Chapter 23: Problem 45
Two charged concentric spherical shells have radii \(10.0 \mathrm{~cm}\) and \(15.0 \mathrm{~cm} .\) The charge on the inner shell is \(4.00 \times 10^{-8} \mathrm{C},\) and that on the outer shell is \(2.00 \times 10^{-8} \mathrm{C}\). Find the electric field (a) at \(r=12.0 \mathrm{~cm}\) and (b) at \(r=20.0 \mathrm{~cm}\)
Short Answer
Step by step solution
Identify the Problem
Understand the Concept of Electric Field Due to a Spherical Shell
Calculate the Electric Field at 12 cm
Analyze Field at 20 cm
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Coulomb's Law
- Coulomb's Law helps us find the electric field around point charges.
- The law only applies to point charges, but spherical charges can often be treated as point charges when viewed from outside.
Concentric Spherical Shells
- The electric field inside a conducting shell is zero due to symmetry — the charges spread out uniformly on the surface.
- Each shell can be considered separately when calculating electric fields, using properties from Gauss's Law and Coulomb's Law.
Charge Distribution
- For conductive materials, any excess charge spreads out uniformly on the surface.
- This property simplifies electric field calculations since, outside the shell, the charges can be treated as a point charge at the center.
Gauss's Law
- This law elegantly handles problems with high symmetry, like concentric spherical shells.
- By selecting a spherical gaussian surface that mirrors this symmetry, calculations for fields become straightforward.