/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 While driving a car at \(90 \mat... [FREE SOLUTION] | 91Ó°ÊÓ

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While driving a car at \(90 \mathrm{~km} / \mathrm{h}\), how far do you move while your cyes shut for \(0.50 \mathrm{~s}\) during a hard sneeze?

Short Answer

Expert verified
The car moves 12.5 meters during the sneeze.

Step by step solution

01

Convert Speed to Meters per Second

The speed is given as 90 km/h. First, we convert this to meters per second (m/s) using the conversion factor: 1 km/h = 0.27778 m/s.\[90 \text{ km/h} \times 0.27778 \text{ m/s per km/h} = 25 \text{ m/s}\]
02

Calculate Time in Seconds

The time is given as 0.50 seconds, which doesn't need conversion for further calculations.
03

Calculate Distance Traveled

Use the formula for distance, which is speed multiplied by time: \[\text{Distance} = \text{Speed} \times \text{Time} = 25 \text{ m/s} \times 0.50 \text{ s} = 12.5 \text{ meters} \]
04

Final Calculation Summary

In the time taken by a sneeze (0.50 seconds), while traveling at a speed of 25 m/s, the distance covered is 12.5 meters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Speed Conversion
Converting speeds is a crucial part of kinematics. It's like changing the language of speed so that it fits the equations we work with. When you see a speed given in kilometers per hour (km/h), it's a good practice to convert it to meters per second (m/s) when calculating distances in physical science problems.To perform this conversion, remember that:
  • 1 kilometer = 1000 meters
  • 1 hour = 3600 seconds
Therefore, to change km/h to m/s, we multiply the original speed by the factor 0.27778. This factor comes from dividing 1000 by 3600 (which simplifies the conversion process). So, converting 90 km/h to m/s involves:\[90 \text{ km/h} \times 0.27778 \text{ m/s per km/h} = 25 \text{ m/s}\]This means that if you're moving at 90 km/h, you're actually covering 25 meters every second.
Distance Calculation
Calculating distance traveled during a certain time period is at the heart of understanding movements or, more broadly, kinematics. The relationship is straightforward: distance equals speed multiplied by time. The formula is:\[\text{Distance} = \text{Speed} \times \text{Time}\]In our example, if you are traveling at 25 m/s and your eyes are shut for 0.50 seconds, then the distance you risk traveling without vision is:\[25 \text{ m/s} \times 0.50 \text{ s} = 12.5 \text{ meters}\]So, just a half-second has you moving 12.5 meters! Understanding this concept helps when you want to find out how far something moves in silence or distraction.
Time and Speed Relationship
The relationship between time and speed is fundamental in kinematics. It shows how they work together to define motion. If you increase the time you travel at a constant speed, the distance covered increases proportionally. Similarly, if speed increases while time stays constant, you cover more distance. To think about it simply:
  • A longer duration at a constant speed means traveling farther.
  • Traveling faster for the same amount of time also covers more ground.
In our sneeze example, although the time is just 0.50 seconds—a brief moment—it’s the speed of 25 m/s that dictates a relatively long distance of 12.5 meters. It illustrates how even short distractions at high speeds can influence travel significantly, an essential reminder of the dangers of taking eyes off the road while driving.

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Most popular questions from this chapter

A car moves uphill at \(40 \mathrm{~km} / \mathrm{h}\) and then back downhill at \(60 \mathrm{~km} / \mathrm{h}\). What is the average speed for the round trip?

The position of a particle as it moves along a \(y\) axis is given by $$ y=(2.0 \mathrm{~cm}) \sin (\pi t / 4) $$ with \(t\) in seconds and \(y\) in centimeters. (a) What is the average velocity of the particle between \(t=0\) and \(t=2.0 \mathrm{~s} ?\) (b) What is the instantaneous velocity of the particle at \(t=0,1.0,\) and \(2.0 \mathrm{~s} ?\) (c) What is the average acceleration of the particle between \(t=0\) and \(t=2.0 \mathrm{~s} ?\) (d) What is the instantancous acceleration of the particle at \(t=0\), \(1.0,\) and \(2.0 \mathrm{~s} ?\)

A shuffleboard disk is accelerated at a constant rate from rest to a speed of \(6.0 \mathrm{~m} / \mathrm{s}\) over a \(1.8 \mathrm{~m}\) distance by a player using a cue. At this point the disk loses contact with the cue and slows at a constant rate of \(2.5 \mathrm{~m} / \mathrm{s}^{2}\) until it stops. (a) How much time elapses from when the disk begins to accelerate until it stops? (b) What total distance does the disk travel?

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