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A certain substance has a mass per mole of \(50.0 \mathrm{~g} / \mathrm{mol}\). When \(314 \mathrm{~J}\) is added as heat to a \(30.0 \mathrm{~g}\) sample, the sample's temperature rises from \(25.0^{\circ} \mathrm{C}\) to \(45.0^{\circ} \mathrm{C}\). What are the (a) specific heat and (b) molar specific heat of this substance? (c) How many moles are in the sample?

Short Answer

Expert verified
Specific heat is 0.523 J/g°C, molar specific heat is 26.15 J/mol°C, and the sample contains 0.6 mol.

Step by step solution

01

Compute Specific Heat

To find the specific heat (\(c\)), use the formula \(c = \frac{Q}{m \cdot \Delta T}\), where \(Q\) is the heat added (\(314 \mathrm{~J}\)), \(m\) is the mass (\(30.0 \mathrm{~g}\)), and \(\Delta T\) is the temperature change (\(45.0^{\circ} \mathrm{C} - 25.0^{\circ} \mathrm{C} = 20.0^{\circ} \mathrm{C}\)). Substitute these values:\[c = \frac{314 \mathrm{~J}}{30.0 \mathrm{~g} \cdot 20.0^{\circ} \mathrm{C}} = 0.523 \mathrm{~J/g^{\circ}C}\]So, the specific heat is \(0.523 \mathrm{~J/g^{\circ}C}\).
02

Compute Molar Specific Heat

Molar specific heat (\(C_m\)) is related to specific heat by the formula \(C_m = c \cdot M\), where \(M\) is the molar mass (\(50.0 \mathrm{~g/mol}\)). Using the specific heat found in Step 1 (\(0.523 \mathrm{~J/g^{\circ}C}\)) and \(M\):\[C_m = 0.523 \mathrm{~J/g^{\circ}C} \cdot 50.0 \mathrm{~g/mol} = 26.15 \mathrm{~J/mol^{\circ}C}\]Thus, the molar specific heat is \(26.15 \mathrm{~J/mol^{\circ}C}\).
03

Determine the Number of Moles

The number of moles (\(n\)) in the sample is calculated using the relation \(n = \frac{m}{M}\), where \(m\) is the mass (\(30.0 \mathrm{~g}\)) and \(M\) is the molar mass (\(50.0 \mathrm{~g/mol}\)). Substitute these values:\[n = \frac{30.0 \mathrm{~g}}{50.0 \mathrm{~g/mol}} = 0.6 \mathrm{~mol}\]Therefore, there are \(0.6 \mathrm{~mol}\) of the substance in the sample.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Specific Heat
Molar specific heat signifies the amount of heat required to raise the temperature of one mole of a substance by one degree Celsius. This concept is a step beyond specific heat, which only accounts for a mass unit of the substance. Knowing the molar specific heat is vital in chemical thermodynamics because it provides a more insightful understanding of the heat capacity in terms of moles, which is a common unit in chemistry.

Consider when we calculated the molar specific heat in the exercise: we used the specific heat, which was found to be \(0.523 \, \mathrm{J/g^{\circ}C}\), and multiplied it by the molar mass of the substance, \(50.0 \, \mathrm{g/mol}\).
  • The formula used is: \(C_m = c \cdot M\).
  • This yielded a molar specific heat of \(26.15 \, \mathrm{J/mol^{\circ}C}\).
Recognizing molar specific heat helps in understanding not just how much heat a given amount of substance absorbs, but also gives insight into the nature and behavior of substances under thermal processes.

It's crucial to understand the implications of molar specific heat since it paints a clearer picture of energy changes at the molecular level during reactions.
Chemical Thermodynamics
Chemical thermodynamics involves studying heat and temperature changes that accompany chemical reactions. It encompasses concepts like energy transfer, where the focus in our exercise was on calculating how much energy is needed to effect a change in the temperature of a sample.

In the original exercise, you learned how adding heat energy, \(314 \, \mathrm{J}\), leads to a temperature rise from \(25.0^{\circ} \mathrm{C}\) to \(45.0^{\circ} \mathrm{C}\) in a sample of \(30.0 \, \mathrm{g}\). This requires calculating the heat capacity of the sample to understand its thermal behavior.
  • Heat energy \(Q\) was factored into the equation \(c = \frac{Q}{m \cdot \Delta T}\) to find specific heat, which shows the energy required per unit mass for temperature change.
  • Thermodynamic principles tell us how efficiently substances store and transfer energy during state changes, fundamental in scientific and industrial processes.
Understanding chemical thermodynamics can help predict reaction outcomes, energy requirements, and system stability across various conditions.
Mole Concept
The mole concept might arguably be one of the most essential ideas in chemistry. The concept acts as a bridge between atomic quantities and measurable amounts used in experiments. It involves using the mole as a unit (\[1 \, \mathrm{mol} = 6.022 \times 10^{23} \, \text{particles}\] ) to simplistically express and measure large numbers of atoms, molecules, or ions.

In our exercise, calculating the number of moles in a 30-gram sample using its molar mass \(50.0 \, \mathrm{g/mol}\) was a key step.
  • The calculation of moles was done using the formula \( n = \frac{m}{M} \).
  • This translated to \(0.6 \, \mathrm{mol}\) in the sample, demonstrating the practical application of the mole concept.
Grasping the mole concept allows students to make mass-volume relationships meaningful during chemical reactions, simplify quantification of substances involved, and accurately follow stoichiometric analyses. It paves the way for deeper understanding of amounts involved in chemical formulas and reactions, essential for any chemistry study.

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Most popular questions from this chapter

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