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A sound source \(A\) and a reflecting surface \(B\) move directly toward each other. Relative to the air, the speed of source \(A\) is \(29.9 \mathrm{~m} / \mathrm{s},\) the speed of surface \(B\) is \(65.8 \mathrm{~m} / \mathrm{s},\) and the speed of sound is \(329 \mathrm{~m} / \mathrm{s}\). The source emits waves at frequency \(1200 \mathrm{~Hz}\) as measured in the source frame. In the reflector frame, what are the (a) frequency and (b) wavelength of the arriving sound waves? In the source frame, what are the (c) frequency and (d) wavelength of the sound waves reflected back to the source?

Short Answer

Expert verified
(a) 1456.9 Hz, (b) 0.225 m, (c) 1600 Hz, (d) 0.2056 m.

Step by step solution

01

Finding the Apparent Frequency Received by the Reflector (Surface B)

To find the frequency received by the moving surface B, we use the Doppler effect formula for sound waves. The formula is given by \( f' = \frac{f(v + v_o)}{v - v_s} \), where \( f \) is the original frequency emitted by the source, \( v \) is the speed of sound in air, \( v_o \) is the speed of the observer (surface B in this case, moving towards the source), and \( v_s \) is the speed of the source (A). Here, \( f = 1200 \; \text{Hz}, \; v_o = 65.8 \;\text{m/s}, \; v_s = 29.9 \;\text{m/s}, \; v = 329 \;\text{m/s}. \)Substituting these into the formula, the frequency \( f' \) is calculated as:\[f' = \frac{1200 \; (329 + 65.8)}{329 - 29.9} \approx 1456.9 \; \text{Hz}\]
02

Finding the Wavelength of Waves Arriving at Surface B

The wavelength \( \lambda' \) can be found using the relationship \( \lambda' = \frac{v_r}{f'} \), where \( v_r \) is the relative speed of wave transmission, calculated as the same speed, \( v, \) of sound through air since the medium has not changed, and \( f' \) is the frequency calculated in Step 1.\[\lambda' = \frac{329}{1456.9} \approx 0.225 \; \text{m}\]
03

Finding the Frequency of Reflected Waves in the Source Frame

The frequency of the sound reflected back to the source A can be calculated using the Doppler effect again. For the reflected waves, the observer (A) now moves towards the stationary reflector.The formula we use is: \( f'' = \frac{f'(v + v_s)}{v} \), where \( f' \) is the frequency of the arriving waves at surface B.\[f'' = \frac{1456.9 \; (329 + 29.9)}{329} \approx 1600 \; \text{Hz}\]
04

Finding the Wavelength of Reflected Waves in the Source Frame

To find the wavelength \( \lambda'' \) of the reflected waves at the source, we use the relationship between speed, frequency, and wavelength. This gives us \( \lambda'' = \frac{v}{f''} \), where \( f'' \) is the frequency calculated in Step 3.\[\lambda'' = \frac{329}{1600} \approx 0.2056 \; \text{m}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sound Waves
Sound waves are a type of longitudinal wave that travel through a medium, like air, by compressing and rarefying the medium. These waves are characterized by their frequency, wavelength, and speed.

The speed of sound in air is generally around 343 m/s at room temperature, but it was given as 329 m/s in this exercise due to specific conditions. The frequency of a sound wave refers to the number of complete vibrations or cycles per unit of time, usually measured in Hertz (Hz). Higher frequencies correspond to higher pitches, while lower frequencies correspond to lower pitches.

The wavelength is the distance between two identical points in consecutive cycles of a wave, such as crest to crest or compression to compression. Understanding these characteristics of sound waves is essential for examining behaviors like the Doppler Effect, where changes in frequency and wavelength are perceived due to relative movement between the source and the observer.
Frequency Calculation
Calculating frequency is a crucial part of understanding sound waves, especially when dealing with the Doppler Effect. The Doppler Effect describes how the frequency of waves changes for an observer moving relative to the wave source.

In the scenario described, there’s a source A emitting sound at 1200 Hz and a reflecting surface B moving towards it. To find the apparent frequency (\(f'\)) at which B receives these waves, we use the Doppler Effect equation:
  • \( f' = \frac{f(v + v_o)}{v - v_s} \)
where \(f\) is the emitted frequency, \(v\) is the speed of sound, \(v_o\) is the observer's speed (toward the source), and \(v_s\) is the source's speed.

Substituting in the values:
  • \(f = 1200 \; \text{Hz}\),
  • \(v = 329 \; \text{m/s}\),
  • \(v_o = 65.8 \; \text{m/s}\),
  • \(v_s = 29.9 \; \text{m/s}\)
we find \(f' = 1456.9 \; \text{Hz}\). This indicates a frequency increase due to the relative motion.
Wavelength Determination
The wavelength of sound waves gives us information about how far the waves travel in a single cycle. When calculating wavelengths for waves interacting with moving objects, we can use the formula:
  • \( \lambda = \frac{v}{f} \)
where \(\lambda\) represents wavelength, \(v\) is the speed of sound, and \(f\) is the wave frequency.

When the reflecting surface B receives the waves, it interprets them with a frequency of 1456.9 Hz, as derived from the Doppler formula. Thus, the wavelength \(\lambda'\) of these incident waves is:
  • \( \lambda' = \frac{329}{1456.9} \approx 0.225 \; \text{m} \)
Once the waves reflect off surface B and travel back to source A, we use the apparent frequency \(f'' = 1600 \; \text{Hz}\) calculated for that specific motion.

Using the same relationship, the wavelength \(\lambda''\) when received again by A is:
  • \( \lambda'' = \frac{329}{1600} \approx 0.2056 \; \text{m} \)
Understanding these wavelength changes helps us comprehend the interaction of sound waves with moving entities.

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Most popular questions from this chapter

Earthquakes generate sound waves inside Earth. Unlike a gas, Earth can experience both transverse (S) and longitudinal (P) sound waves. Typically, the speed of S waves is about \(4.5 \mathrm{~km} / \mathrm{s},\) and that of \(\mathrm{P}\) waves \(8.0 \mathrm{~km} / \mathrm{s} .\) A seismograph records \(\mathrm{P}\) and \(\mathrm{S}\) waves from an earthquake. The first \(\mathrm{P}\) waves arrive \(3.0 \mathrm{~min}\) before the first S waves. If the waves travel in a straight line, how far away did the earthquake occur?

A stationary detector measures the frequency of a sound source that first moves at constant velocity directly toward the detector and then (after passing the detector) directly away from it. The emitted frequency is \(f\). During the approach the detected frequency is \(f_{\text {app }}^{\prime}\) and during the recession it is \(f_{\text {rec }}^{\prime}\). If \(\left(f_{\text {app }}^{\prime}-f_{\text {rec }}^{\prime}\right) / f=0.500,\) what is the ratio \(v_{s} / v\) of the speed of the source to the speed of sound?

A tube \(1.20 \mathrm{~m}\) long is closed at one end. A stretched wire is placed near the open end. The wire is \(0.330 \mathrm{~m}\) long and has a mass of \(9.60 \mathrm{~g}\). It is fixed at both ends and oscillates in its fundamental mode. By resonance, it sets the air column in the tube into oscillation at that column's fundamental frequency. Find (a) that frequency and (b) the tension in the wire.

Find the ratios (greater to smaller) of the (a) intensities, (b) pressure amplitudes, and (c) particle displacement amplitudes for two sounds whose sound levels differ by \(37 \mathrm{~dB}\).

A state trooper chases a speeder along a straight road; both vehicles move at \(160 \mathrm{~km} / \mathrm{h}\). The siren on the trooper's vehicle produces sound at a frequency of \(500 \mathrm{~Hz}\). What is the Doppler shift in the frequency heard by the speeder?

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