/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 A sound source sends a sinusoida... [FREE SOLUTION] | 91Ó°ÊÓ

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A sound source sends a sinusoidal sound wave of angular frequency \(3000 \mathrm{rad} / \mathrm{s}\) and amplitude \(12.0 \mathrm{nm}\) through a tube of air. The internal radius of the tube is \(2.00 \mathrm{~cm} .\) (a) What is the average rate at which energy (the sum of the kinetic and potential energies) is transported to the opposite end of the tube? (b) If, simultaneously, an identical wave travels along an adjacent, identical tube, what is the total average rate at which energy is transported to the opposite ends of the two tubes by the waves? If, instead, those two waves are sent along the same tube simultaneously, what is the total average rate at which they transport energy when their phase difference is (c) \(0,\) (d) \(0.40 \pi\) rad, and (e) \(\pi\) rad?

Short Answer

Expert verified
(a) One tube: calculate power using given formula. (b) Two adjacent tubes: double the power. (c) Same tube, phase 0: four times power. (d) Phase 0.40π: use cosine rule. (e) Phase π: zero power.

Step by step solution

01

Calculate the Power Transmitted by One Wave in One Tube

To find the average power transmitted by a single sound wave, we use the formula for the average rate of energy transport:\[ P = \frac{1}{2} \rho v \omega^2 A^2 \pi r^2 \]where \( \rho \) is the density of air (approximately \(1.21 \text{ kg/m}^3\)), \( v \) is the speed of sound in air (approximately \(343 \text{ m/s}\)), \( \omega \) is the angular frequency, \( A \) is the amplitude, and \( r \) is the radius of the tube. Substituting the given values:\[ P = \frac{1}{2} \times 1.21 \times 343 \times (3000)^2 \times (12.0 \times 10^{-9})^2 \times \pi \times (0.02)^2 \]Performing the calculations, we find the average power \( P \) carried by one wave in one tube.
02

Total Power for Two Identical Waves in Adjacent Tubes

Since both tubes are identical and each carries an identical wave, the total average power for two tubes is simply double the power calculated for one tube:\[ P_{total} = 2P \]
03

Calculate Total Power for Two Waves in the Same Tube with Zero Phase Difference

When the two waves are in-phase with a phase difference \( \Delta \phi = 0 \), their amplitudes add constructively. The total amplitude becomes \( 2A \). The new power is:\[ P_{total} = \frac{1}{2} \rho v \omega^2 (2A)^2 \pi r^2 = 4P \]
04

Calculate Total Power for Two Waves in the Same Tube with 0.40Ï€ Phase Difference

With a phase difference \( \Delta \phi = 0.40 \pi \), the amplitudes do not add completely. The resultant amplitude \( A_{res} \) is:\[ A_{res} = 2A \cos(0.20 \pi) \]Thus, the power becomes:\[ P_{total} = \frac{1}{2} \rho v \omega^2 A_{res}^2 \pi r^2 \]
05

Calculate Total Power for Two Waves in the Same Tube with π Phase Difference

For a phase difference of \( \Delta \phi = \pi \), the waves interfere destructively and cancel each other out completely (in theory if perfectly matched), resulting in zero net amplitude and thus zero power:\[ A_{res} = 0 \] \ \[ P_{total} = 0 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sinusoidal Wave
A sinusoidal wave is a smooth, periodic oscillation that can describe various phenomena, such as sound waves or electromagnetic waves. In the case of sound waves, a sinusoidal wave represents the pressure oscillation that travels through a medium, like air, carrying energy from one place to another. This wave can be visualized as a perfect, continuous curve that repeats in time and space.

The key features of a sinusoidal wave include:
  • Amplitude: The maximum displacement of the wave from its equilibrium position. For sound waves, this correlates to the loudness.
  • Wavelength: The distance between consecutive points in phase, such as from crest to crest.
  • Frequency: The number of oscillations per second, measured in Hertz (Hz).
Understanding these features helps in analyzing how sound waves propagate and how their energies can be calculated in different scenarios.
Angular Frequency
Angular frequency, denoted by the symbol \( \omega \), is a measure of how quickly a wave oscillates in terms of radians per second. It complements the standard frequency (\( f \)), which counts cycles per second. The relationship between angular frequency and frequency is given by: \[ \omega = 2\pi f \]where \( \pi \) is approximately 3.14159. This equation shows that angular frequency is just the regular frequency multiplied by the factor \( 2\pi \), as a full cycle around a circle is 2\(\pi\) radians.

In sound waves, a higher angular frequency means more rapid oscillations, which often correspond to higher-pitched sounds. For example, in the problem provided, an angular frequency of \(3000\text{ rad/s}\) would indicate a very high-pitched wave traveling through the air.

Angular frequency is crucial for calculating the wave's energy transport, as it contributes to the wave's kinetic and potential energy components. This is useful when determining how much energy a wave carries as it moves through a medium.
Phase Difference
Phase difference refers to the difference in phase between two waves at a specific point in time. It is often denoted by \( \Delta \phi \) and measured in radians. Phase difference is a critical concept because it influences whether waves will constructively or destructively interfere with one another.

Key points about phase difference include:
  • Zero Phase Difference (In-phase): Waves add their amplitudes constructively, resulting in a larger amplitude.
  • Half-Period Phase Difference (\(\pi\) radians): Waves cancel each other completely, resulting in zero amplitude, often termed destructive interference.
  • Partial Phase Difference: Varying degrees lead to different resultant amplitudes, as seen in the problem with a \(0.40\pi\) phase difference.
Understanding phase difference allows one to predict how overlapping waves will interact, which is essential for tasks like calculating the total energy transported by waves in a shared medium.
Wave Interference
Wave interference occurs when two or more waves meet while traveling along the same medium. The principle of superposition states that the resulting wave is the sum of the displacements of the individual waves at each point in time.

Types of wave interference:
  • Constructive Interference: Occurs when waves meet in phase (phase difference of 0), enhancing each other's amplitudes.
  • Destructive Interference: Occurs when waves meet out of phase (phase difference of \(\pi\)), decreasing the overall amplitude or canceling it out completely.
In sound wave scenarios, wave interference plays a crucial role in determining the net energy carried by waves. For example, if two waves with identical properties but opposite phases travel through the same medium, they can completely cancel each other out, resulting in no net energy transfer. Understanding interference helps in predicting how waves will behave when they overlap, which is necessary to solve problems involving energy transport through wave media.

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Most popular questions from this chapter

The speed of sound in a certain metal is \(v_{m}\). One end of a long pipe of that metal of length \(L\) is struck a hard blow. A listener at the other end hears two sounds, one from the wave that travels along the pipe's metal wall and the other from the wave that travels through the air inside the pipe. (a) If \(v\) is the speed of sound in air, what is the time interval \(\Delta t\) between the arrivals of the two sounds at the listener's ear? (b) If \(\Delta t=1.00 \mathrm{~s}\) and the metal is steel, what is the length \(L ?\)

A point source emits sound waves isotropically. The intensity of the waves \(2.50 \mathrm{~m}\) from the source is \(1.91 \times 10^{-4} \mathrm{~W} / \mathrm{m}^{2}\). Assuming that the energy of the waves is conserved, find the power of the source.

The source of a sound wave has a power of \(1.00 \mu \mathrm{W}\). If it is a point source, (a) what is the intensity \(3.00 \mathrm{~m}\) away and (b) what is the sound level in decibels at that distance?

Pipe \(A,\) which is \(1.20 \mathrm{~m}\) long and open at both ends, oscillates at its third lowest harmonic frequency. It is filled with air for which the speed of sound is \(343 \mathrm{~m} / \mathrm{s}\). Pipe \(B,\) which is closed at one end, oscillates at its second lowest harmonic frequency. This frequency of \(B\) happens to match the frequency of \(A .\) An \(x\) axis extends along the interior of \(B,\) with \(x=0\) at the closed end. (a) How many nodes are along that axis? What are the (b) smallest and (c) second smallest value of \(x\) locating those nodes? (d) What is the fundamental frequency of \(B ?\)

The sound intensity is \(0.0080 \mathrm{~W} / \mathrm{m}^{2}\) at a distance of \(10 \mathrm{~m}\) from an isotropic point source of sound. (a) What is the power of the source? (b) What is the sound intensity \(5.0 \mathrm{~m}\) from the source? (c) What is the sound level \(10 \mathrm{~m}\) from the source?

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