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The speeds of 10 molecules are \(2.0,3.0,4.0, \ldots, 11 \mathrm{~km} / \mathrm{s}\) What are their (a) average speed and (b) rms speed?

Short Answer

Expert verified
(a) Average speed is 6.5 km/s and (b) RMS speed is approximately 7.11 km/s.

Step by step solution

01

Identify the Given Data

The problem provides the speeds of 10 molecules as an arithmetic sequence: \(2.0, 3.0, 4.0, \ldots, 11.0\text{ km/s}\). We'll list these speeds: \(2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0, 11.0\).
02

Calculate the Average Speed

To find the average speed, we sum up all the speeds and then divide by the number of molecules. Calculate as follows:\[\text{Average speed} = \frac{2.0 + 3.0 + 4.0 + 5.0 + 6.0 + 7.0 + 8.0 + 9.0 + 10.0 + 11.0}{10}\]This simplifies to:\[\text{Average speed} = \frac{65.0}{10} = 6.5\text{ km/s}\]
03

Calculate Each Speed Squared

Square each speed to facilitate the calculation of the root mean square (RMS) speed:* \(2.0^2 = 4.0\)* \(3.0^2 = 9.0\)* \(4.0^2 = 16.0\)* \(5.0^2 = 25.0\)* \(6.0^2 = 36.0\)* \(7.0^2 = 49.0\)* \(8.0^2 = 64.0\)* \(9.0^2 = 81.0\)* \(10.0^2 = 100.0\)* \(11.0^2 = 121.0\)
04

Calculate the RMS Speed

To find the RMS speed, sum the squares of the speeds calculated in the previous step, divide by the number of speeds, and take the square root:First, compute the sum of the squares:\[4.0 + 9.0 + 16.0 + 25.0 + 36.0 + 49.0 + 64.0 + 81.0 + 100.0 + 121.0 = 505.0\]Then compute the mean of these squares:\[\frac{505.0}{10} = 50.5\]Finally, take the square root to find the RMS speed:\[\text{RMS speed} = \sqrt{50.5} \approx 7.11\text{ km/s}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Average Speed
The concept of average speed is straightforward yet essential in understanding molecular motion. When you have a collection of molecules with different speeds, the average speed helps summarize the overall pace of the entire group. Imagine these speeds as a report card for how fast molecules are moving.
Calculating average speed is simple. It is the total of all individual speeds, divided by the number of speeds. In our example, we add speeds from 2.0 to 11.0 km/s. This simple arithmetic gives us the average speed. Think of it like finding the average score in a game: add all scores together, divide by the number of players, and you get the average.
For the given molecules:
  • Sum of speeds = 65.0 km/s
  • Number of molecules = 10
Thus, the average speed is 6.5 km/s. This value gives a quick peek into how fast the molecules are moving on average, a crucial measure when studying molecular dynamics.
Root Mean Square (RMS) Speed
The Root Mean Square (RMS) speed is a bit more mathematical in nature but incredibly useful in the context of physics, especially when applying the kinetic molecular theory. RMS speed doesn't just look at the average, it considers the overall energy of moving molecules.
To find the RMS speed, each molecule's speed is squared—influencing the importance of higher speeds more significantly than lower ones. After squaring, you'll find the average of these squared values, and then finally take the square root. This series of steps makes RMS a valuable measure, particularly in scenarios where kinetic energy is crucial, as kinetic energy is proportional to the square of speed.
For our set, once each speed is squared, summed, divided by the number of speeds (10, in this case), and square-rooted, the RMS speed reveals itself:
  • Sum of squares = 505.0
  • Mean of squares = 50.5
  • Square root of mean = 7.11 km/s
Thus, the RMS speed is approximately 7.11 km/s, giving a deeper understanding of the energy profile of the molecules beyond what average speed can tell.
Molecular Speeds
Molecular speed refers to the velocity at which individual molecules travel in a gas. These speeds are not uniform but distributed over a range due to collisions and energy exchange among molecules. The tale of molecular speeds is one of diversity, not uniformity.
Understanding molecular speeds is central to the kinetic molecular theory, a theory that explains the behavior of gas particles. It tells us that even if we know the average or RMS speed, individual molecules are bustling about at various speeds, some slower, others much faster. The average and RMS speeds give us a statistical vantage point.
  • Average Speed: A fair estimation of central tendency.
  • RMS Speed: Delves into the energetic domain of molecular motion.
The diversity in molecular speeds directly impacts properties such as gas pressure and temperature. While we compute average and RMS speeds to get a handle on these fluctuations, molecular speeds remind us of the complexities underlying simple averages. They are a launchpad for exciting explorations in molecular kinetics and thermodynamics.

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Most popular questions from this chapter

A hydrogen molecule (diameter \(\left.1.0 \times 10^{-8} \mathrm{~cm}\right)\), traveling at the rms speed, escapes from a \(4000 \mathrm{~K}\) furnace into a chamber containing cold argon atoms (diameter \(3.0 \times 10^{-8} \mathrm{~cm}\) ) at a density of \(4.0 \times 10^{19}\) atoms \(/ \mathrm{cm}^{3}\). (a) What is the speed of the hydrogen molecule? (b) If it collides with an argon atom, what is the closest their centers can be, considering each as spherical? (c) What is the initial number of collisions per second experienced by the hydrogen molecule? (Hint: Assume that the argon atoms are stationary. Then the mean free path of the hydrogen molecule is given by Eq. \(19-26\) and not Eq. \(19-25 .)\)

At what frequency do molecules (diameter \(290 \mathrm{pm}\) ) collide in (an ideal) oxygen gas ( \(\mathrm{O}_{2}\) ) at temperature \(400 \mathrm{~K}\) and pressure 2.00 atm?

(a) What is the volume occupied by \(1.00 \mathrm{~mol}\) of an ideal gas at standard conditions - that is, 1.00 atm \(\left(=1.01 \times 10^{5} \mathrm{~Pa}\right)\) and \(273 \mathrm{~K} ?\) (b) Show that the number of molecules per cubic centimeter (the Loschmidt number) at standard conditions is \(2.69 \times 10^{9}\).

Two containers are at the same temperature. The gas in the first container is at pressure \(p_{1}\) and has molecules with mass \(m_{1}\) and root-mean-square speed \(v_{\text {rmsl }}\). The gas in the second is at pressure \(2 p_{1}\) and has molecules with mass \(m_{2}\) and average speed \(v_{\text {avg } 2}=2 v_{\text {rms } 1}\). Find the ratio \(m_{1} / m_{2}\) of the masses of their molecules.

A quantity of ideal gas at \(10.0^{\circ} \mathrm{C}\) and \(100 \mathrm{kPa}\) occupies a volume of \(2.50 \mathrm{~m}^{3}\). (a) How many moles of the gas are present? (b) If the pressure is now raised to \(300 \mathrm{kPa}\) and the temperature is raised to \(30.0^{\circ} \mathrm{C}\), how much volume does the gas occupy? Assume no leaks.

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