It allows us to compute the entire current flowing through a wire when only the current density is known. The integration involves setting up an integral to add up all the current elements defined by the current density formula:
  • For a function like \( J_a = J_0 \frac{r}{R} \), the integration \( I_a = \int_0^R J_a \, 2\pi r \, dr \) adds up the infinitesimal currents over the radius of the wire.
  • Larger integration limits or different density functions result in different total currents.
Through integration, abstract mathematical descriptions become precise physical quantities.
Radial Distance
Radial distance in this context refers to the distance from the center of the wire to a specific point within it. Imagine slicing the wire vertically; radial distance would mark how far you are from the centerline.
Understanding radial distance is crucial when considering how current density varies across the wire's cross-section. For instance, in the case of the current density function \( J_a = J_0 \frac{r}{R} \), the current density increases linearly with radial distance, meaning it's lower at the center and higher at the surface.
The radial concept helps us comprehend why different formulas lead to different current distributions and thereby influence the total current through varying areas of cross-section.
Using these mathematical concepts, we can conclude which points in the wire maximize or minimize current density. With \( J_b = J_0(1 - \frac{r}{R}) \), the maximum density is at the center and decreases towards the outside, emphasizing how essential radial distance is in defining the behavior of current within the wire. Understanding this helps in designing and analyzing electrical systems.

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Most popular questions from this chapter

Two conductors are made of the same material and have the same length. Conductor \(A\) is a solid wire of diameter \(1.0 \mathrm{~mm} .\) Conductor \(B\) is a hollow tube of outside diameter \(2.0 \mathrm{~mm}\) and inside diameter \(1.0 \mathrm{~mm} .\) What is the resistance ratio \(R_{A} / R_{B}\), measured between their ends?

The legend that Benjamin Franklin flew a kite as a storm approached is only a legend-he was neither stupid nor suicidal. Suppose a kite string of radius \(2.00 \mathrm{~mm}\) extends directly upward by \(0.800 \mathrm{~km}\) and is coated with a \(0.500 \mathrm{~mm}\) layer of water having resistivity \(150 \Omega \cdot \mathrm{m} .\) If the potential difference between the two ends of the string is \(160 \mathrm{MV},\) what is the current through the water layer? The danger is not this current but the chance that the string draws a lightning strike, which can have a current as large as 500000 A (way beyond just being lethal).

A 1250 W radiant heater is constructed to operate at \(115 \mathrm{~V}\). (a) What is the current in the heater when the unit is operating? (b) What is the resistance of the heating coil? (c) How much thermal energy is produced in \(1.0 \mathrm{~h} ?\)

A cylindrical resistor of radius \(5.0 \mathrm{~mm}\) and length \(2.0 \mathrm{~cm}\) is made of material that has a resistivity of \(3.5 \times 10^{-5} \Omega \cdot \mathrm{m} .\) What are (a) the magnitude of the current density and (b) the potential difference when the energy dissipation rate in the resistor is \(1.0 \mathrm{~W} ?\)

A caterpillar of length \(4.0 \mathrm{~cm}\) crawls in the direction of electron drift along a 5.2-mm-diameter bare copper wire that carries a uniform current of 12 A. (a) What is the potential difference between the two ends of the caterpillar? (b) Is its tail positive or negative relative to its head? (c) How much time does the caterpillar take to crawl \(1.0 \mathrm{~cm}\) if it crawls at the drift speed of the electrons in the wire? (The number of charge carriers per unit volume is \(8.49 \times 10^{28} \mathrm{~m}^{-3}\).

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