Chapter 19: Problem 40
Two containers are at the same temperature. The first contains gas with pressure \(p_{1},\) molecular mass \(m_{1},\) and \(\mathrm{rms}\) speed \(v_{\mathrm{rms} 1}\) The second contains gas with pressure \(2.0 p_{1},\) molecular mass \(m_{2}\), and average speed \(v_{\text {avg } 2}=2.0 v_{\text {rms } 1}\). Find the mass ratio \(m_{1} / m_{2}\).
Short Answer
Step by step solution
Understand Given Information
Relate Speed and Temperature for Gas 1
Relate Speed and Temperature for Gas 2
Calculate Temperature Equality
Solve for Mass Ratio
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Root Mean Square Speed
- \( v_{\text{rms}} \) is the root mean square speed,
- \( k \) is the Boltzmann constant,
- \( T \) is the temperature in Kelvin,
- \( m \) is the molecular mass of the gas.
Molecular Mass
Boltzmann Constant
- It's a constant value: \( 1.38 \times 10^{-23} \text{ J/K} \),
- It provides a link between temperature, an observable quantity, and energy, a microscopic property.
Pressure and Temperature Relationship
- An increase in temperature means an increase in the energy and speed of molecules.
- Faster molecules impact more forcefully on the walls of the container, thus raising the pressure.