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A string under tension \(\tau_{i}\) oscillates in the third harmonic at frequency \(f_{3}\), and the waves on the string have wavelength \(\lambda_{3}\). If the tension is increased to \(\tau_{f}=4 \tau_{i}\) and the string is again made to oscillate in the third harmonic, what then are (a) the frequency of oscillation in terms of \(f_{3}\) and \((b)\) the wavelength of the waves in terms of \(\lambda_{3} ?\)

Short Answer

Expert verified
(a) The new frequency is \( 2f_3 \). (b) The new wavelength is \( \lambda_3 \).

Step by step solution

01

Understand the relationship between tension, frequency, and wavelength

For a string under tension, the wave speed \( v \) is given by \( v = \sqrt{\frac{\tau}{\mu}} \) where \( \tau \) is the tension and \( \mu \) is the linear mass density of the string. The frequency \( f \) and wavelength \( \lambda \) are related to the wave speed by the equation \( v = f \lambda \).
02

Analyze initial conditions

Initially, the string is oscillating in the third harmonic with tension \( \tau_i \), frequency \( f_3 \), and wavelength \( \lambda_3 \). For the third harmonic, the wavelength is \( \lambda_3 = \frac{2L}{3} \), where \( L \) is the length of the string.
03

Increase tension and find new wave speed

When the tension is increased to \( \tau_f = 4\tau_i \), the new wave speed \( v_f \) on the string becomes \( v_f = \sqrt{\frac{4\tau_i}{\mu}} = 2\sqrt{\frac{\tau_i}{\mu}} = 2v_i \), where \( v_i \) is the initial wave speed.
04

Calculate the new frequency

The frequency of oscillation is given by \( f = \frac{v}{\lambda} \). Since the tension increases, the wave speed doubles. The frequency of oscillation in the third harmonic remains linked to \( L \) and does not change with wavelength. Therefore, the new frequency is \( f'_3 = 2f_3 \) as the wave speed doubled.
05

Determine the new wavelength

For the same harmonic (third harmonic) and with a tension change, the wavelength linked to the wave speed is unchanged for the harmonic itself. Therefore, the wavelength \( \lambda_3 \) as a physical length doesn't change when expressed in terms of \( L \) because it still fulfills the condition \( \lambda_3 = \frac{2L}{3} \). Hence, the new wavelength remains \( \lambda_3' = \lambda_3 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

String Tension and Its Impact on Wave Mechanics
The tension in a string has a significant impact on the behavior of waves traveling through it. When a string is under tension, waves can move along it, and the properties of these waves, such as speed and frequency, are directly influenced by the level of tension. The relationship between tension and wave speed is described mathematically by the formula: \[ v = \sqrt{\frac{\tau}{\mu}} \] where:
  • \( v \) is the wave speed,
  • \( \tau \) is the tension in the string, and
  • \( \mu \) is the linear mass density (mass per unit length) of the string.
An increase in tension results in an increase in wave speed. This is because more tension pulls the string tighter, allowing vibrations to travel faster. In our given problem, when the tension is increased fourfold, the wave speed doubles, significantly affecting the frequency but not the wavelength in this harmonic situation.
Understanding Harmonics on a Vibrating String
In the realm of wave mechanics, harmonics refer to specific frequencies at which a string vibrates along with standing waves. Generally, the first harmonic is the fundamental frequency, and other harmonics are multiples of this frequency. For a string of length \( L \), vibrated at harmonic frequencies, the standing waves establish nodes and antinodes along the string. For the third harmonic (as in our exercise), the wavelength \( \lambda_3 \) is determined by the equation:\[ \lambda_3 = \frac{2L}{3} \]This means three "loops" or parts of a wave fit within the string's length, establishing a pattern of nodes where the string doesn’t move. Although the tension in the string changes, the number of nodes and loops must remain constant for a particular harmonic, keeping the relative wavelength linked to \( L \) unchanged.
What Affects Wave Speed on a String?
Wave speed is one of the fundamental aspects of wave behavior and is influenced by the tension in the string as well as its mass density. As previously noted, wave speed \( v \) is proportional to the square root of the tension. Therefore, by increasing the tension, the square root yields a proportional increase in wave speed.When applied to our problem, the initial wave speed \( v_i \) doubles with a quadrupling of tension due to the following derivation:\[ v_f = \sqrt{\frac{4\tau_i}{\mu}} = 2\sqrt{\frac{\tau_i}{\mu}} = 2v_i \]Thus, this doubling of wave speed directly influences the frequency, demonstrating how principles of physics elegantly interrelate tension and wave characteristics.
Frequency and Wavelength Relationship in String Waves
The frequency and wavelength of a wave are intricately linked to wave speed through the relation:\[ v = f \lambda \]where:
  • \( v \) is the wave speed,
  • \( f \) is the frequency, and
  • \( \lambda \) is the wavelength.
In our scenario, the tension's increase doubles the wave speed, which, in turn, doubles the frequency of the third harmonic, giving rise to a new frequency \( f'_3 = 2f_3 \). However, the wavelength remains the same for the third harmonic as the number of wave segments fitting into the length of the string does not change. This constancy in wavelength amidst changes in frequency underscores the independence of wavelength for specific harmonics, ensuring consistency in wave patterns across different tensions.

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Most popular questions from this chapter

The equation of a transverse wave traveling along a string is $$ y=(2.0 \mathrm{~mm}) \sin \left[\left(20 \mathrm{~m}^{-1}\right) x-\left(600 \mathrm{~s}^{-1}\right) t\right] $$ Find the (a) amplitude, (b) frequency, (c) velocity (including sign), and (d) wavelength of the wave. (e) Find the maximum transverse speed of a particle in the string.

A transverse sinusoidal wave is generated at one end of a long, horizontal string by a bar that moves up and down through a distance of \(1.00 \mathrm{~cm}\). The motion is continuous and is repeated regularly 120 times per second. The string has linear density \(120 \mathrm{~g} / \mathrm{m}\) and is kept under a tension of \(90.0 \mathrm{~N}\). Find the maximum value of (a) the transverse speed \(u\) and (b) the transverse component of the tension \(\tau\). (c) Show that the two maximum values calculated above occur at the same phase values for the wave. What is the transverse displacement \(y\) of the string at these phases? (d) What is the maximum rate of energy transfer along the string? (e) What is the transverse displacement \(y\) when this maximum transfer occurs? (f) What is the minimum rate of energy transfer along the string? (g) What is the transverse displacement \(y\) when this minimum transfer occurs?

A sinusoidal wave is traveling on a string with speed \(40 \mathrm{~cm} / \mathrm{s}\). The displacement of the particles of the string at \(x=10 \mathrm{~cm}\) varies with time according to \(y=(5.0 \mathrm{~cm}) \sin \left[1.0-\left(4.0 \mathrm{~s}^{-1}\right) t\right] .\) The linear density of the string is \(4.0 \mathrm{~g} / \mathrm{cm}\). What are (a) the frequency and (b) the wavelength of the wave? If the wave equation is of the form \(y(x, t)=\) \(y_{m} \sin (k x \pm \omega t),\) what are \((c) y_{m},(\mathrm{~d}) k\) (c) \(\omega,\) and (f) the correct choice of sign in front of \(\omega ?(g)\) What is the tension in the string?

Consider a loop in the standing wave created by two waves (amplitude \(5.00 \mathrm{~mm}\) and frequency \(120 \mathrm{~Hz}\) ) traveling in opposite directions along a string with length \(2.25 \mathrm{~m}\) and mass \(125 \mathrm{~g}\) and under tension \(40 \mathrm{~N}\). At what rate does energy enter the loop from (a) each side and (b) both sides? (c) What is the maximum kinetic energy of the string in the loop during its oscillation?

Two sinusoidal waves with identical wavelengths and amplitudes travel in opposite directions along a string with a speed of \(10 \mathrm{~cm} / \mathrm{s}\). If the time interval between instants when the string is flat is \(0.50 \mathrm{~s}\), what is the wavelength of the waves?

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