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An electric dipole consists of charges \(+2 e\) and \(-2 e\) separated by \(0.78 \mathrm{nm}\). It is in an electric field of strength \(3.4 \times 10^{6} \mathrm{~N} / \mathrm{C}\). Calculate the magnitude of the torque on the dipole when the dipole moment is (a) parallel to, (b) perpendicular to, and (c) antiparallel to the electric field.

Short Answer

Expert verified
(a) 0 Nm, (b) \(8.49 \times 10^{-23}\) Nm, (c) 0 Nm.

Step by step solution

01

Define the dipole moment

The dipole moment \( p \) is defined as the product of the charge \( q \) and the separation distance \( d \) between the charges. For our dipole, \( q = 2e \), where \( e \) is the elementary charge (\( 1.6 \times 10^{-19} \) C), and \( d = 0.78 \times 10^{-9} \) m. The dipole moment is given by \( p = q \cdot d = 2e \times 0.78 \times 10^{-9} \). Calculate \( p \).
02

Calculation of dipole moment

Substitute the values: \( p = 2 \times (1.6 \times 10^{-19}) \times 0.78 \times 10^{-9} \). Calculate \( p = 2.496 \times 10^{-29} \text{ C} \cdot \text{m} \).
03

Torque on a parallel dipole

When the dipole moment is parallel to the electric field, the angle \( \theta = 0^{\circ} \). The torque \( \tau = pE\sin\theta \). For \( \theta = 0^{\circ} \), \( \sin 0^{\circ} = 0 \). Hence, \( \tau = pE\sin 0 = 0 \).
04

Torque on a perpendicular dipole

When the dipole is perpendicular to the electric field, \( \theta = 90^{\circ} \). Calculate the torque using \( \tau = pE\sin 90^{\circ} \). Here, \( \sin 90^{\circ} = 1 \), so \( \tau = pE \). \( \tau = 2.496 \times 10^{-29} \times 3.4 \times 10^{6} = 8.4864 \times 10^{-23} \text{ Nm} \).
05

Torque on an antiparallel dipole

When the dipole moment is antiparallel to the electric field, \( \theta = 180^{\circ} \). The torque is \( \tau = pE\sin 180^{\circ} \). However, \( \sin 180^{\circ} = 0 \). Hence, \( \tau = 0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dipole Moment
An electric dipole consists of two equal but opposite charges separated by a specific distance. The dipole moment (\( p \)) is a vector quantity that characterizes the dipole. It provides both the magnitude and the direction of the dipole's ability to produce electric fields. The dipole moment is calculated as the product of the charge (\( q \)) and the separation distance (\( d \)) between charges, given by \( p = q \cdot d \).
For example, let's consider a dipole composed of charges \( +2e \) and \( -2e \), where \( e \) is the elementary charge (\( 1.6 \times 10^{-19} \text{ C} \)) and the distance separating them is \( 0.78 \times 10^{-9} \text{ m} \).
  • Charge, \( q = 2 \times (1.6 \times 10^{-19}) \text{ C} \)
  • Distance, \( d = 0.78 \times 10^{-9} \text{ m} \)
The dipole moment can be calculated as \( p = 2 \times (1.6 \times 10^{-19}) \times 0.78 \times 10^{-9} = 2.496 \times 10^{-29} \text{ C} \cdot \text{m} \).
The dipole moment points from the negative to the positive charge and its magnitude can help us understand the interaction of the dipole with external electric fields.
Torque on Dipole
Torque measures the tendency of a force to rotate an object about an axis. In the context of a dipole placed in an external electric field, the torque (\( \tau \)) depends on both the dipole moment and its orientation with respect to the field.
The torque is given by the formula:\[\tau = pE\sin\theta\]where \( p \) is the dipole moment, \( E \) is the strength of the electric field, and \( \theta \) is the angle between the dipole moment and the electric field.
  • **Parallel orientation (\( \theta = 0^{\circ} \))**: When the dipole is parallel to the electric field, \( \sin 0^{\circ} = 0 \), resulting in zero torque (\( \tau = 0 \)).
  • **Perpendicular orientation (\( \theta = 90^{\circ} \))**: When the dipole is perpendicular to the electric field, \( \sin 90^{\circ} = 1 \), the torque is maximized and given by \( \tau = pE \). For our example, this results in \( \tau = 2.496 \times 10^{-29} \times 3.4 \times 10^{6} = 8.4864 \times 10^{-23} \text{ Nm} \).
  • **Antiparallel orientation (\( \theta = 180^{\circ} \))**: When the dipole is antiparallel, \( \sin 180^{\circ} = 0 \), so the torque is again zero (\( \tau = 0 \)).
Thus, the orientation of the dipole relative to the electric field is crucial in determining the torque experienced by the dipole.
Electric Field
The electric field (\( E \)) is a vector field that surrounds electric charges and exerts force on other charges within the field. It is usually described as the force per unit charge, implying that any charged particle placed in the field would experience a force proportional to its charge.
The strength of the electric field is measured in units of newtons per coulomb (\( \text{N/C} \)) and is often a crucial factor in determining how charged objects like dipoles behave when exposed to it. The uniform electric field can affect the orientation and stability of an electric dipole, and this is characterized by the torque experienced by the dipole.
In our scenario, the given electric field strength is \( 3.4 \times 10^{6} \text{ N/C} \). This strong field can significantly influence the dipole's behavior:
  • When aligning with the electric field (\( \theta = 0^{\circ} \) or \( \theta = 180^{\circ} \)), the dipole experiences no torque.
  • When perpendicular (\( \theta = 90^{\circ} \)), the electric field induces a maximum torque, rotating the dipole to align with the field.
Understanding electric fields is important, as they can determine the dynamics and equilibrium states of electric dipoles in space.

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Most popular questions from this chapter

At some instant the velocity components of an electron moving between two charged parallel plates are \(v_{x}=1.5 \times 10^{5} \mathrm{~m} / \mathrm{s}\) and \(v_{y}=3.0 \times 10^{3} \mathrm{~m} / \mathrm{s} .\) Suppose the electric field between the plates is uniform and given by \(\vec{E}=(120 \mathrm{~N} / \mathrm{C}) \hat{\mathrm{j}} .\) In unit-vector notation, what are (a) the electron's acceleration in that field and (b) the electron's velocity when its \(x\) coordinate has changed by \(2.0 \mathrm{~cm} ?\)

An electric dipole consisting of charges of magnitude \(1.50 \mathrm{n} \mathrm{C}\) separated by \(6.20 \mu \mathrm{m}\) is in an electric tield of strength \(1100 \mathrm{~N} / \mathrm{C} .\) What are (a) the magnitude of the electric dipole moment and (b) the difference between the potential energies for dipole orientations parallel and antiparallel to \(\vec{E} ?\)

Two charged particles are fixed to an \(x\) axis: Particle 1 of charge \(q_{1}=2.1 \times 10^{-8} \mathrm{C}\) is at position \(x=20 \mathrm{~cm}\) and particle 2 of charge \(q_{2}=-4.00 q_{1}\) is at position \(x=70 \mathrm{~cm} .\) At what coordinate on the axis (other than at infinity) is the net electric field produced by the two particles equal to zero?

Assume that a honeybee is a sphere of diameter \(1.000 \mathrm{~cm}\) with a charge of \(+45.0 \mathrm{pC}\) uniformly spread over its surface. Assume also that a spherical pollen grain of diameter \(40.0 \mu \mathrm{m}\) is electrically held on the surface of the bee because the bee's charge induces a charge of \(-1.00 \mathrm{pC}\) on the near side of the grain and a charge of \(+1.00 \mathrm{pC}\) on the far side. (a) What is the magnitude of the net electrostatic force on the grain due to the bee? Next, assume that the bee brings the grain to a distance of \(1.000 \mathrm{~mm}\) from the tip of a flower's stigma and that the tip is a particle of charge \(-45.0 \mathrm{pC}\). (b) What is the magnitude of the net electrostatic force on the grain due to the stigma? (c) Does the grain remain on the bee or does it move to the stigma?

A uniform electric field exists in a region between two oppositely charged plates. An electron is released from rest at the surface of the negatively charged plate and strikes the surface of the opposite plate, \(2.0 \mathrm{~cm}\) away, in a time \(1.5 \times 10^{-8} \mathrm{~s}\). (a) What is the speed of the electron as it strikes the second plate? (b) What is the magnitude of the electric field \(\vec{E} ?\)

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